Desrialzing JSON in spring boot, where a field is the combination of two fields - spring

Question

I have a controller with the following signiture:
public HttpEntity<RepresentationModel> confirmRegistration(#Valid #RequestBody RegistrationRequest request{}
the RegistrationRequest Json looks like this
{
//other fields
"countryCode":"44",
"mobileNumber": "07545878096"
}
I am trying to write a custom deserializer for this json
My mobileNumber class looks like this:
#Getter
#Setter
#EqualsAndHashCode
#ToString
#AllArgsConstructor
public class MobileNumber {
#JsonProperty("mobilePhoneNumber")
#JsonAlias("mobileNumber")
String number;
#JsonProperty(value = "countryCode", defaultValue = "44")
String countryCode;
}
and a request object like so:
public class RegistrationRequest {
//other fields
#JsonDeserialize(using = MobileNumberDeserializer.class)
#MobileNumberValidator
private final MobileNumber mobilePhoneNumber;
}
where the MobileNumberDeserializer looks like this:
public class ContactNumberDeserializer extends StdDeserializer<MobileNumber> {
private static final long serialVersionUID = 1L;
protected ContactNumberDeserializer() {
super(MobileNumber.class);
}
#Override
public MobileNumber deserialize(JsonParser jsonParser, DeserializationContext ctxt)
throws IOException {
JsonNode node = jsonParser.getCodec().readTree(jsonParser);
String mobileNumber = "";
if (node.has("mobilePhoneNumber")) {
mobileNumber = node.get("mobilePhoneNumber").asText();
} else if (node.has("phoneNumber")) {
mobileNumber = node.get("phoneNumber").asText();
} else if (node.has("mobileNumber")) {
mobileNumber = node.get("mobileNumber").asText();
}
String countryCode = node.get("countryCode").asText();
return new MobileNumber(mobileNumber, countryCode);
}
when the ContactNumberDeserializer is invoked by the controller,jsonParser.getCodec().readTree(jsonParser); it's just the mobilePhoneNumber node and cant access countryCode.

Answer 1

Quick check if ContactNumber and MobileNumber are the same classes.
Ideally it should be
public class ContactNumberDeserializer extends StdDeserializer<MobileNumber {
...
}

Answer 2

In your MobileNumber class:
#Getter
#Setter
#EqualsAndHashCode
#ToString
#AllArgsConstructor
public class MobileNumber {
#JsonProperty("mobilePhoneNumber")
#JsonAlias("mobileNumber")
String number;
#JsonProperty("countryCode")
String countryCode = "44";
}
Update JsonProperty annotation like above for countryCode. Hope it helps!

Answer 3

You don't need to write ContactNumberDeserializer. If you wrote your class MobileNumber it would simply work.