While loop restart if condition isn't meant - bash

I'm trying to get this script to loop back and restart if the user inputs a response that does not match the choices allowed but then enters a correct response the second time around. I tried using continue, but it loops infinitely. Any thoughts?
`
#!/bin/bash
#Obtaing user selection and input
echo " Gathering list of users on this machine..."
sleep 2
echo "$( ls /Users )"
echo "From the list above, which user did you want to work with?"
read userSelection
echo "What is that user's password?"
#Hiding User's Password
stty -echo
read userSelectionPassword
stty echo
echo "Did you want [enable], [disable], or check the current [status] of Secure Token for $userSelection?"
read taskSelection
#Converting input to lowercase
taskSelectionLower=$(echo $taskSelection | tr '[:upper:]' '[:lower:]')
#Running commands
while [ true ]
do
if [[ $taskSelectionLower == "enable" ]]; then
echo "Enabling..."
echo "$(sysadminctl -adminUser AdminUser -adminPassword AdminPass -secureTokenOn $userSelection -password $userSelectionPassword)"
break
elif [[ $taskSelectionLower == "status" ]]; then
echo "Displaying $userSelection current Secure Token status..."
echo "$( sysadminctl -secureTokenStatus $userSelection )"
break
elif [[ $taskSelectionLower == "disable" ]]; then
echo "Disabling..."
echo "$(sysadminctl -adminUser AdminUser -adminPassword AdminPass -secureTokenOff $userSelection -password $userSelectionPassword)"
break
else
echo "Incorrect selection made..."
echo "Did you want [enable], [disable], or check the current [status] of Secure Token for $userSelection?"
read taskSelection
exit
fi
done
`
Attempted using continue at the end of the condition, but loops infinitely.
Expected outcome would be for the for loop to restart, allowing the user to input a correct response and get the correct output.

The select command was designed exactly for this sort of interactive script.
Some hopefully useful observations -
echo " Gathering list of users on this machine..."
sleep 2 # why?
This sleep seems to serve no purpose but to annoy the user.
echo "$( ls /Users )" # why?? Don't do this.
This is exactly the same as
ls /Users # same output. Keep it simple.
Also, since you are bash instead of sh, rather than
taskSelectionLower=$(echo $taskSelection | tr '[:upper:]' '[:lower:]')
try declaring the variable as lowercase -
declare -l taskSelectionLower
read taskSelectionLower
or handle it with parameter parsing syntax -
read taskSelectionLower
taskSelectionLower="${taskSelectionLower,,}"
but why let them possibly mistype at all?
Consider using a select statement.
Rather than building your own loop, presenting options, worrying about formatting, etc, let tools that already do that handle it for you.
My rewrite using echo to show the commands to be executed - take those out and it should run fine.
#!/bin/bash
cd /c/Users
echo "Please select a valid user from this system."
select u in */; do
if [[ -d "$u" ]]
then userSelection="${u%/}"; break
else echo "Please enter a number from the presented options."
fi
done # get just the username
cd $OLDPWD # if needed
admSet() { # no reason to ask for the password just to get status...
read -sp "what's $userSelection's password? " userSelectionPassword
echo # reading the password leaves the cursor on the previous line
echo sysadminctl -adminUser AdminUser -adminPassword AdminPass \
-secureToken$1 "$userSelection" -password "$userSelectionPassword"
}
select taskSelection in enable disable status; do # case is controlled
case "$taskSelection" in
status) echo "Displaying $userSelection current Secure Token status..."
echo sysadminctl -secureTokenStatus $userSelection ;;
enable) echo "Enabling..." ; admSet On ;;
disable) echo "Disabling..." ; admSet Off ;;
*) echo "Please enter a number from the presented options."
continue ;;
esac
break
done

Related

why is a bash read prompt not appearing when a script is run?

