while running application got this error I am using MySQL 8 version and also here get dialect version 8 but its not working
I want to connect database and store my value which, I have passed
package com.practice;
import org.springframework.boot.SpringApplication;
import org.springframework.boot.autoconfigure.SpringBootApplication;
import org.springframework.context.ApplicationContext;
import com.practice.dao.UserRepository;
import com.practice.entities.User;
#SpringBootApplication
public class DemoApplication {
public static void main(String[] args) {
ApplicationContext context = SpringApplication.run(DemoApplication.class, args);
UserRepository userRepository =context.getBean(UserRepository.class);
User user = new User();
user.setName("shrikant suryawanshi");
user.setCity("Pune");
user.setStatus("active");
User user1 = userR
Repository.save(user);
System.out.println(user1);`
}
}
Error:
Error creating bean with name 'entityManagerFactory' defined in class path resource [org/springframework/boot/autoconfigure/orm/jpa/HibernateJpaConfiguration.class]: Entity 'com.practice.entities.User' has no identifier (every '#Entity' class must declare or inherit at least one '#Id' or '#EmbeddedId' property)
Every entity (table in you DB) must be declared with #Entity anotation, and every Entity must have unique identifier anotated with #Id anotation, https://www.baeldung.com/jpa-entities . If error continues after fixing Entity classes add them to your question
I got the same error and it turned out that I had the incorrect import for #Id. The correct import is
import jakarta.persistence.Id
Related
We are currently on a Spring Boot Version 1.x
We have Error Messages (Error Key -> Error Code) pairs in our error.properties file (this is in the class path).
We leveraged PropertiesConfigurationFactory to get these Error Key and Error Code pairs in to a POJO, this POJO had a Map
Hence very convenient to be used across our application to get an Error code for a given Error Key.
What is its equivalent in Spring Boot 2.x ?.
Assuming you have error.properties file with the below contents:
errors.error1=101
errors.error2=102
errors.error3=103
A simple spring boot app that demonstrates the injection of these properties :
package snmaddula.remittance;
import java.util.Map;
import org.springframework.boot.CommandLineRunner;
import org.springframework.boot.SpringApplication;
import org.springframework.boot.autoconfigure.SpringBootApplication;
import org.springframework.boot.context.properties.ConfigurationProperties;
import org.springframework.context.annotation.Bean;
import org.springframework.context.annotation.PropertySource;
#SpringBootApplication
#ConfigurationProperties
#PropertySource("classpath:error.properties")
public class DemoApplication {
private Map<String, Integer> errors;
public static void main(String[] args) {
SpringApplication.run(DemoApplication.class, args);
}
#Bean
public CommandLineRunner cli() {
return (args) -> {
System.out.println(errors); // you can print and see the error properties injected to this map.
};
}
public void setErrors(Map<String, Integer> errors) {
this.errors = errors;
}
}
With the use of #PropertySource and #ConfigurationProperties we can enable property injection provided we have a setter method for our attribute.
When you run this program, you can see the properties getting printed on to the console as I added a CommandLineRunner cli() {..} to show the working of it.
The working sample is available on GitHub.
I am trying to use Spring data and repositories in a Spring Boot application, but I have an error when compiling the project.
Here is my Entity :
package fr.investstore.model;
import javax.persistence.Id;
...
#Entity
public class CrowdOperation {
#Id
#GeneratedValue(strategy=GenerationType.IDENTITY)
public Long id;
#Enumerated(EnumType.STRING)
public RepaymentType repaymentType;
...
}
And the corresponding Repository:
package fr.investstore.repositories;
import org.springframework.data.repository.CrudRepository;
import org.springframework.data.repository.PagingAndSortingRepository;
import org.springframework.stereotype.Repository;
import fr.investstore.model.CrowdOperation;
public interface CrowdOperationRepository extends CrudRepository<CrowdOperation, Long> {
}
I use it in a WS controller, generating a repository through the Autowired annotation:
package fr.investstore.ws;
import org.springframework.beans.factory.annotation.Autowired;
import org.springframework.boot.autoconfigure.EnableAutoConfiguration;
import org.springframework.stereotype.Controller;
import org.springframework.web.bind.annotation.ResponseBody;
import org.springframework.web.bind.annotation.RequestMethod;
import org.springframework.web.bind.annotation.RequestParam;
import org.springframework.web.bind.annotation.RequestMapping;
...
