how to extract a ip address from command result and store result in a variable [duplicate] - bash

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How to grep for contents after pattern?
(8 answers)
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How to extract the IP address of the output of the gcloud command mentioned bellow?
The goal is to extract the IP_ADRESS where TARGET contains targetPools and store it in a variable.
$ gcloud compute forwarding-rules list
>output:
NAME: abc
REGION: us
IP_ADDRESS: 00.000.000.000
IP_PROTOCOL: abc
TARGET: us/backendServices/abc
NAME: efg
REGION: us
IP_ADDRESS: 11.111.111.111
IP_PROTOCOL: efg
TARGET: us/targetPools/efg
desired output:
IP="11.111.111.111"
my attempt:
IP=$(gcloud compute forwarding-rules list | grep "IP_ADDRESS")
it doesn't work bc it need to
get the one with TARGET contains targetPools
extract the IP_ADRESS
store in local variable to be used
But not sure how to do this, any hints?

Answer 1

Using awk:
gcloud ... 2>&1 | awk -F: 'BEGIN {RS=""} $10 ~ /targetPools/ {print $6}'

Answer 2

With your given input, you could chain a few commands with pipes. That means there is always one line of text/string in between TARGET and IP_ADDRESS.
gcloud ... 2>&1 | grep -FB2 'TARGET: us/targetPools/efg' | head -n1 | sed 's/^.*: *//'
You could do without the head, something like
gcloud ... 2>&1 | grep -FB2 'TARGET: us/targetPools/efg' | sed 's/^.*: *//;q'
Some code explanation.
2>&1 Is a form of shell redirection, it is there to capturestderr and stdout.
-FB2 is a shorthand for -F -B 2
See grep --help | grep -- -B
See grep --help | grep -- -F
sed 's/^.*: *//'
^ Is what they call an anchor, it means from the start.
.* Means zero or more character/string.
. Will match a single string/character
* Is what they call a quantifier, will match zero or more character string
: Is a literal : in this context
* Will match a space, (zero or more)
// Remove what ever is/was matched by the pattern.
q means quit, without it sed will print/output all the lines that was matched by grep