I have a Java Spring Boot project where I need to be able to copy a file into a specific folder. However I am not able to copy any files. So I need to enable permissions for a specific folder where I am copying into. I am just copying files from one area of the image to another.
Is the following code using correct syntax? It does not seem like it is working because I still am not able to copy anything.
jib {
from {
image = "aregistry.com/images/jre11"
auth {
username = "${registryUsername}"
password = "${registryPassword}"
}
}
to {
image = "us-central1-docker.pkg.dev/myartifactregistry"
auth {
username = "oauth2accesstoken"
password = "${artifactRegistryToken}"
}
}
extraDirectories {
permissions = [
'/nativelibs': '755'
]
}
}
Specifically I am asking about the extraDirectories section. The folder lies at the root of the project.
Related
I want to copy storage.db to documents or downloads folder. It's very easy to get the file path:
const filePath = application.android.context.getDatabasePath("storage.db").getAbsolutePath();
But, what isn't that easy is to copy that file to a folder users have access to. I searched this whole forum, and I found nothing useful for my case.
I'm using NativeScript 4.0.1 with vanilla JS.
If you want to share the DB file, the easiest way is to use nativescript-share-file plugin, send the file path and it will give you a nice dialog with intent picker, user may choose to Email the file Or save it to local folder etc.,
const shareFile = new ShareFile();
shareFile.open({
path: filePath,
});
I finally found the solution. I've seen so many users trying to achieve this, and I hope this will help all of you.
Add this to your AndroidManifest.xml:
<uses-permission android:name="android.permission.WRITE_EXTERNAL_STORAGE"/>
Install nativescript-permissions:
npm i nativescript-permissions
Asking for permission:
const permissions = require('nativescript-permissions');
permissions.requestPermission(android.Manifest.permission.WRITE_EXTERNAL_STORAGE, "");
Require the necessary modules:
const fileSystemModule = require("tns-core-modules/file-system");
const application = require("application");
Then, create this function where you need to use it:
function copyFile() {
var myInput = new java.io.FileInputStream(appModule.android.context.getDatabasePath("storage.db").getAbsolutePath());
var myOutput = new java.io.FileOutputStream("/storage/emulated/0/databases/storage.db");
try {
var buffer = java.lang.reflect.Array.newInstance(java.lang.Byte.class.getField("TYPE").get(null), 1024);
var length;
while ((length = myInput.read(buffer)) > 0) {
myOutput.write(buffer, 0, length);
}
}
catch (err) {
console.info("Error", err);
}
//Close the streams
myOutput.flush();
myOutput.close();
myInput.close();
}
exports.copyFile = copyFile;
In my case, the file storage.db will be copied to /storage/emulated/0/databases. If you need to create a folder, just do the following:
try {
var javaFile = new java.io.File("/storage/emulated/0/newfolder");
if (!javaFile.exists()) {
javaFile.mkdirs();
javaFile.setReadable(true);
javaFile.setWritable(true);
}
}
catch (err) {
console.info("Error", err);
}
If the destination folder has a file with the same name as the one you want to copy, you need to remove it first. That's why you should create a specific folder to guarantee it's empty.
I am currently building a WinForms app and I need to create a bin file
in which I will serialize data. I let the user choose in which folder he wants the file to be saved in, but if he doesn't choose anything I want to save the file in a default path.
The thing is, I am not so familiar with windows' file system, and I am unable to find a good folder to save the file in.
My requirements from such folder are:
All windows computers should have it
The path to this folder all windows computer is the same
Is used for programs' auto-generated files as an "international default"
Not used frequently by the user (a "just don't touch" folder)
what is the common solution for such things?
You cas use a dedicated common ProgramData folder:
string CommonAppDataFolderPath
= Environment.GetFolderPath(Environment.SpecialFolder.CommonApplicationData)
+ Path.DirectorySeparatorChar
+ AssemblyCompany
+ Path.DirectorySeparatorChar
+ AssemblyTitle
+ Path.DirectorySeparatorChar;
public string AssemblyCompany
{
get
{
object[] attributes = Assembly.GetExecutingAssembly().GetCustomAttributes(typeof(AssemblyCompanyAttribute), false);
if ( attributes.Length == 0 )
{
return "";
}
return ((AssemblyCompanyAttribute)attributes[0]).Company;
}
}
public string AssemblyTitle
{
get
{
object[] attributes = Assembly.GetExecutingAssembly().GetCustomAttributes(typeof(AssemblyTitleAttribute), false);
if ( attributes.Length > 0 )
{
AssemblyTitleAttribute titleAttribute = (AssemblyTitleAttribute)attributes[0];
if ( titleAttribute.Title != "" )
{
return titleAttribute.Title;
}
}
return System.IO.Path.GetFileNameWithoutExtension(Assembly.GetExecutingAssembly().CodeBase);
}
}
It is AppData and you can get it with Environment.GetFolderPath:
(Environment is in System.IO namespace)
string binPath = Path.Combine(Environment.GetFolderPath(Environment.SpecialFolder.ApplicationData), "SomeAppName");
// this will return something like this:
// C:\Users\SomeUserName\AppData\Roaming\SomeAppName
You can use System.Reflection to identify a path in the debug or release folder of your assembly:
public static string Path = System.IO.Path.Combine(System.IO.Path.GetDirectoryName(
System.Reflection.Assembly.GetExecutingAssembly().GetName().CodeBase), "someapp");
I have some code that saves an xml file to the file system.