#Controller
#EnableAutoConfiguration
public class SampleController {
#Autowired
private CrowdOperationRepository crowdOperationRepository;
#RequestMapping(path = "/", method = RequestMethod.GET)
#ResponseBody
public String getOperations(#RequestParam(required=true, defaultValue="Stranger") String name) {
crowdOperationRepository.save(new CrowdOperation());
return "Hello " + name;
}
}
And the code of the application:
package fr.investstore;
import org.springframework.boot.SpringApplication;
import org.springframework.boot.autoconfigure.SpringBootApplication;
import fr.investstore.ws.SampleController;
#SpringBootApplication
public class InvestStoreApplication {
public static void main(String[] args) {
SpringApplication.run(SampleController.class, args);
}
}
But when compiling the project I get:
APPLICATION FAILED TO START
Description: Field crowdOperationRepository in
fr.investstore.ws.SampleController required a bean of type
'fr.investstore.repositories.CrowdOperationRepository' that could not
be found.
Action: Consider defining a bean of type
'fr.investstore.repositories.CrowdOperationRepository' in your
configuration.
Woudn't Spring automatically generate a bean for the repository through the interface?
How can I resolve this?
EDIT: I also tried to put the Repository annotation (from org.springframework.stereotype.Repository) onto CrowdOperationRepository, but I got the same error
While creating a spring-boot application, we need to keep some point in our mind like
Always keep main class (class with `#SpringBootApplication annotation) on the top level package and other classes should lie under sub-packages.
Always mark your bean classes with proper annotation e.g. all repositories should be marked by #Repository annotation, all service implementation classes should be marked with #Service, other component classes should be marked by #Component, class which defines our beans should be marked as #Configuration
Enable the feature which you are using e.g. #EnableJpaRepositories, #EnableTransactionManagement, #EnableJpaAuditing, these annotations also provides functionality which let us define which package spring needs to scan.
So in your case, you need to mark InvestStoreApplication class with #EnableJpaRepositories annotation and CrowdOperationRepository with #Repository.
you have to tell your spring boot application to load JPA repositories.
copy this one to your application class
it will auto-scan your JPA repository and load it in your spring container even if you do not define your interface with #Repository it will wire that bean in your dependent class.
#EnableJpaRepositories(basePackages = { "fr.investstore.repositories" })
Thank to #JBNizet for his comment, that made it working.
I create this answer since he did not:
Replace SpringApplication.run(SampleController.class, args); with SpringApplication.run(InvestStoreApplication.class, args);. And remove the useless #EnableAutoConfiguration on your controller.
Annotating your entity class as shown as spring hint below to allow spring get a valid repository bean
Spring Data JPA - Could not safely identify store assignment for repository candidate interface com.xxxxx.xxxxRepository.
If you want this repository to be a JPA repository, consider annotating your entities with one of these annotations: javax.persistence.Entity, javax.persistence.MappedSuperclass (preferred),
or consider extending one of the following types with your repository: org.springframework.data.jpa.repository.JpaRepository.
2022-05-06 12:32:12.623 [ restartedMain] INFO [.RepositoryConfigurationDelegate:201 ] - Finished Spring Data repository scanning in 3 ms. Found 0 JPA repository interfaces.
I am learning the Spring-Boot(I am new to it), reading the Spring Boot Document. In the 23.6 Accessing application arguments, It talk about the ApplicationArguments, and the code is:
package com.example.project;
import org.springframework.boot.*;
import org.springframework.beans.factory.annotation.*;
import org.springframework.stereotype.*;
import java.util.*;
#Component
public class MyBean {
#Autowired
public MyBean(ApplicationArguments args) {
boolean debug = args.containsOption("debug");
List<String> files = args.getNonOptionArgs();
System.out.println(debug);
System.out.println(files);
}
}
It says if run with "--debug logfile.txt" debug=true, files=["logfile.txt"].
