I am getting pulling the data from server and placing that in my local.
curl --verbose --ftp-ssl--user 'username:password' ftp://abc.com:001//this/is/stackoverflow/ > /home/dir1/dir2/dir3
In ideal scenario i am getting below output after hitting more dir3 command in unix.
drwxrwxrwx 1 owner group 0 Jan 1 2021 00:00 filename1
drwxrwxrwx 1 owner group 0 Jan 1 2022 04:30 filename2
drwxrwxrwx 1 owner group 0 Jan 1 2021 06:30 filename3
-rwxrwxrwx 1 owner group 1122 Jan 1 2022 08:30 filename4
-rwxrwxrwx 1 owner group 2233 Jan 1 2022 10:30 filename5
-rwxrwxrwx 1 owner group 3344 Jan 1 2023 11:30 filename6
I want something that the date will be in reverse order. I have tried multiple command below,it didnt work. Was trying to reverse with Month as its 6th col so using -k6M
curl --verbose --ftp-ssl--user 'username:password' ftp://abc.com:001//this/is/stackoverflow/ > /home/dir1/dir2/dir3 | sort -n -t- -k6M | tail -1
curl --verbose --ftp-ssl--user 'username:password' ftp://abc.com:001//this/is/stackoverflow/ > /home/dir1/dir2/dir3 | sort -n -t- -k6M
curl --verbose --ftp-ssl--user 'username:password' ftp://abc.com:001//this/is/stackoverflow/ > /home/dir1/dir2/dir3 | sort -k6M | tail -1
some more command i have used. All i want while using curl command , all the files should placed in reverse order in directory itself.
Related
Let's say I run a command in Bash like:
ls -l | grep filename
How can I save output of both command to a variable? In another words output of "ls -l" and "grep filename" to the same variable?
The command must use a pipe.
Thank you in advance!
combinedOutput = ""
ls -l
total 4
-rw-r--r-- 1 webmaster webmaster 0 Nov 16 20:34 a
-rw-r--r-- 1 webmaster webmaster 0 Nov 16 20:34 b
-rw-r--r-- 1 webmaster webmaster 0 Nov 16 20:34 file1.txt
-rw-r--r-- 1 webmaster webmaster 0 Nov 16 20:34 file2.txt
-rw-r--r-- 1 webmaster webmaster 5 Nov 16 20:34 main.sh
ls -l | grep main.sh
-rw-r--r-- 1 webmaster webmaster 20 Nov 16 20:35 main.sh
echo $combinedOutput
total 4
-rw-r--r-- 1 webmaster webmaster 0 Nov 16 20:34 a
-rw-r--r-- 1 webmaster webmaster 0 Nov 16 20:34 b
-rw-r--r-- 1 webmaster webmaster 0 Nov 16 20:34 file1.txt
-rw-r--r-- 1 webmaster webmaster 0 Nov 16 20:34 file2.txt
-rw-r--r-- 1 webmaster webmaster 5 Nov 16 20:34 main.sh
-rw-r--r-- 1 webmaster webmaster 20 Nov 16 20:35 main.sh
UPDATE #1:
A better example: let's say I am trying to archive and compress a directory using the following command:
tar cvf - /some/directory/ | pigz --verbose -1 -p 4 >compressed_archive.tgz;
The question is how to put outputs of "tar cvf - /some/directory/" and "pigz --verbose -1 -p 4 >compressed_archive.tgz" to a variable.
Simply:
combinedOutput=$(( ls -l | tee /dev/stderr | grep filename ) 2>&1)
echo "$combinedOutput"
Just run two commands.
combinedOutput=$(
ls -l
ls -l | grep filename
)
But anyway, you may be more comfortable with just:
one=$(ls -l)
two=$(ls -l | grep filename)
combinedOutput="$one
$two"
It's not possible to get the output you want with echo $combinedOutput. You can do echo "$combinedOutput". Consider researching shell quoting. Check your scripts with shellcheck.
I am trying to copy the first two items in my 'Downloads' directory using only the terminal.
I open up zsh, cd into my 'Downloads' directory and start typing.
The below reflects what is shown in the terminal:
% ls -lt | head -3
file1.csv
file2.csv (exactly the files I want)
% ls -lt | head -3 > ToBeCopied.txt
% vim ToBeCopied.txt
total 24625744
-rw-r--r-- 1 Aaron staff 0 22 Apr 15:28 ToBeCopied.txt
-rw-r--r--# 1 Aaron staff 42042 22 Apr 15:16 file1.csv
What happened to file2.csv?
I'm a little bit confused, i changed my time on one file with the shell command :
touch -t = touch -t 201606012135 trial01
But after the ls -lt, I got this :
-rw-r--r-- 1 CharleyD staff 87 1 jun 2016 trial01
drwxr-xr-x 15 CharleyD staff 510 3 apr 12:57 Hybrid_proj
Why the shell doesn't write the hours like the "Hybrid_proj" directory for the "trial01" ? The trial01 file have the hour : 21:35, so itsn't empty.
