With a Genexus procedure, setting the call protocol to Http and the output_file rule, you can create a report and show to the user a pdf, basic Genexus tool. My problem is that I can't set the name of this pdf, it ignores the parameter of the output_file rule and if I try to save the pdf manually, it's named as the name of the procedure.
Can I set the name of the pdf somehow? Better if I can send it as parameter
Add this code to the procedure.
// &DocumentFriendlyName is varchar(100)
&HttpResponse.AddHeader(!"Content-Type", !"application/pdf")
&HttpResponse.AddHeader(!"Content-Disposition", !"attachment;filename=" + &DocumentFriendlyName + !".pdf")
If you don't want to download the PDF directly, create the PDF on the server, then use a &Window object to show it.
&Window.Url = &DownloadPdfUrl
&Window.Open()
If you add the rule:
Output_file(&FileName, 'PDF');
It does not generate the file with the value of the variable &FileName?
Related
I know there is already a similar question but the answers to that didn't work for me
I'm working with Genexus 16U11 and I have a panel with an image variable (called &sourceImage) with control type as "SD Image Annotation". I need to send this image to the server, in a specific folder. According the documentation if I call a procedure using the image as variable this should go on the server but it's not working. I can't find the image anywhere, I searched also in the PublicTempStorage directory, in the procedure is as the variable is empty.
I tried also to convert the image in base64 to send it as longvarchar to the procedure
&blob = &sourceImage.GetAnnotatedImage()
&longvarchar = ToBase64(&blob)
but in this way I can only get this string ZmlsZTovLy8vc3RvcmFnZS9lbXVsYXRlZC8wL0FuZHJvaWQvZGF0YS9jb20uYXJ0ZWNoLnJpY2hpZXN0YXBlcm1lc3NpMTZ1MTEuc2Zpcm1hL2ZpbGVzL3RyYW5zZm9ybWF0aW9ucy8yMDIyLTAzLTE4LS0xNC00My0yNi02MTQ2NDcyMTA5MjM5NDU3NzgzODAxLnBuZw==
that is the path of the file
file:////storage/emulated/0/Android/data/com.artech.richiestapermessi16u11.sfirma/files/transformations/2022-03-18--14-43-26-6146472109239457783801.png
I tried with file variable, blob, image, extra images, method fromUrl, nothing is working.
What am I doing wrong?
To upload the image to the server you need to call the procedure in the server (Connectivity=Online).
Then the image variable will be send to the server and you can save, copy, etc. there.
For example, save in a Transaction with a code like this:
Call in the panel:
Composite
&resultImage = &ImageA.GetAnnotatedImage()
procSaveImage(&resultImage)
EndComposite
Procedure online:
&TrnData = new()
&TrnData.TrnDataImage = &parmImage
&TrnData.Insert()
if &TrnData.Success()
commit
Working in Genexus v17u8 .
I am generating html report using pytest-html plugin. I'm executing the pytest file by giving "pytest --html=report.html" in command line.
So the name and title of the html report generated is report.html. I want to change the title of the generated report.
Please let me know, how to do that?
Since v2.1.0, this plugin exposes a hook called before adding the title to the report. You can add this to conftest.py:
def pytest_html_report_title(report):
report.title = 'your title!'
This is also explained in the plugin's User Guide.
create conftest.py file in the same folder of the test.
this file is used to configure pytest.
put this snippet inside
def pytest_html_results_summary(prefix, summary, postfix):
prefix.extend([html.h1("A GOOD TITLE")])
if you need to change the html report file name you can try something like this
# #pytest.hookimpl(tryfirst=True)
def pytest_configure(config):
# to remove environment section
config._metadata = None
if not os.path.exists('reports'):
os.makedirs('reports')
config.option.htmlpath = 'reports/' + datetime.now().strftime("%d-%m-%Y %H-%M-%S") + ".html"
my example will put the report.html file in a folder called reports naming with a date instead of a static name
From what I see in the code there is no mean to change only the report's title yet, it is for now hardcoded as
html.h1(os.path.basename(self.logfile))
So the report title will always be the report file name. I've just pushed a merge request to the project to add a new hook to allow the change of the title without changing the file name, we will see if it is accepted.
I have a models.ImageField which I sometimes populate with the corresponding forms.ImageField. Sometimes, instead of using a form, I want to update the image field with an ajax POST. I am passing both the image filename, and the image content (base64 encoded), so that in my api view I have everything I need. But I do not really know how to do this manually, since I have always relied in form processing, which automatically populates the models.ImageField.
How can I manually populate the models.ImageField having the filename and the file contents?
EDIT
I have reached the following status:
instance.image.save(file_name, File(StringIO(data)))
instance.save()
And this is updating the file reference, using the right value configured in upload_to in the ImageField.
