Check if a variable is a color SCSS [duplicate] - sass

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Sass - Check which kind of value a variable has
(2 answers)
Closed 2 years ago.
I would like to know if a variable is a valid color in a SASS function.
This is the first code I wrote, so I check if the variable is initialised.
#function get-valid-color($color) {
#if variable-exists($color) {
#return $color;
} #else {
#return inherit;
}
}
I would like to understand also if the variable is a valid color or not. Only in that case I would return the variable, otherwise I would return inherit.
This the expected output:
$primary-text = red;
$primary-bg = #000000;
$border-width = 4px;
color: get-color($border-width); // color: inherit;
background-color: get-color($primary-bg); // background-color: #000000;
color: get-color($primary-text); // color: red;
color: get-color($fake-variable); // color: inherit
Ideas, thanks.

There is a built-in method in SASS (type-of()) that might help to check if the current existing color is actually is a color or not, so you can check it like this:
#function get-valid-color($color) {
#if type-of($color) != color {
#return inherit;
} #else {
#return $color;
}
}

Related

Sass manipulate with #content

Is it possible to manipulate with #content magic variable in SASS?
I would like to replace some stuff in here before output.
Or maybe can I fill some variable with it?
The conclusion is that, I want to make an mixin #important that create both versions. Important, and no-important.
Input
.test {
#include important {
color: red;
text-align: left;
}
}
Expected output
.test {
color: red;
text-align: left;
}
.test-i {
color: red !important;
text-align: left !important;
}
No, you can't. But I quickly wrote you a mixin to make it work. It doesn't accepts multiple properties (yet).
First Note: I changed the mixin it now does accept multiple properties. Here is the Codepen.
Second Note: I updated the mixin adding multiple properties does no longer compile to different classes for each property, instead you get two versions, one without the !important suffix and one with.
This is the mixin:
#function return($state) {
#return if($state == '', '', '-i');
}
#mixin loop($name, $items...) {
#each $item in $items / 2 {
#each $state in ('', '!important') {
$suffix: return($state);
.#{$name}#{$suffix} {
#for $i from 1 through (length($items) / 2) {
#{nth($items, ($i * 2) - 1)}: #{nth($items, ($i * 2))} #{$state};
}
}
}
}
}
This is how you include it:
// #include loop([classname], [property], [value]);
#include loop(whateverClassname, color, red);
This is what it compiles to:
.whateverClassname {
color: red ;
}
.whateverClassname-i {
color: red !important;
}
This is what it now compiles to, when you use multiple properties at once:
#include loop(whateverClassname, color, red, background-color, green, display, flex);
.whateverClassname {
color: red ;
background-color: green ;
display: flex ;
}
.whateverClassname-i {
color: red !important;
background-color: green !important;
display: flex !important;
}
Conclusion: it works as expected and does no longer bloat your CSS.
Hope I could help you at least a little ;-)

Using a sass variable in an #each loop

I'm trying to create a little overview for all the colors we use in our corporate identity. All our colors have been defined in _settings-colors.scss, and the only reason I need this bit of css is for the library, where the colors need to be listed.
What I have now is as follows:
$colors-brand: color-brand, color-brand-40, color-brand-60, color-brand-70;
.prfx-color {
display: block;
height: 5rem;
width: 100%;
#each $color in $colors-brand {
&--#{$color} {
background-color: #{'$'+$color};
&::after {
content: '$'+$color;
}
}
}
}
These color-brand variables are set in another file which I'm including in this scss file.
The code above outputs this:
.prfx-color {
display: block;
height: 5rem;
width: 100%;
}
.prfx-color--color-brand {
background: $color-brand;
}
.prfx-color--color-brand::after {
content: "$color-brand";
} [...etc]
What I'm after however, is this:
.prfx-color--color-brand {
background: #00ff11; // don't worry, brand is not actually this color
}
The problem I'm having is that the $color-brand variable isn't interpreted as a sass variable anymore, but is a literal value. I need the #hheexx that this variable refers to!
All the solutions I've found so far consist of using two lists, or a key-value pair. In my situation these variables have already been set once, and I want a solution where I don't want to have to manually edit the library if the colors change.
Is this at all possibe, or am I too greedy here?
And I realized I overcomplicated it. You don't need any extra functions because the #each is designed to work with maps and iterating over multiple values.
$cool: blue;
$mad: red;
$colors: (
cool: $cool,
mad: $mad
);
.prfx-color {
#each $key, $val in $colors {
&--#{$key} {
background-color: $val;
&::after { content: "$#{$key}"; }
}
}
}
You could use a map.
Here's a sassmeister playground for you.
$cool: blue;
$mad: red;
$colors: (
cool: $cool,
mad: $mad
);
.prfx-color {
#each $color in map-keys($colors) {
&--#{$color} {
background-color: map-get($colors, $color);
&::after { content: "$#{$color}"; }
}
}
}

SASS: create name that is unique per-mixin?