I have a bash script that prompts the user for different information based on what they're trying to do. The prompts are usually done with read -p. Usually it works just fine, the user sees what is being asked, enters what they need to enter, and everything does what it needs to do.
See the following (sanitized) snippet of a function in the script:
#!/bin/bash
function_name() {
if [ "$this_value" == "default" ];then
echo "Value set to default."
read -p "Enter desired value here: " desired_value
desired_value=${desired_value^^}
if [ "${#desired_value}" != 3 ] ;then
echo "$desired_value is an invalid entry."
exit 1
fi
if [ "$desired_value" != "$(some command that returns something to compare against)" ];then
echo "$desired_value is an invalid entry."
exit 1
fi
read -p "You entered $desired_value. Is this correct? [y/N] " reply
reply=${reply,,}
case "$reply" in
y|yes)
$some command that does what I want it to do
;;
*)
echo "User did not enter yes"
exit 1
;;
esac
fi
}
Usually the Enter desired value here and is this correct? lines appear just fine. But in a few instances I've seen, for some reason the read prompt is just blank. A user will see the following:
./script.bash
##unrelated script stuff
##unrelated script stuff
Value set to default.
user_entered_value_here
User did not enter yes. Exiting.
This is a real example that just happened that finally made me come here to ask what is going on (and I modified appropriately to make it an SO post).
What's happening is these two blank lines appear instead of the read -p text. For the first one, the user entered user_entered_value_here because they already know what is supposed to be entered there even without the read prompt. The second one, the Y/N prompt, they don't know, so they see it apparently hanging, and hit Enter instead of y, causing it to trigger the * case option.
I don't understand why the read -p text is not appearing, and especially why it's appearing for most users but not all users. I suspect there's some kind of environmental setting that causes this, but for the life of me I can't figure out what. This is being run only on RHEL 6.2, under bash 4.1.2.
I looked at the man of bash to catch some kind of detail about the read built-in. It is specified that -p option displays the "prompt on standard error, without a trailing newline, before attempting to read any input. The prompt is displayed only if input is coming from a terminal".
Let's consider the simple script input.sh:
#!/bin/bash
read -p "Prompt : " value
echo The user entered: "$value"
Example of execution:
$ ./input.sh
Prompt : foo
The user entered: foo
If stderr is redirected:
$ ./input.sh 2>/dev/null
foo
The user entered: foo
If the input is a pipe
$ echo foo | ./input.sh
The user entered: foo
If the input is a heredoc
$ ./input.sh <<EOF
> foo
> EOF
The user entered: foo
Rewrote your script with shell agnostic grammar and fixed some errors like comparing the string length with a string comparator != = rather than a numerical comparator -ne -eq:
#!/usr/bin/env sh
this_value=default
toupper() {
echo "$1" | tr '[:lower:]' '[:upper:]'
}
function_name() {
if [ "$this_value" = "default" ]; then
echo "Value set to default."
printf "Enter desired value here: "
read -r desired_value
desired_value=$(toupper "$desired_value")
if [ "${#desired_value}" -ne 3 ]; then
printf '%s is an invalid entry.\n' "$desired_value"
exit 1
fi
if [ "$desired_value" != "$(
echo ABC
: some command that returns something to compare against
)" ]; then
echo "$desired_value is an invalid entry."
exit 1
fi
printf 'You entered %s. Is this correct? [y/N] ' "$desired_value"
read -r reply
reply=$(toupper "$reply")
case $reply in
'y' | 'yes')
: "Some command that does what I want it to do"
;;
*)
echo "User did not enter yes"
exit 1
;;
esac
fi
}
function_name

How can I limit the input only to yes or no [duplicate]