But it is not saving the image. I would have imagined that the first .save call would:
Generate a file name in the configured storage
Save the file contents to the selected file, including handling of any kind of storage configured for this ImageField (local FS, Amazon S3, or whatever)
Update the reference to the file in the ImageField
And the second .save would actually save the updated instance to the database.
What am I doing wrong? How can I make sure that the new image content is actually written to disk, in the automatically generated file name?
EDIT2
I have a very unsatisfactory workaround, which is working but is very limited. This illustrates the problems that using the ImageField directly would solve:
# TODO: workaround because I do not yet know how to correctly populate the ImageField
# This is very limited because:
# - only uses local filesystem (no AWS S3, ...)
# - does not provide the advance splitting provided by upload_to
local_file = os.path.join(settings.MEDIA_ROOT, file_name)
with open(local_file, 'wb') as f:
f.write(data)
instance.image = file_name
instance.save()
EDIT3
So, after some more playing around I have discovered that my first implementation is doing the right thing, but silently failing if the passed data has the wrong format (I was mistakingly passing the base64 instead of the decoded data). I'll post this as a solution
Just save the file and the instance:
instance.image.save(file_name, File(StringIO(data)))
instance.save()
No idea where the docs for this usecase are.
You can use InMemoryUploadedFile directly to save data:
file = cStringIO.StringIO(base64.b64decode(request.POST['file']))
image = InMemoryUploadedFile(file,
field_name='file',
name=request.POST['name'],
content_type="image/jpeg",
size=sys.getsizeof(file),
charset=None)
instance.image = image
instance.save()
Is there a way to capture and store (or write to a file) the values returned in the Response? (Checkpoint values)
Using HP UFT 11.52
Thanks,
Lynn
I figured it out. In UFT API under Standard Activities, there are File function modules including "Write to File". I added the module to the test, set the path and other properties, passed the variable to the file and it worked! Couldn't be easier.
I mentioned this on my other answer , you can also write it programatically if you have dynamic array response please refer below:
https://stackoverflow.com/a/28012383/3972994
After running a test, in the test folder, you can find a Snapshots/LastIteration directory.
In it you can find the return value for each step saved in a txt file.
Pay attention that if you data drive the step, only the last iteration will be saved to file.
However, in the Test's log (Test dir/Log/vtd_user.log) you can find all the iterations persisted
Thanks,
Yossi
You do not need to use the standard activities if you do this
var iResponse = this.Activity.responsebody;
System.IO.File.WriteLines(#"directorypath&FileName);
the above will write the response to the file and rewrite it for every run
Using BIRT designer 3.7.1, it's easy enough to define a report for an XML file data source; however, the input file name is written into the .rptdesign file as constant value, initially. Nice for the start, but useless in real life. What I want is start the BIRT ReportEngine via the genReport.bat script, specifying the name of the XML data source file as parameter. That should be trivial, but it is surprisingly difficult...
What I found out is this: Instead of defining the XML data source file as a constant in the report definition you can use params["datasource"].value, which will be replaced by the parameter value at runtime. Also, in BIRT Designer you can define the Report Parameter (datasource) and give it a default value, say "file://d:/sample.xml".
Yet, it doesn't work. This is the result of my Preview attempt in Designer:
Cannot open the connection for the driver: org.eclipse.datatools.enablement.oda.xml.
org.eclipse.datatools.connectivity.oda.OdaException: The xml source file cannot be found or the URL is malformed.
ReportEngine, started with 'genReport.bat -p "datasource=file://d:/sample.xml" xx.rptdesign' says nearly the same.
Of course, I have made sure that the XML file exists, and tried different spellings of the file URL. So, what's wrong?
What I found out is this: Instead of defining the XML data source file as a constant in the report definition you can use params["datasource"].value, which will be replaced by the parameter value at runtime.
No, it won't - at least, if you specify the value of &XML Data Source File as params["datasource"].value (instead of a valid XML file path) at design time then you will get an error when attempting to run the report. This is because it is trying to use the literal string params["datasource"].value for the file path, rather than the value of params["datasource"].value.
Instead, you need to use an event handler script - specifically, a beforeOpen script.
To do this:
Left-click on your data source in the Data Explorer.
In the main Report Design pane, click on the Script tab (instead of the Layout tab). A blank beforeOpen script should be visible.
Copy and paste the following code into the script:
this.setExtensionProperty("FILELIST", params["datasource"].value);
If you now run the report, you should find that the value of the parameter datasource is used for the XML file location.
You can find out more about parameter-driven XML data sources on BIRT Exchange.
Since this is an old thread but still usefull, i ll add some info :
In the edit datasource, add some url to have sample data to create your dataset
Create your dataset
Then remove url as shown
add some script