How to copy unique files to each directory using shell scripting - bash

Question

I have lot of files in source directory with different name and ending with some number as suffix name. I need to copy all the files into 3 different directory. While copying, each file should be unique to other directory.
Example :
Source directory
1) Test01.csv
2) Test02.csv
3) Test03.csv
4) Nontesting01.csv
5) Nontesting02.csv
6) Nontesting03.csv
Destination directory
Directory 1 : Test01.csv
Nontesting01.csv
Directory 2 : Test02.csv
Nontesting02.csv
Directory 3 : Test03.csv
Nontesting03.csv
I have tried below code but it's copying 1 file per directory.
#!/bin/bash
dest=/Users/myprofile/Testing_
count=0
for f in *.csv ; do (cp $f/*.csv* "${dest}"${count}/$f ) ;
((count++))
done
Could someone help how to achieve this scenario using shell scripting.

Answer 1

Piggy-backing on what Jetchisel said, the code should be adapted, as a loop on patterns, to look like this:
#!/bin/bash
destPref="/Users/myprofile/Testing_"
for pattern in 01 02 03
do
files=(*${pattern}.csv)
cp -v -- "${files[#]}" "${destPref}${pattern}/"
done
As a general guidance, if you start by writing the code logic
in pseudo-code,
fine-grained for each task that you are trying to accomplish,
in the correct sequence and
in the correct context,
then having that worded so that it does exactly what you want it to do ... will, almost explicitly, tell you WHAT you need to code for each of those, not the HOW. The HOW is the nitty gritty of coding.
If you give that a try, the solution will almost pop out of the page at you.
Good luck with your apprenticeship!