Am I able to add list partitions to an un-partitioned oracle table? I have seen range partitions added in other examples online, but not list partitions. If I am able to add list partitions to an existing non-partitioned oracle table, are there some requirements that must be met to do so?
I tried
alter table t1 MODIFY
PARTITION BY LIST (c1)
( PARTITION c1a VALUES ('c1a'),
PARTITION c1b VALUES ('c1b'),
PARTITION c1c VALUES ('c1c'))
But get:
ORA-14006;invalid partition name
Related
I want to generate dynamically the below alter code(the below one is an eg, it will differ table to table) for all the partitioned tables in 12c DB.
Some tables may be partitioned on RANGE, LIST etc.
The column name, partition type will also change as per the table.
ALTER TABLE EMP
MODIFY PARTITION BY RANGE (START_DATE)
( PARTITION P1 VALUES LESS THAN (date'2021-1-1') ) ONLINE;
I have already created tables without partition in another db and now want to partition those tables which were partitioned in the source db. So want a simple script which can create code to partition the tables in the target db. Note - all tables have different partition and my goal is to make them sync with source. Only data differs in both the DBs.
The code below would create a new partition if I would insert a date that does not exist in my table. Is it possible to do the same thing in a list partitioned table, where the partition is based on a VARCHAR2 column?
ALTER TABLE MY_TABLE MODIFY
PARTITION BY RANGE(DATE) INTERVAL(NUMTODSINTERVAL(1,'day'))
( partition MY_PARTITION values less than (to_date('2019-06-01', 'yyyy-mm-dd')));
Yes, it is possible starting from the Oracle 12.2.
See the details here.
I have existing table which has 10 years of data (I have taken dump).
I would like to Range partition the existing table on one date key column within the table.
Most of the examples I see are with CREATE TABLE..PARTITION BY RANGE... to add new partitions. But my table is existing table.
I assume I need some ALTER statement.
ALTER TABLE TABLE_NAME
PARTITION BY RANGE(CREATED_DATE)
PARTITION JAN16 VALUES LESS THAN (01-02-2016),
PARTITION FEB16 VALUES LESS THAN (01-03-2016) AND GREATER THAN(31-01-2016),//OR?
PARTITION MAR16 VALUES BETWEEN (01-03-2016) AND (31-03-2016), //OR?
Two questions..
Do I need Alter statement to add partitioning mechanism or need to work with create statement?
What is the proper syntax for keeping each partition having only ONE MONTH data.
If you are using Oracle 12c Release 2 you could use single ALTER to convert non-partitioned table to partitioned one (this is one way trip):
CREATE TABLE my_tab ( a NUMBER(38,0), b NUMBER(38,0));
ALTER TABLE MY_TAB MODIFY PARTITION BY RANGE (a) INTERVAL (1000) (
PARTITION p1 VALUES LESS THAN (1000)) ONLINE;
You could convert indexes too, adding:
update indexes (index_name [local/global]);
db<>fiddle demo
Beacuse your table non-partitioned you have two options:
Export data, drop table, create new patitioned table, import data.
Use split then exchange partition method. https://oracle-base.com/articles/misc/partitioning-an-existing-table-using-exchange-partition
Also, if you want new partition per month read about SET INTERVAL. For example:
CREATE TABLE tst
(col_date DATE)
PARTITION BY RANGE (col_date) INTERVAL (NUMTOYMINTERVAL(1, 'MONTH'))
(PARTITION col_date_min VALUES LESS THAN (TO_DATE('2010-01-01', 'YYYY-MM-DD')));
I have a table which has two partitions (by range): first_half and second_half based on a column "INSERT_DAY".
I need to add subpartitions "SUCCESS" and "NONSUCCESS" based on the values of another column "STATUS" (subpartition by list) i.e. I need to transform my range partition to composite (range-list) partition.
I do not wish to drop existing tables or partitions. What is the ALTER query for this?
PS: The database is Oracle 9i
No alter query for adding subpartitions as far as i know.
To get the desired result performe the folowing steps
Create the table in the structure you want using create as select with the partitions and the sub partitions.
switch the names of the two tables.
you can also explore the use of dbms_Redefinition but if you have a luxury of a littel downtime it's not worth it.
I want to partition my table in hive so that for every unique item in the row it creates a partition. There are ~250 partitions for about a 4 billion row table so I would like to to something like a for loop or a distinct. Here is my thoughts in code (which obviously have not worked)
ALTER TABLE myTable ADD IF NOT EXISTS
PARTITION( myColumn = distinct myColumn);
or is there some kind of loop in Hive?
Does this require a UDF? A hive answer would be preferable if possible.
Thanks.
just use dynamic partitions
https://cwiki.apache.org/confluence/display/Hive/Tutorial#Tutorial-DynamicpartitionInsert
it does the partition creation on the go