I have a thread group that runs 100,000 loops, with the date 2022-01-01 22:47:18 (HH:MM:SS are random within one day).
I need to generate data for 365 days.
How to make the date change to 2022-01-02 after 100,000 loops of 2022-01-01 are completed and another 100,000 loops are performed and so on until the end of the year?
Example:
100000 loops ran with date 2022-01-01 HH:MM:SS then jmeter increments date +1 day
100000 loops ran with date 2022-01-02 HH:MM:SS then jmeter increments date +1 day
100000 loops ran with date 2022-01-03 HH:MM:SS then jmeter increments date +1 day
etc.
Any pointers on how to do this please?
Related
I'm a beginner in Power Query and I have some data that that I want to repeat for each end of month to show a running total.
I can get the running total every time there's a transaction but how do I show a running total by month even if there are no transactions in that month?
You can merge the original table to a date table. Since you can do a running total if you were to just use amounts of 0 on days where there was no data (Find and replace nulls with 0) then you should be golden from there.
I have a dbms_scheduler job which has to run every 4 hours, in timezone 'Europe/Berlin'
My question is: what happens on days with a change in daylight saving time?
Let's say, last runtime was 01:00 AM. Not time either is set from 02:00AM to 03:00AM or from 03:00AM to 02:00AM.
Is the next runtime of my job after 3 hours in the first and after 5 hours in the second case or will it be just after 4 hours, regardless of the change in daylight saving time?
I'm trying to convert the normal 24 hour system to a 20 hour system in JavaScript or html
there seems to be problems and I don't know how to fix them, the program code as a whole works ok but it's not accurate in the area of displaying the proper time
can someone help me.
24hrs per day to 20hrs
60 minutes per hour to 40 minutes per hour
60 seconds per minute to 80 seconds per minute
1000 milliseconds per second to 1350 milliseconds per second
I have been working with the code that is supposed to get the milliseconds from 1/1/1970 to make things hopefully simple but like I said the program isn't working quite right, I do have a table that lets me know what normal time would be at each changed hour but that's all the info I have
Check this Fiddle:
http://jsfiddle.net/z4s7j9vL/1/
My approach was to get the timestamp difference between the current time and midnight of the same day:
millis = ts - clone.getTime();
This way you get how many milliseconds have passed this day and you can do your conversion from there. This is limited to converting time only, but if months and years followed the same principles you could just convert the same way from the current timestamp.
I have programmed a punch clock system. I need to modify it to comply with California overtime rules such that if someone works more than 8 hours in 24, they receive overtime. I am stumped on how to go about doing this that is not computationally intensive.
Our punches are rounded to 15 minute intervals, meaning people will punch in at 8:00 AM, 8:15 AM, 8:30 AM and so on.
So if someone starts at 8am on Monday, works a total of 8 hours, and starts at 7am on Tuesday, they get an hour of overtime?
Assume you have a list of start/stop date time pairs for a given employee. This list has to include start/stop date time pairs from the previous time period.
Get the first start/stop date time pair from the current pay period.
Get the previous start/stop date time pair.
Determine the interval in hours and fractions of hours between the previous start and the current start.
If the interval is greater than or equal to 24, get the next current pay period start/stop date time pair, and go to 2. Exit if no more start/stop date time pairs.
Else, if the interval is less than 24, calculate the overtime in the current start/stop date time pair. The lessor of (24 - interval) and the amount of hours worked in the current start/stop date time pair.
Get the next current pay period start/stop date time pair. Exit if no more start/stop date time pairs.
Hold the previous start/stop date time pair.
Go to 3.
how can I determine machine time in seconds on unix O/S? (i can't use 'date +%s', it's not POSIX).
what functions exist for date and epoch time in second?
by using date "+%format" how can i subtract 1-2 hour from present hour?
Regards
Try the time function in time.h. For example:
time_t the_time=time(NULL);
// the_time now contains the number of seconds since the epoch
To get a time in the past, just subtract the number of seconds. Since there are 3600 seconds in an hour, to go an hour back, just subtract 3600.