In this particular case, I'd like to add a confirm in Bash for
Are you sure? [Y/n]
for Mercurial's hg push ssh://username#www.example.com//somepath/morepath, which is actually an alias. Is there a standard command that can be added to the alias to achieve it?
The reason is that hg push and hg out can sound similar and sometimes when I want hgoutrepo, I may accidentlly type hgpushrepo (both are aliases).
Update: if it can be something like a built-in command with another command, such as: confirm && hg push ssh://... that'd be great... just a command that can ask for a yes or no and continue with the rest if yes.
These are more compact and versatile forms of Hamish's answer. They handle any mixture of upper and lower case letters:
read -r -p "Are you sure? [y/N] " response
case "$response" in
[yY][eE][sS]|[yY])
do_something
;;
*)
do_something_else
;;
esac
Or, for Bash >= version 3.2:
read -r -p "Are you sure? [y/N] " response
if [[ "$response" =~ ^([yY][eE][sS]|[yY])$ ]]
then
do_something
else
do_something_else
fi
Note: If $response is an empty string, it will give an error. To fix, simply add quotation marks: "$response". – Always use double quotes in variables containing strings (e.g.: prefer to use "$#" instead $#).
Or, Bash 4.x:
read -r -p "Are you sure? [y/N] " response
response=${response,,} # tolower
if [[ "$response" =~ ^(yes|y)$ ]]
...
Edit:
In response to your edit, here's how you'd create and use a confirm command based on the first version in my answer (it would work similarly with the other two):
confirm() {
# call with a prompt string or use a default
read -r -p "${1:-Are you sure? [y/N]} " response
case "$response" in
[yY][eE][sS]|[yY])
true
;;
*)
false
;;
esac
}
To use this function:
confirm && hg push ssh://..
or
confirm "Would you really like to do a push?" && hg push ssh://..
Here is roughly a snippet that you want.
Let me find out how to forward the arguments.
read -p "Are you sure you want to continue? <y/N> " prompt
if [[ $prompt == "y" || $prompt == "Y" || $prompt == "yes" || $prompt == "Yes" ]]
then
# http://stackoverflow.com/questions/1537673/how-do-i-forward-parameters-to-other-command-in-bash-script
else
exit 0
fi
Watch out for yes | command name here :)
Confirmations are easily bypassed with carriage returns, and I find it useful to continually prompt for valid input.
Here's a function to make this easy. "invalid input" appears in red if Y|N is not received, and the user is prompted again.
prompt_confirm() {
while true; do
read -r -n 1 -p "${1:-Continue?} [y/n]: " REPLY
case $REPLY in
[yY]) echo ; return 0 ;;
[nN]) echo ; return 1 ;;
*) printf " \033[31m %s \n\033[0m" "invalid input"
esac
done
}
# example usage
prompt_confirm "Overwrite File?" || exit 0
You can change the default prompt by passing an argument
To avoid explicitly checking for these variants of 'yes' you could use the bash regular expression operator '=~' with a regular expression:
read -p "Are you sure you want to continue? <y/N> " prompt
if [[ $prompt =~ [yY](es)* ]]
then
(etc...)
That tests whether the user input starts with 'y' or 'Y' and is followed by zero or more 'es's.
This may be a hack:
as in question In Unix / Bash, is "xargs -p" a good way to prompt for confirmation before running any command?
we can using xargs to do the job:
echo ssh://username#www.example.com//somepath/morepath | xargs -p hg push
of course, this will be set as an alias, like hgpushrepo
Example:
$ echo foo | xargs -p ls -l
ls -l foo?...y
-rw-r--r-- 1 mikelee staff 0 Nov 23 10:38 foo
$ echo foo | xargs -p ls -l
ls -l foo?...n
$
This may be a little too short, but for my own private use, it works great
read -n 1 -p "Push master upstream? [Y/n] " reply;
if [ "$reply" != "" ]; then echo; fi
if [ "$reply" = "${reply#[Nn]}" ]; then
git push upstream master
fi
The read -n 1 just reads one character. No need to hit enter. If it's not a 'n' or 'N', it is assumed to be a 'Y'. Just pressing enter means Y too.
(as for the real question: make that a bash script and change your alias to point to that script instead of what is was pointing to before)
Add the following to your /etc/bashrc file.
This script adds a resident "function" instead of an alias called "confirm".
function confirm( )
{
#alert the user what they are about to do.
echo "About to $#....";
#confirm with the user
read -r -p "Are you sure? [Y/n]" response
case "$response" in
[yY][eE][sS]|[yY])
#if yes, then execute the passed parameters
