A5
B5
This cell contains 01/02/2023, but has 31/01/2023 and 25/12/2022 too
=REGEXEXTRACT(A6;"[0-9]+[0-9]+[/][0-9]+[0-9]+[/][0-9]+[0-9]")
A5
B5
C5
D5
This cell contains 01/02/2023, but has 31/01/2023 and 25/12/2022 too
01/02/2023
31/01/2023
25/12/2022
can you try:
=INDEX(IFNA(--REGEXEXTRACT(TO_TEXT(SPLIT(REGEXREPLACE(B5;"(\d{2}/\d{2}/\d{4})";"$1🐠");"🐠"));"(\d{2}/\d{2}/\d{4})")))
try:
=REGEXEXTRACT(A6; REGEXREPLACE(A6; "( \d+/\d+/\d{4})"; "($1)"))
arrayformula:
=INDEX(REGEXEXTRACT(A2:A; REGEXREPLACE(A2:A; "( \d+/\d+/\d{4})"; "($1)")))
Related
I am looking to format a phone number with twig.
Basically, I wanted to separate every 2 digits with this function and it works perfectly when I have a 10-digit phone number like 0600000000:
{% set splitPhone = store.phones['phone_store']|split('', 2) %}
{% set phone = splitPhone|join(' ') %}
I get what I want:
06 00 00 00 00
The problem is that my data can also arrive in the form: +336000000
so in that case I get
+3 36 00 00 00
I would like something like : + 336 00 00 00
In this case, I would like to find a general technique to ensure that if my number is 10 digits, it does as I currently do but in case there is the "+" in front, it separates it from the digits.
Do you know how I can do this?
You can just extend twig with a custom filter which solves this for you, e.g.
$twig->addFilter(new \Twig\TwigFilter('format_phone', function($phone) {
$prefix = null;
if (strpos($phone, '+') === 0) $prefix = substr($phone, 0, 4).' ';
$temp = str_split(substr($phone, $prefix ? 4 : 0), 2);
return $prefix.implode(' ', $temp);
});
demo
{{ '0600000000'|format_phone }}
{{ '+336000000'|format_phone }}
Hi I was wondering if yall could help me figure this error out. Im rather new to cobol as it is my first (and only) cobol class in my major.
I keep getting this error lab3a.cob:23: Error: syntax error, unexpected "Identifier", expecting EXTERNAL or GLOBAL
whenever I try to compile. And I cant seem to see what I'm doing wrong.
My Code
IDENTIFICATION DIVISION.
PROGRAM-ID. "LAB3A".
Author. Fielding Featherston
* Takes inputs from file and seperates.
ENVIRONMENT DIVISION.
INPUT-OUTPUT SECTION.
FILE-CONTROL.
SELECT InFile
ASSIGN to "lab3-in.dat"
ORGANIZATION is LINE SEQUENTIAL.
DATA DIVISION.
FILE SECTION.
FD InFile.
01 InString.
05 PIC X(13).
05 Instrument PIC X(12).
88 Brass value "Bugle" "Flugelhorn"
"Sousaphone" "Trombone"
"Trumpet" "Tuba".
88 Percussion value "Bass Drum" "Bells" "Bongos"
"Castanets" "Chimes" "Cymbals"
"Snare Drum" "Xylophone".
88 Strings value "Banjo" "Bass" "Cello" "Guitar"
"Harp" "Lyre"
"Mandolin" "Violin".
88 Woodwind value "Bagpipes" "Bassoon" "Clarinet"
"Flute" "Oboe"
"Piccolo" "Saxophone".
WORKING-STORAGE SECTION.
01 BrassCount PIC 9(3).
01 PerCount PIC 9(3).
01 StringCount PIC 9(3).
01 WoodCount PIC 9(3).
01 OtherCount PIC 9(3).
01 BrassStr PIC ZZ9.
01 PerStr PIC ZZ9.
01 StringStr PIC ZZ9.
01 WoodStr PIC ZZ9.
01 OtherStr PIC ZZ9.
01 InStringLength PIC 99.
01 EndFileStr PIC X VALUE "n".
88 EndFile VALUE "y"
When Set to False is "y".
PROCEDURE DIVISION.
000-Main.
Open Input InFile
Perform until EndFile
Read InFile
At end
Set EndFile to FALSE
Not at End
PERFORM 100-SeperateStrings
PERFORM 200-ClassCount
END-READ
END-PERFORM
CLOSE InFile
Move BrassCount to BrassStr
Move PerCount to PerStr
Move StringCount to StringStr
Move WoodCount to WoodStr
Move OtherCount to OtherStr
DISPLAY "Counts"
DISPLAY " Brass: " FUNCTION TRIM(BrassStr)
DISPLAY " Percussion: " FUNCTION TRIM(PerStr)
DISPLAY " String: " FUNCTION TRIM(StringStr)
DISPLAY " Woodwind: " FUNCTION TRIM(WoodStr)
DISPLAY " OTHER: " FUNCTION TRIM(OtherStr)
STOP RUN.
100-SeperateStrings.
MOVE FUNCTION Length(InString) to InStringLength
UNSTRING InString (14:InStringLength)
INTO Instrument
END-UNSTRING.
200-ClassCount.
IF Brass
Add 1 to BrassCount
ELSE IF Percussion
Add 1 to PerCount
ELSE IF Strings
Add 1 to StringCount
ELSE IF Woodwind
Add 1 to WoodCount
ELSE
Add 1 to OtherCount
END-IF.