Indeed, I search to get this in output :
-rw-r--r-- 1 CharleyD staff 87 1 jun 21:35 trial01
drwxr-xr-x 15 CharleyD staff 510 3 apr 12:57 Hybrid_proj
How I can do this ?
Thx a lot buddies to enlighten my way ! ;)
If a file is not from the current year, ls defaults to showing the year instead of the time. The time is still correctly set, just formatted differently.
To always show the full time, with GNU ls, you can use ls --time-style=long-iso -l:
$ ls --time-style=full-iso -l
total 0
-rw-r--r-- 1 user user 0 2017-04-04 13:20 newfile
-rw-r--r-- 1 user user 0 2016-04-03 12:34 oldfile
With BusyBox ls, you can use -e:
$ busybox ls -e
total 0
-rw-r--r-- 1 user user 0 Tue Apr 4 13:20:42 2017 newfile
-rw-r--r-- 1 user user 0 Sun Apr 3 12:34:00 2016 oldfile
With macOS ls, you can use -lT:
$ ls -lT
total 0
-rw-r--r-- 1 user group 0 Apr 4 13:19:35 2017 myfile
-rw-r--r-- 1 user group 0 Apr 3 12:34:00 2016 oldfile
In each case, you get a long timestamp with the same format for older and newer files.
Use the -T option if your ls supports it.
I am trying to extract the newest file in folder.
I tried this:
ls -1t | head -1
But the problem is, that this command doesn't seem to differentiate in which second the file was created - if multiple files were created in the the same, this command just give the first file in this minute.
Is there a way to make this command more precise?
You should add T argument to the options to do that:
ls -1tT | head -1
See the output when l argument is added:
ls -tTl
-rw-r--r-- 1 user wheel 0 Apr 23 17:54:27 2016 1
-rw-r--r-- 1 user wheel 0 Apr 23 17:54:19 2016 3
-rw-r--r-- 1 user wheel 0 Apr 23 17:54:12 2016 2
I'd to display every two line, a line from a file. I've seen the sed -n 'f~d' awk and perl method. But the sed one doesn't work on osX (As I understood) and the two others are are interpreted languages which i can't use.
Can you help me ?
Here's an exemple :
output before :
-rw-r--r-- 1 mfassi-f 2013 22 Jul 17 12:36 test.sh
-rw-r--r-- 1 mfassi-f 2013 29 Jul 17 12:30 test1.sh
-rw-r--r-- 1 mfassi-f 2013 22 Jul 17 12:36 test2.sh
-rw-r--r-- 1 mfassi-f 2013 29 Jul 17 12:30 test3.sh
-rw-r--r-- 1 mfassi-f 2013 22 Jul 17 12:36 test4.sh
-rw-r--r-- 1 mfassi-f 2013 29 Jul 17 12:30 test5.sh
-rw-r--r-- 1 mfassi-f 2013 22 Jul 17 12:36 test6.sh
output after :
-rw-r--r-- 1 mfassi-f 2013 29 Jul 17 12:30 test1.sh
-rw-r--r-- 1 mfassi-f 2013 29 Jul 17 12:30 test3.sh
-rw-r--r-- 1 mfassi-f 2013 29 Jul 17 12:30 test3.sh
-rw-r--r-- 1 mfassi-f 2013 29 Jul 17 12:30 test5.sh
Here are two answers. One for a file, and one for command-line input.
['cause the question's changed ever so slightly, but these two seemed too similar to put as independent answers].
You can use zsh, ls, cut and paste to do this in a for loop. It's not the cleanest solution, but it does work (surprisingly).
for file in `ls -1 | paste - - | cut -f 1`
do
ls -l -d $file
done
We take the output of ls -1, then extract every second filename. (The way ls chooses to sort the files will have an impact here). Then, we do ls -l -d on each of these files. -d is necessary to stop ls from showing us the contents of $file, if $file is a directory. (Not sure if this is OS X specific, or if that's default POSIX ls behaviour).
Second answer: display every second line from a file.
If you're after a mostly zsh solution, you could do something like the following:
$ jot 8 0 7 >> sample.txt # Generate some numbers.
$ count=0 # Storage variable
$ for i in `cat sample.txt`
do
if [ $(( $count % 2 )) -eq 0 ] ; then
echo $i
fi
count=`expr $count + 1`
done
This displays every second line.
Notes:
- This leaves a variable count in your session afterwards (it's not clean).
- This fails badly if sample.txt does not contain a single word per line.
- I'm almost sure that the modulus comparison I do isn't the most efficient: I grabbed it from here.
- I say it's mostly zsh because it does rely on cat, but I'm not sure how to avoid that.
The OS X version of sed is frustrating. Using sed -n '0~2p' <filename> doesn't work because, in the BSD sed, -n does something different:
-n
By default, each line of input is echoed to the standard output after all of the commands have been applied to it. The -n option suppresses this behavior.
I'd highly recommend installing GNU sed, which can be done using Homebrew:
brew install gnu-sed
And then you can use:
gsed -n '0~2p' filename # Display the 2nd, 4th etc
gsed -n '1~2p' filename # Display the 1st, 3rd etc.