"$#"
;;
*)
#Otherwise exit...
echo "ciao..."
exit
;;
esac
}
read -r -p "Are you sure? [Y/n]" response
response=${response,,} # tolower
if [[ $response =~ ^(yes|y| ) ]] || [[ -z $response ]]; then
your-action-here
fi
No pressing enter required
Here's a longer, but reusable and modular approach:
Returns 0=yes and 1=no
No pressing enter required - just a single character
Can press enter to accept the default choice
Can disable default choice to force a selection
Works for both zsh and bash.
Defaulting to "no" when pressing enter
Note that the N is capitalsed. Here enter is pressed, accepting the default:
$ confirm "Show dangerous command" && echo "rm *"
Show dangerous command [y/N]?
Also note, that [y/N]? was automatically appended.
The default "no" is accepted, so nothing is echoed.
Re-prompt until a valid response is given:
$ confirm "Show dangerous command" && echo "rm *"
Show dangerous command [y/N]? X
Show dangerous command [y/N]? y
rm *
Defaulting to "yes" when pressing enter
Note that the Y is capitalised:
$ confirm_yes "Show dangerous command" && echo "rm *"
Show dangerous command [Y/n]?
rm *
Above, I just pressed enter, so the command ran.
No default on enter - require y or n
$ get_yes_keypress "Here you cannot press enter. Do you like this"
Here you cannot press enter. Do you like this [y/n]? k
Here you cannot press enter. Do you like this [y/n]?
Here you cannot press enter. Do you like this [y/n]? n
$ echo $?
1
Here, 1 or false was returned. Note no capitalisation in [y/n]?
Code
# Read a single char from /dev/tty, prompting with "$*"
# Note: pressing enter will return a null string. Perhaps a version terminated with X and then remove it in caller?
# See https://unix.stackexchange.com/a/367880/143394 for dealing with multi-byte, etc.
function get_keypress {
local REPLY IFS=
>/dev/tty printf '%s' "$*"
[[ $ZSH_VERSION ]] && read -rk1 # Use -u0 to read from STDIN
# See https://unix.stackexchange.com/q/383197/143394 regarding '\n' -> ''
[[ $BASH_VERSION ]] && </dev/tty read -rn1
printf '%s' "$REPLY"
}
# Get a y/n from the user, return yes=0, no=1 enter=$2
# Prompt using $1.
# If set, return $2 on pressing enter, useful for cancel or defualting
function get_yes_keypress {
local prompt="${1:-Are you sure} [y/n]? "
local enter_return=$2
local REPLY
# [[ ! $prompt ]] && prompt="[y/n]? "
while REPLY=$(get_keypress "$prompt"); do
[[ $REPLY ]] && printf '\n' # $REPLY blank if user presses enter
case "$REPLY" in
Y|y) return 0;;
N|n) return 1;;
'') [[ $enter_return ]] && return "$enter_return"
esac
done
}
# Credit: http://unix.stackexchange.com/a/14444/143394
# Prompt to confirm, defaulting to NO on <enter>
# Usage: confirm "Dangerous. Are you sure?" && rm *
function confirm {
local prompt="${*:-Are you sure} [y/N]? "
get_yes_keypress "$prompt" 1
}
# Prompt to confirm, defaulting to YES on <enter>
function confirm_yes {
local prompt="${*:-Are you sure} [Y/n]? "
get_yes_keypress "$prompt" 0
}
Well, here's my version of confirm, modified from James' one:
function confirm() {
local response msg="${1:-Are you sure} (y/[n])? "; shift
read -r $* -p "$msg" response || echo
case "$response" in
[yY][eE][sS]|[yY]) return 0 ;;
*) return 1 ;;
esac
}
These changes are:
use local to prevent variable names from colliding
read use $2 $3 ... to control its action, so you may use -n and -t
if read exits unsuccessfully, echo a line feed for beauty
my Git on Windows only has bash-3.1 and has no true or false, so use return instead. Of course, this is also compatible with bash-4.4 (the current one in Git for Windows).
use IPython-style "(y/[n])" to clearly indicate that "n" is the default.
This version allows you to have more than one case y or Y, n or N
Optionally: Repeat the question until an approve question is provided
Optionally: Ignore any other answer
Optionally: Exit the terminal if you want
confirm() {
echo -n "Continue? y or n? "
read REPLY
case $REPLY in
[Yy]) echo 'yup y' ;; # you can change what you do here for instance
[Nn]) break ;; # exit case statement gracefully
# Here are a few optional options to choose between
# Any other answer:
# 1. Repeat the question
*) confirm ;;
# 2. ignore
# *) ;;
# 3. Exit terminal
# *) exit ;;
esac
# REPLY=''
}
Notice this too: On the last line of this function clear the REPLY variable. Otherwise if you echo $REPLY you will see it is still set until you open or close your terminal or set it again.