I'm creating a mixin called static() that is used inside another mixin to separate the static properties out into placeholders, so that those properties aren't repeated in the output every time a mixin is used. Here's how you would use it in a mixin called button(), for example:
#mixin button($color) {
#include static('button') {
border: 1px solid;
border-radius: 5px;
padding: .25em .5em;
&:hover {
cursor: pointer;
}
}
background-color: $color;
&:hover {
background-color: mix(black, $color, 15%;
}
}
Here's the code for the static() mixin:
#mixin static($mixin-name, $extend: true) {
// set global $Placeholder-Selectors if it doesn't already exist
$Placeholder-Selectors: () !global !default;
$selector: map-get($Placeholder-Selectors, $mixin-name);
#if $extend == true {
#if $selector == null {
$selector: unique-id();
$Placeholder-Selectors: map-merge($Placeholder-Selectors, ($mixin-name: $selector)) !global;
#at-root %#{$selector} {
#include static($mixin-name, false) {
#content;
};
}
}
#extend %#{$selector};
} #else {
#content;
}
}
The only purpose of the variable $mixin-name is to make sure the declarations of the created placeholder are not overwritten by another placeholder of the same name. My assumption is that the best way to ensure this is to use the name of the mixin itself for the $Placeholder-Selectors' key (since this will be unique to the mixin).
Question:
If that assumption is correct, I don't want to have to type out the name of the mixin I'm using (as in "#include static('button')")...so, in the static() mixin, is there a way to dynamically determine the name of the mixin that static() is being used inside?
Or, is there another way to ensure a placeholder that is unique per-mixin?
No. Sass does not have a way to get any of the names of the mixins used.
That said, you're over-engineering. All you need to do is setup your extend selector outside of the mixin.
%common-button-styles {
border: 1px solid;
border-radius: 5px;
padding: .25em .5em;
&:hover {
cursor: pointer;
}
}
#mixin button($color) {
color: $color;
#extend %common-button-styles;
&:hover {
background-color: mix(black, $color, 15%);
}
}
If you're jumping through all of these hoops in an attempt to avoid creating duplicate extend only selectors via multiple imports, what you're looking for is called import once. If you're a Compass user, 1.0 includes an extension by default that does this. If not, a quick search will show you a few different ways of implementing such a feature.

Sass color variable not working inside darken()

I've got list of colors and I would like to use darken() on them like so:
$innerPagesBgColors: "#6B46C1", "#2980B9", "#FD5456", "#000";
.foo {
color: darken(nth($innerPagesBgColors, 3), 5%);
}
But I get this error:
$color: "#FD5456" is not a color for `darken'
I tried interpolating the nth() portion but that didn't help either.
The problem is that darken function requires a color as first argument and, instead, you're trying to pass a string.
type-of(#6B46C1); // returns color
type-of("#6B46C1"); // returns string
So you should remove all quotes in $innerPagesBgColors:
$innerPagesBgColors: #6B46C1, #2980B9, #FD5456, #000;
In my case I solved with this.
#each $name, $color in $set_colors{
// check type-of before
#if (type-of($color) == 'color'){
.color-#{$name}{
color: #{$color};
}
.background-#{$name}{
background-color: $color;
&:hover{
background-color: darken($color, 10%);
}
}
}
}

Passing a list to a mixin in SASS as parameters?

I'm trying to make a SCSS stylesheet easily configurable by defining a set of constants that will be used in a number of mixins and with the Compass library. Ideally, I'd like to be able to do the following:
$item-bgs: linear-gradient(white, black), #ccc;
#mixin some-mixin() {
#include background-with-css2-fallback($item-bgs*);
}
The background-with-css2-fallback is a Compass mixin that accepts up to 10 params. I'm assuming that SASS does not currently support passing a list parameter as the argument list, otherwise Compass would probably use it, but I'm wondering if I can get the $item-bgs list to be the first 2 arguments to the background-with-css2-fallback mixin. Is there a way to do this currently, or is it even planned for SASS in the future?
It may not be supported by SASS natively, but Compass does support passing a list as the first argument to the background-with-css2-fallback mixin. If you look at the source for the mixin, you'll see that it uses a compact function that handles the logic for collapsing the arguments into a single list, whether passed individually or in a single list parameter.
For example, this works fine for me:
#import "compass";
$item-bgs: (linear-gradient(white, black), #ccc);
.test {
#include background-with-css2-fallback($item-bgs);
}
Examples of useing maps as arguments:
Example 1 (list)
#mixin transition($property...){
#if $property {
transition-property: $property;
}
#else {
transition-property: all;
}
transition-timing-function: ease-in-out;
transition-duration: .3s;
transition-delay: 0;
}
.btn {
color: black;
border: 1px solid black;
#include transition(color, border-color);
&:hover {
color: red;
border-color: red;
}
}
Example 2 (Custom params)
#use 'sass:meta';
#mixin example2($args...) {
#each $key, $value in meta.keywords($args) {
#{$key}: #{$value};
}
}
.shape {
#include example2($width:200px, $height:100px);
}
Example 3 (map)
#mixin colors($args:()) {
#if length($colors) > 0 {
#each $key, $val in $args{
.txt-#{$key} {
color: #{$value};
}
.bg-#{$key} {
background-color: #{$value};
}
}
}
}
$colors_map: (
primary: blue,
secondary: green,
accent: red,
light: white,
dark: black
);
#include colors($colors_map);

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