An EXTERNAL or GLOBAL clause in the context of the error may only occur in a record description entry; that is, a data entry that begins with 1 or 01. Given that the error occurs between two 88 level items, it appears the compiler is confused about where it is while scanning the source code.
There is some unusual formatting that may be creating a problem with an the compiler. In particular, line 22 contains a number of TAB characters that should not, but may, confuse the compiler. Also, lines 33 and 46 contain a number of TAB characters at the end of each source line causing the lines to exceed 72 characters.
Another possible issue is expansion of tabs, whether each TAB character is replaced by 4 or 8 spaces by the compiler. Again this will affect whether the text exceeds 72 characters. In the absence of a SOURCE FORMAT directive, source text after column 72 is ignored.
Until you know the effect that tabs have on the source code, I suggest replacing all tabs with spaces.
This is my first question here, so hope it's correctly done.
Im trying to get some information from a ZTE C300 OLT.
The thing is when i try to get the SN of one of the ONTS I get the response in HEX-String
snmpwalk -cpublic -v2c [OLTIP] 1.3.6.1.4.1.3902.1082.500.10.2.2.5.1.2
And this is the response that I get
SNMPv2-SMI::enterprises.3902.1082.500.10.2.2.5.1.2.285278736.1 = Hex-STRING: 5A 54 45 47 C8 79 9B 27
This is the SN that i have on the OLT ZTEGC8799B27, but im trying to convert the HEX-STRING into text and i don't get that SN text.
Indeed i have a python script for SNMP and the response that i get for that OID is
{'1.3.6.1.4.1.3902.1082.500.10.2.2.5.1.2.285278736.1': "ZTEGÈy\x9b'"}
Can someone give me a hand on this?. I'm new on SNMP and this is giving me some headache.
Thanks in advace!
This is a 8 octet hex string, the first 4 octets are ASCII.
Just convert hex 2 ascii.
Indeed it was easier. The firts 4 bytes were encoded, and the other 4 is the actual serial number splitted every 2 digits. So i only need to decode the first part and concatenate the rest.
Works with OLT ZTE C320
def hex_str(str):
str = str.strip()
str = str.split(' ')
vendor_id = ''
serial = str[4:]
serial = "".join(serial)
for hex_byte in str[:4]:
vendor_id += chr(int(hex_byte, 16))
normalized_serial = vendor_id + serial
return normalized_serial
def ascii_to_hex(str):
arr = []
hex_byte = ''
for i in range(len(str)):
hex_byte += hex(ord(str[i]))
hex_byte = hex_byte.replace('0x', ' ')
hex_byte = hex_str(hex_byte)
return hex_byte
# value = f"5A 54 45 47 C8 79 9B 27 "
# value = f"49 54 42 53 8B 69 A2 45 "
# value = f"ZTEGÈy\x9b'"
value = f"ITBS2Lz/"
# value = f"ITBS2HP#"
if(len(value) == 24):
print(hex_str(value))
else:
print(ascii_to_hex(value))
I'm trying a process with powercenter designer but I do not get the desired objective.
I have these initial data:
CODE CODE2 OPTION
001 A 89
001 A 55
001 A 12
002 B 25
002 A 59
025 A 44
I have to get it for code to do the following: if there are several records per CODE then you have to put the value 1111 in the OPTION2 field to the record with the highest value in the OPTION field, if there is only one record in CODE it also puts the value 1111. I do this by making an SORTER transformation in powercenter, not complicated.
What I can not do is the next step. The second record with the highest value in the OPTION field corresponds to the value of the first field and so on.
OUTPUT:
CODE CODE2 OPTION OPTION2
001 A 89 111111
001 A 55 89
001 A 12 55
002 A 59 111111
002 B 25 59
025 A 44 111111
How could I get this?
What transformations should I use?
Thanks! ^^
You can sort it by code and descending order of option. Then in an expression variable hold the value for the previous record's value in a variable.
v_OPTION2 = IIF(ISNULL(v_PREV_CODE) OR CODE != v_PREV_CODE,
111111,
v_PREV_OPTION
)
out_OPTION2 = v_OPTION2
v_PREV_OPTION = OPTION
v_PREV_CODE = CODE
I am trying to read data from sony felica card using pc/sc transparent session and transceive data object.
The response I am getting is for a read without encryption command is
c0 03 00 90 00 92 01 00 96 02 00 00 97 82 00 + Data
But according to the protocol, the response should be
c0 03 00 90 00 92 01 00 96 02 00 00 97 + Data
I am unable to figure out the last 82 00 appended in the response from the card.
Now when I try to authenticate with the card I get
c0 03 01 6F 01 90 00
which is a error in pc/sc. I want to resolve these extra bytes 82 00 which I believe will solve the issue with all the commands which require authentication and encryption.
The response data is BER-TLV encoded (see PC/SC 2.02, Part 3).
In BER-TLV encoding there are several possibilities to encode tag 0x97 with two octets of data 0xD0D1, e.g.:
97|02|D0D1 -- short form (see parsed)
97|8102|D0D1 -- long form with one octet with length (see parsed)
97|820002|D0D1 -- long form with two octets with length (see parsed)
97|83000002|D0D1 -- long form with three octets with length (see parsed)
...
Your reader is using two octets for sending the length of ICC Response data object (which is perfectly valid).
You should parse the response properly...Good luck!
PS: The above means, that the Data part of your truncated responses still contains one extra byte with the response length (i.e. Len|Data)