Late to the game, but I created yet another variant of the confirm functions of previous answers:
confirm ()
{
read -r -p "$(echo $#) ? [y/N] " YESNO
if [ "$YESNO" != "y" ]; then
echo >&2 "Aborting"
exit 1
fi
CMD="$1"
shift
while [ -n "$1" ]; do
echo -en "$1\0"
shift
done | xargs -0 "$CMD" || exit $?
}
To use it:
confirm your_command
Features:
prints your command as part of the prompt
passes arguments through using the NULL delimiter
preserves your command's exit state
Bugs:
echo -en works with bash but might fail in your shell
might fail if arguments interfere with echo or xargs
a zillion other bugs because shell scripting is hard
Try,
#!/bin/bash
pause ()
{
REPLY=Y
while [ "$REPLY" == "Y" ] || [ "$REPLY" != "y" ]
do
echo -e "\t\tPress 'y' to continue\t\t\tPress 'n' to quit"
read -n1 -s
case "$REPLY" in
"n") exit ;;
"N") echo "case sensitive!!" ;;
"y") clear ;;
"Y") echo "case sensitive!!" ;;
* ) echo "$REPLY is Invalid Option" ;;
esac
done
}
pause
echo "Hi"
This isn't exactly an "asking for yes or no" but just a hack: alias the hg push ... not to hgpushrepo but to hgpushrepoconfirmedpush and by the time I can spell out the whole thing, the left brain has made a logical choice.
Not the same, but idea that works anyway.
#!/bin/bash
i='y'
while [ ${i:0:1} != n ]
do
# Command(s)
read -p " Again? Y/n " i
[[ ${#i} -eq 0 ]] && i='y'
done
Output:
Again? Y/n N
Again? Y/n Anything
Again? Y/n 7
Again? Y/n &
Again? Y/n nsijf
$
Now only checks 1st character of $i read.
Below code is combining two things
shopt -s nocasematch that will take care of case insensitive
and if condition that will accept both the input either you pass yes,Yes,YES,y.
shopt -s nocasematch
if [[ sed-4.2.2.$LINE =~ (yes|y)$ ]]
then exit 0
fi
Here is my solution that using localised regex. So in german also "j" for "Ja" would be interpreted as yes.
First argument is the question, if the second argument is "y" than yes would be the default answer otherwise no would be the default answer. The return value is 0 if the answer was "yes" and 1 if the answer was "no".
function shure(){
if [ $# -gt 1 ] && [[ "$2" =~ ^[yY]*$ ]] ; then
arg="[Y/n]"
reg=$(locale noexpr)
default=(0 1)
else
arg="[y/N]"
reg=$(locale yesexpr)
default=(1 0)
fi
read -p "$1 ${arg}? : " answer
[[ "$answer" =~ $reg ]] && return ${default[1]} || return ${default[0]}
}
Here is a basic usage
# basic example default is no
shure "question message" && echo "answer yes" || echo "answer no"
# print "question message [y/N]? : "
# basic example default set to yes
shure "question message" y && echo "answer yes" || echo "answer no"
# print "question message [Y/n]? : "
I know this is an old question but this might help someone, it hasn't been addressed here.
I have been asked how to use rm -i in a script which is receiving input from a file. As file input to a script is normally received from STDIN we need to change it, so that only the response to the rm command is received from STDIN. Here's the solution:
#!/bin/bash
while read -u 3 line
do
echo -n "Remove file $line?"
read -u 1 -n 1 key
[[ $key = "y" ]] && rm "$line"
echo
done 3<filelist
If ANY key other than the "y" key (lower case only) is pressed, the file will not be deleted. It is not necessary to press return after the key (hence the echo command to send a new line to the display).
Note that the POSIX bash "read" command does not support the -u switch so a workaround would need to be sought.
Yes default base on Dennis Williamson answer
#!/bin/bash
confirm() {
# call with a prompt string or use a default
read -r -p "${1:-Are you sure?} [Y/n] " response
case "$response" in
#([nN])*([oO]))
false
;;
*)
true
;;
esac
}
I like to exit as soon as possible if the user isn't sure, and I like the code to be readable and short. Depending on whether you'd like the user to press Return after their answer or not,
With pressing Return,
read -p "Warning: something scary: Continue (Y/N)? " reply
[ $reply != 'Y' ] && [ $reply != 'y' ] && echo 'Aborting' && exit 1
echo 'Scary thing'
or if you prefer not to wait for the user to press Return,
read -n1 -p "Warning: something scary: Continue (Y/N)? " reply
echo ''
[ $reply != 'Y' ] && [ $reply != 'y' ] && echo 'Aborting' && exit 1
echo 'Scary thing'
The other answers have the background on that -n1 flag and other options for read. The echo '' in the 2nd variant is to make subsequent output appear on a new line since the user doesn't have to press Return, so no newline has been echoed to the terminal.