public static void Save(T obj, string FileName)
{
if (Application.Current.HasElevatedPermissions)
{
string myDocuments = Environment.GetFolderPath(Environment.SpecialFolder.MyDocuments);
string path = System.IO.Path.Combine(myDocuments, FileName);
using (var writer = new StreamWriter(path))
{
var serializer = new XmlSerializer(typeof(T));
serializer.Serialize(writer, obj);
writer.Flush();
}
}
else
{
throw new Exception("Cannot Save File. Application Requires Elevated permissions.");
}
}
While debugging using Internet Explorer 10 the file is not saved to the listed path in the path variable "C:\Users\Travis\Documents\Save.xml"
I call load with the exact same path "C:\Users\Travis\Documents\Save.xml" and the file loads correctly but the file still does not exist at the listed location.
I searched the file system with no results for Save.xml but it has to exist since it is able to load after application exit.
If I access the same page using Chrome the file is created successfully at the location.
I am wondering where Internet Explorer saves the file?
I found that if I uncheck "Enable Protected Mode" in IE's Security tab then the file is created in the location as expected.
I am having some trouble with a asp.net MVC3 web application that I am developing. I need an upload page which Allows the user to upload excel files and dump them to the file system. I got this to work fine. The next part is the part that I am having trouble with, After I upload the excel files I need to programmatically kick off a SSIS package which I have created already to import the excel files.
Here is what I have so far in code:
//
// POST: /Home/Update/
[HttpPost]
public ActionResult Update(HttpPostedFileBase file)
{
// Verify that the user selected a file
if (file != null && file.ContentLength > 0)
{
var fileName = Path.GetFileName(file.FileName);
// store the file inside ~/App_Data/uploads folder
var path = Path.Combine(Server.MapPath("~/App_Data/uploads"), fileName);
ViewBag.Message = "File Uploaded Successfully";
file.SaveAs(path);
}
//Start the SSIS here
try
{
Application app = new Application();
Package package = null;
package = app.LoadPackage( #"C:\Users\Chris\Documents\Visual Studio
2008\Projects\Integration Services Project1\Integration Services Project1
\bin\Package.dtsx", null);
// Execute Package
DTSExecResult results = package.Execute();
if(results == DTSExecResult.Failure)
{
foreach(DtsError local_DtsError in package.Errors)
{
ViewBag.Message("Package Execution results:{0}",
local_DtsError.Description.ToString());
}
}
}
catch(DtsException ex)
{
//ViewBag.Message("{0} Exception caught.", ex);
}
// redirect back to the index action to show the form once again
return RedirectToAction("Update");
}
When I run the code and upload an excel file I get a DtsException caught, which says:
Failed to open package file "C:\Users\Chris\Documents\Visual Studio 2008\Projects\Integration Services Project1\Integration Services Project1\bin\Package.dtsx" due to error 0x80070003 "The system cannot find the path specified.". This happens when loading a package and the file cannot be opened or loaded correctly into the XML document. This can be the result of either providing an incorrect file name was specified when calling LoadPackage or the XML file was specified and has an incorrect format.
I don't understand why it is giving me this because the file path is right I checked and it is exactly correct. I need some help fixing this issue I would greatly appreciate any help you guys can give.
Permissions I should think. Put the file somewhere where account running IIS can see it. Whereever you were planning on deploying it, would be good.
I'm developing a project with Maven. In a class to send e-mails, in run and dev modes, I get the following error: Caused by: java.io.FileNotFoundException: jQuery/images/logo.png (Ficheiro ou directoria inexistente) ==> translation = File or directory not found.
I've tryed lots of paths, like "./jQuery/images/logo.png", "/jQuery/images/logo.png" and others. The full relative path is: "src/main/webapp/jQuery/images/logo.png".
In "target" folder, the path is "project-1.0-SNAPSHOT/jQuery/images/logo.png".
Inside war file, is "jQuery/images/logo.png".
I don't think it's important, but I'm using NetBeans 7.1.1 as IDE.
I found that the absolute path returned in runtime is "/home/user/apache-tomcat-7.0.22/bin/jQuery/images/logo.png"!... It's not the project path!
How can I get a file in webapp folder and descendents from a Java class, in a Maven project?
The code is:
MimeBodyPart attachmentPart = null;
FileDataSource fileDataSource = null;
for (File a : attachments) {
System.out.println(a.getAbsolutePath());
attachmentPart = new MimeBodyPart();
fileDataSource = new FileDataSource(a) {
#Override
public String getContentType() {
return "application/octet-stream";
}
};
attachmentPart.setDataHandler(new DataHandler(fileDataSource));
attachmentPart.setFileName(fileDataSource.getName());
multipart.addBodyPart(attachmentPart);
}
msg.setContent(multipart);
msg.saveChanges();
Transport transport = session.getTransport("smtp");
transport.connect(host, from, "password");
transport.sendMessage(msg, msg.getAllRecipients());
The path .../apache-tomcat-7.0.22/bin/jQuery/... is really odd. bin contains scripts for Tomcat, it should not contain any code nor any resources related to your application. Even if you deploy your app in the context /bin, the resources would end up under `.../apache-tomcat-7.0.22/webapps/bin/...
This looks like a mistake made in an earlier deployment.
Now back to your question. To get the path of resource of your web app, use this code:
String absolutePath = getServletContext().getRealPath("/jQuery/images/logo.png");
(docs)