But in my project, I don't know how to run it. I create the spring-boot using Maven: The Project Structure
In Spring Boot doc ApplicationArguments is autowired in a bean. Here is a more hands on example where it's used in a Main method.
import org.springframework.boot.ApplicationArguments;
import org.springframework.boot.ApplicationRunner;
import org.springframework.boot.SpringApplication;
import org.springframework.boot.autoconfigure.SpringBootApplication;
#SpringBootApplication
public class Application implements ApplicationRunner {
public static void main(String[] args) {
SpringApplication.run(Application.class, args).stop();
}
#Override
public void run(ApplicationArguments args) throws Exception {
boolean debug = args.containsOption("debug");
List<String> files = args.getNonOptionArgs();
System.out.println(debug);
System.out.println(files);
}
}
Assuming that you have an Application class with annotation #SpringBootApplication like in the answer provided by a.b.d.
To be able to provide the arguments within IntelliJ IDEA environment you will need to first Run the main method and then Edit 'Run/Debug Configurations' and under Main Class fill Program arguments field with "--debug logfile.txt":
In one word like a thousand :
the 'Program arguments' in your IDE field prefixed by -- is simply the same name as the 'Option' expected in the 'ApplicationArguments'.
Hence you can match --debug and "args.containsOption("debug")".
My project used spring-boot (1.4.0.release) and mybatis-spring-boot-starter. When I try to have some test code for controller, I always get a exception
Caused by: java.lang.IllegalArgumentException: Property 'sqlSessionFactory' or 'sqlSessionTemplate' are required
at org.springframework.util.Assert.notNull(Assert.java:115)
at org.mybatis.spring.support.SqlSessionDaoSupport.checkDaoConfig(SqlSessionDaoSupport.java:75)
at org.mybatis.spring.mapper.MapperFactoryBean.checkDaoConfig(MapperFactoryBean.java:74)
at org.springframework.dao.support.DaoSupport.afterPropertiesSet(DaoSupport.java:44)
at org.springframework.beans.factory.support.AbstractAutowireCapableBeanFactory.invokeInitMethods(AbstractAutowireCapableBeanFactory.java:1637)
at org.springframework.beans.factory.support.AbstractAutowireCapableBeanFactory.initializeBean(AbstractAutowireCapableBeanFactory.java:1574)
... 42 more`
But when I comment #MapperScan("com.toby.mapper"), it runs very well.
Here is my example class:
#MapperScan("com.toby.mapper")
#EnableTransactionManagement
#EnableConfigurationProperties(AppConfig.class)
#SpringBootApplication(scanBasePackages = "com.toby.configuration,com.toby.web.controller,com.toby.service,com.toby.dao")
public class Example {
public static void main(String[] args) throws Exception {
//new SpringApplicationBuilder().sources(Example.class).run(args);
SpringApplication application=new SpringApplication(Example.class);
application.addInitializers(new PropertyPasswordDecodingContextInitializer());
application.run(args);
}
}
Here is my test code:
package com.toby.web.controller;
import com.toby.common.config.AppConfig;
import org.junit.Test;
import org.junit.runner.RunWith;
import org.springframework.beans.factory.annotation.Autowired;
import org.springframework.boot.test.autoconfigure.web.servlet.WebMvcTest;
import org.springframework.boot.test.mock.mockito.MockBean;
import org.springframework.test.context.junit4.SpringRunner;
import org.springframework.test.web.servlet.MockMvc;
/**
* Created by Toby on 2016/8/10.
*/
#RunWith(SpringRunner.class)
#WebMvcTest(value = MyRestController.class)
public class MyRestControllerTests {
#Autowired
private MockMvc mvc;
#MockBean
private AppConfig appConfig;
#Test
public void testHome() throws Exception {
/*this.mvc.perform(get("/users").accept(MediaType.TEXT_PLAIN))
.andExpect(status().isOk()).andExpect(content().string("Honda Civic"));*/
}
}
I guess you've updated the description or I didn't read it properly the first time. #MapperScan is a mybatis specific annotation that triggers something but is missing some guard of some sort.
We had the same problem in boot actually. Let's say you put #EnableCaching on your main app. Because slicing disables all auto-configurations but a list of specific ones, the cache auto-configuration would not kick in and you'll get an exception because the CacheManager isn't found. To fix that issue, we've started to create some annotation to easily enable those. If you look at WebMbcTest you'll see it's annotated with AutoConfigureCache that's going to provide a dummy no-op cache manager unless specified otherwise.