If / Else statement issues in bash scripting

I recently created a different thread with an issue concerning a for loop in a bash script I was writing for my GCSE coursework. I have another issue with the same bash script (however it has evolved a fair bit since last time).
Here is the code:
#!/bin/bash
# A script that creates users.
uerror='^[0-9]+$'
echo "This is a script to create new users on this system."
echo "How many users do you want to add? (in integer numbers)"
read am
echo " "
if [[ $am =~ $uerror ]] ; then
echo "ERROR: Please use integer numbers."
echo "Please re-enter the amount."
read am ;
else
echo " "
for i in $(seq "$am")
do
echo "Enter a username below:"
read usern
sudo useradd $usern
sudo passwd $usern
echo " "
echo "User $i '$usern' added."
echo " "
echo "What group do you want to add $usern to?"
read group
sudo usermod $usern -aG $group
echo "$usern added to $group"
echo " "
echo "-------------------"
echo " "
done
fi
The issue is in the if statement. It's purpose is to stop users entering anything other than an integer number. But for some reason, I don't seem to be able to capture the input from the read am part. Instead the script skips straight onto the for loop where the $(seq "$am") obviously will have issues comprehending an input that is not a number.
The output from this error is as follows.
seq: invalid floating point argument
However, I don't think this is relevant because as far as I can tell, the issue is with the if / else statement.
If anyone could point me in the right direction of what I need to do to fix this, I would be greatly appreciative.
I'd also like to iterate that I am still learning how to write bash scripts (and not in a particularly organised manner) so I've probably made a very simple mistake. Apologies for that.
Thanks,
Callum.
EDIT: I mistyped an echo message, I've now changed that so it actually makes sense.
If you want to read in a number and make sure it is a number use a while loop:
while read -p 'type a number:' n ; do
# Exit the loop if the input is a number
[[ "$n" =~ ^[0-9]+$ ]] && break
echo "This was not a number! Don't trick me!"
done
# Now can use `seq`
seq "$n"
The if statement in your example would do the completely the wrong thing. It checks if the input is a number and in that case asks for the input again and exits the script. If you don't type a number, it uses the (wrong) input in the else branch.
Replace your whole file with this:
#!/bin/bash
# A script that creates users.
uerror='^[0-9]+$'
echo "This is a script to create new users on this system."
echo "How many users do you want to add? (in integer numbers)"
read am
echo " "
while true; do
if [[ $am =~ $uerror ]] ; then
break;
else
echo "Must be integer"
echo "Please re-enter: "
read am ;
fi
done
for i in $(seq "$am")
do
echo "Enter a username below:"
read usern
sudo useradd $usern
sudo passwd $usern
echo " "
echo "User $i '$usern' added."
echo " "
echo "What group do you want to add $usern to?"
read group
sudo usermod $usern -aG $group
echo "$usern added to $group"
echo " "
echo "-------------------"
echo " "
done

