name 'Path' is not defined - python-3.9

Question

Here you can see the Python-code. As output then always appears: name 'Path' is not defined.
import tkinter as tk
from tkinter import filedialog
from tkinter import *
import pandas as pd
f = open("test_filedialog.txt", "w")
f.close()
def openfile():
Path=filedialog.askopenfilenames(title ="Datein auswählen", filetypes=[("CSV-Datein", "*.csv"),("alle Datein", "*.*")]).open("test_filedialog.txt", "w")
f = open("test_filedialog.txt", "w")
f.write(str(Path))
f.close()
x = tk.Tk()
title= x.title("Titelleiste")
label1=tk.Label(x, text="Hallo", width=25, height=5)
label1.pack()
button1=tk.Button (x, text="Exit",width= 10, height=1, command=x.destroy)
button1.pack()
button2=tk.Button (x, text= "open file", width= 15, height=2, command=openfile)
button2.pack()
x.mainloop()
#import matplotlib import pyplot as plt
daten=pd.read_csv(Path, header=None, sep=';',) #liest jetzt ausgewählte Spalten ein --> Die Frage ist wie wir das für Spaltenbereiche machen
df=daten.drop(range (2),axis=1)
new_header=df.iloc[0]
df=df[1:]
df.columns=new_header
auswahl=df.loc[:,158.936:159.01]
print(auswahl)
if __name__ == "__main__":
root = tkinter.Tk()
app = testApp(root)
root.mainloop()
`
I tried to define the 'Path' as an extra class. But unfortunately this did not lead to any result.
It would be nice if you have a solution for the problem. Maybe how to define the 'Path' as an extra class but also another solution would be ok :)

Answer 1

In python a variable defined inside a function does not have global scope. You shoud define a Path variable that is path to a csv file. You have error at line 38.
import pandas as pd
path = './data.csv' # path to csv file
df = pd.read_csv(path)
print(df.to_string())
Actually I should have tried to run the script.I have not fixed the error.
import tkinter as tk
from tkinter import filedialog
from tkinter import *
import pandas as pd
def read_csv(Path):
daten=pd.read_csv(Path, header=None, sep=',',)
print(daten)
# df=daten.drop(range (2),axis=1)
# new_header=df.iloc[0]
# df=df[1:]
# df.columns=new_header
# auswahl=df.loc[:,158.936:159.01]
# print(auswahl)
def openfile():
Path=filedialog.askopenfilenames(title ="Datein auswählen", filetypes=[("CSV-Datein", "*.csv"),("alle Datein", "*.*")])[0]
read_csv(Path) # do file operation in this function
x = tk.Tk()
title= x.title("Titelleiste")
label1=tk.Label(x, text="Hallo", width=25, height=5)
label1.pack()
button1=tk.Button (x, text="Exit",width= 10, height=1, command=x.destroy)
button1.pack()
button2=tk.Button (x, text= "open file", width= 15, height=2, command=openfile)
button2.pack()
x.mainloop()
#import matplotlib import pyplot as plt
if __name__ == "__main__":
root = tk()
# app = testApp(root)
root.mainloop()
The askopenfile function does not return an object but a tupple with file names. Also you should do file operations in openfile function. Hope it helps.