Your problem is that the mybatis support is a third party integration and there isn't any support for that. Some solutions:
Change #WebMbvcTest to provide the class of another configuration class, effectivly disabling the use of your main spring boot app. Of course that class shouldn't define the #MapperScan annotation
Move the MapperScan (and anything that's not required with slicing) to another Configuration class. It could be a class in the same package as your app. Slicing won't scan those by default so you'll be fine. It's by far the easiest
Create an issue in the mybatis support so that they improve the auto-configuration to back-off (prevent this exception). I am not sure that's possible actually
Long story short, since #MapperScan is a way to tell mybatis to scan your entities, maybe you shouldn't add it on your main boot app if you use slicing. Because your #WebMbcTest doesn't want to use that obviously.
Can anyone help me with a Spring Boot problem?
I want to create a factory bean as part of my application context but I want to be able to instantiate it with injected property values. However it seems that Spring will load FactoryBeans before anything else as demonstrated here:
import java.util.ArrayList;
import java.util.List;
import org.springframework.beans.factory.annotation.Value;
import org.springframework.beans.factory.config.AbstractFactoryBean;
import org.springframework.beans.factory.config.ListFactoryBean;
import org.springframework.boot.SpringApplication;
import org.springframework.boot.autoconfigure.EnableAutoConfiguration;
import org.springframework.context.annotation.Bean;
#EnableAutoConfiguration
public class TestClass
{
#Value("${test.value}")
String value;
#Bean
public Object test1()
{
System.out.println("test.value=" + value );
List<String> list = new ArrayList<String>();
ListFactoryBean factory = new ListFactoryBean();
factory.setSourceList(list);
return factory;
}
public static void main(String[] args)
{
SpringApplication.run(TestClass.class, args);
}
}
When run with
java -Dtest.value=HELLO -jar myTest.jar
It loads in the value correctly:
test.value=HELLO
However, when I specify that the bean to be loaded is in fact a factory bean, and run it in the same way:
import java.util.ArrayList;
import java.util.List;
import org.springframework.beans.factory.annotation.Value;
import org.springframework.beans.factory.config.AbstractFactoryBean;
import org.springframework.beans.factory.config.ListFactoryBean;
import org.springframework.boot.SpringApplication;
import org.springframework.boot.autoconfigure.EnableAutoConfiguration;
import org.springframework.context.annotation.Bean;
#EnableAutoConfiguration
public class TestClass
{
#Value("${test.value}")
String value;
#Bean
public AbstractFactoryBean test1()
{
System.out.println("test.value=" + value );
List<String> list = new ArrayList<String>();
ListFactoryBean factory = new ListFactoryBean();
factory.setSourceList(list);
return factory;
}
public static void main(String[] args)
{
SpringApplication.run(TestClass.class, args);
}
}
The value is null because it hasn't been injected yet.
test.value=null
Is there any way around this?
Thanks
Spring often has to query bean definitions for the type of object they produce. Factory beans are always problematic because they can cause dependency cascades in a futile attempt to resolve all dynamic information available before asking for the type.
I think ListFactoryBean is insufficiently precise about its product type (getObjectType() can only return a non-generic List.class). You might be able to write your own factory that is parameterized with the correct generic type. Or you might get away with just declaring the #Bean to return a FactoryBean<List<String>.
Another tip is to move the #Bean definition to a separate class (e.g. a nested static one) so that it can be instantiated independently of the rest of the application context. E.g.
#EnableAutoConfiguration
public class TestClass
{
protected static class NestedConfiguration {
#Value("${test.value}")
String value;
#Bean
public FactoryBean<Properties> test1()
{
System.out.println("test.value=" + value );
// ...
return factory;
}
}
...
}
Not really a Boot question this one so you might consider changing the tags.
Take look at Empowering your apps with Spring Boot's property support
There is new annotation #EnableConfigurationProperties in Spring Boot Actuator
The Spring Environment is a collection of name-value pairs taken from (in order of decreasing precedence)
1) the command line,
2) the external configuration file,
3) System properties,
4) the OS environment.
There is also possible to define application properties (external configuration) in YAML format.