Confirming Shell Script Input

I'm writing a script to preform a repetitive task that only changes basic values and locations such as user name.
I've written up code that prompts for a username and verifies that it is not already in use. I'm now trying to prompt the user if the input the script received is correct and if it is not to change it. My issue is that if the input is correct it keeps looping. Anyone have any suggestions?
clear
confirm () {
# call with a prompt string or use a default
echo "CMIT # ${1}"
read -r -p "CMIT [Y/n/q] > " answer
case "${answer}" in
[yY]|[yY][eE][sS]) false ;;
[nN]|[nN][oO]) true ;;
[qQ]|[qQ][uU][iI][tT]) exit 1 ;;
esac
}
while true; do
OE_USER=
while (id -u $OE_USER > /dev/null 2>&1); do
echo "CMIT # What user will this run under?"
read -r -p "CMIT > " OE_USER
if id -u $OE_USER > /dev/null 2>&1; then
echo "CMIT # Bad User Name. Try Again"
fi
done
clear
confirm "Continue installing using '$OE_USER' as the server name?"
done
You can either declare a global flag that gets set inside the confirm function on a good answer, or you can use a return statement inside confirm that gets tested in a conditional in your while loop.
There are other options too, like using a recursive call after testing the user input. This would negate the need for the while loop, but create the need to make your initial input a function as well.
You can use the exit status of your function:
Change the "yes" case to execute "true", and the "no" case to execute "false". Then
while true; do
# ...
if confirm "Continue installing using '$OE_USER' as the server name?"
then
break
fi
done
clear
GO=true
confirm () {
# call with a prompt string or use a default
echo "CMIT # ${1}"
read -r -p "CMIT [Y/n/q] > " answer
case "${answer}" in
[yY]|[yY][eE][sS]) GO=false ;;
[nN]|[nN][oO]) GO=true ;;
[qQ]|[qQ][uU][iI][tT]) exit 1 ;;
esac
}
while $GO; do
OE_USER=
while (id -u $OE_USER > /dev/null 2>&1); do
echo "CMIT # What user will this run under?"
read -r -p "CMIT > " OE_USER
if id -u $OE_USER > /dev/null 2>&1; then
echo "CMIT # Bad User Name. Try Again"
fi
done
clear
confirm "Continue installing using '$OE_USER' as the server name?"
done
GO=true

Whats the Vi command to delete a line from a file from a user input?

I have a file and want to delete lines when user enters an ID in UNIX/Vi.
The file is called 'users' and contains:
001:joe:one:20:01:02
002:joe:two:21:06:02
003:joe:three:22:05:02
004:joe:four:23:04:02
I have used the following function in Vi:
function deleteRecord()
{
echo "Please enter staff ID: "
read userID
#store staffID in variable
sID=$( grep -w "$userID" users )
#store staff details only if user does not exist
#else prompt them to input again until they enter unused data
if [ $? -ne 0 ]
then
echo "Sorry that user does not exist!"
echo "Try entering a different staff ID to delete"
deleteRecord
elif [ $? -eq 0 ]
then
#:g/^$userID:/d
#sed /$userID/d users >tmp
#imv tmp users
echo "You have successfully deleted the user."
sleep 2
mainMenu
fi
}
I have tried that but it does not work! Is sed the problem?
Please help.
You're best off using the built in functionality. e.g.
:g/^theuserid:/d
Only for fun - here is your homework. Next time tag it.
#!/bin/bash
IDFILE="./testfile"
function killVogon() {
while read -p 'Enter Vogon-ID (or "q" for return) >' id
do
case "$id" in
(q|Q) return;;
esac
grep "^0*$id:" "$IDFILE" >/dev/null 2>&1
case $? in
(0) ;;
(1) echo "Although it is infinitely improbable, the '$id' does not exists!"; continue;;
(*) echo "You're blind and can't see any Vogons around"; sleep 1 ; return;;
esac
sed -i '.bak' -e "/^0*$id:/d" "$IDFILE"
case $? in
(0) echo "The Vogon is successfully killed"; sleep 1; return;;
(*) echo "Huh... Marvin, powered with pangalactic gargleblaster is too paranoid now. The Vogon is NOT killed" ;;
esac
done
}
killVogon

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