Is it possible to run something like this:
parent-script.sh "child-script1.sh | child-script2.sh"
and execute $1 inside the parent-script.sh?
...
CMD=$1
...
$CMD
Related
I have a bash script named test.sh with:
#!/bin/bash
var1=hello
sh test2.sh $var1="/var/log"
My test2.sh looks like this:
#!/bin/bash
function jumpto
{
label=$1
cmd=$(sed -n "/$label:/{:a;n;p;ba};" $0 | grep -v ':$')
eval "$cmd"
exit
}
start=${1:-"start"}
jumpto $start
start:
echo "variable -- " $var1
This does not work due to I used jumpto function. When execution, always $var1 assigned to the $1 variable in jumpto function.
Is there a different way to do this.?
We suggest to learn about environment variable and export command and their scope.
Try modify your test.sh
#!/bin/bash
export var1=hello
sh test2.sh $var1="/var/log"
I have the following code:
...
stage('Some stage') {
sh """
#!/bin/bash
CHECK=$(curl -sI https://somegithuburl.com)
echo $CHECK
"""
}
...
And when the Jenkins job is executed it returns:
+ CHECK=
Do you know how can I save the output in a variable in the same way I would do in a Shell script?
Correct way to pull the output and save as a variable:
export CHECK="$(curl -s https://somegithuburl.com)"
then you can use $CHECK as a variable
try:
export CHECK=`curl -sI https://somegithuburl.com`;
echo $CHECK
I have a curl command that looks like this:
curl -X PUT -H "myheader:coca-cola" -d '{ "name":"harrypotter" }' http://mygoogle.com/service/books/123
Running this command as is via terminal returns the expected results.
I am trying to incorporate this curl command in my bash script as follows:
#!/bin/bash
MYURL=http://mygoogle.com/service/books/123
# Generate body for curl request
generate_put_data()
{
cat <<EOF
{
"name":"harrypotter"
}
EOF
}
put_data=$(echo "$(generate_put_data)")
put_data_with_single_quotes="'$put_data'"
# Generate headers for curl request
header=myheader:coca-cola
header_with_double_quotes="\"$header\""
# The following function takes two inputs - a simple string variable (with no spaces or quotes) and the curl command string
function run_cmd() {
echo $1
echo $2
#Run the curl command
"$2"
#Check return code of the curl command
if [ "$?" -ne 0 ]; then
#do something with simple string variable
echo "$1"
echo "Job failed"
exit 1
else
#do something with simple string variable
echo "$1"
echo "Job Succeeded"
fi
}
# Run the bash function - run_cmd
run_cmd "mysimplestring" "curl -X PUT -H $header_with_double_quotes -d $put_data_with_single_quotes $MYURL"
However, when I try to run the above bash script, it fails at the point where I call run_cmd() function with the two inputs. I get the following error:
curl -X PUT -H "myheader:coca-cola" -d '{
"name":"harrypotter"
}' http://mygoogle.com/service/books/123: No such file or directory
Job failed
This error occurs on the line where "$2" is being executed in the run_cmd() function declaration.
Could someone help me understand where I am going wrong? Thanks!
"$2"
This will take the second argument and try to run it without doing any word splitting. It treats it as one string.
You're going to run into trouble passing in the curl command as one string. You'll do better if you pass it without quotes, just as if you typed it on the command line. You'll want to quote each of the variables but not quote the command as a whole.
run_cmd "mysimplestring" curl -X PUT -H "$header" -d "$put_data" "$MYURL"
Notice that you don't need the "with_quotes" variables any more. You don't have to do anything like that. The original plain values will work.
Now you can access the command using array syntax:
function run_cmd() {
local name=$1; shift
local cmd=("$#")
#Run the curl command
"${cmd[#]}"
}
By the way, this is a useless use of echo:
put_data=$(echo "$(generate_put_data)")
Make that:
put_data=$(generate_put_data)
I want to use the variables of ssh in shell script.
suppose I have some variable a whose value I got inside the ssh and now I want to use that variable outside the ssh in the shell itself, how can I do this ?
ssh my_pc2 <<EOF
<.. do some operations ..>
a=$(ls -lrt | wc -l)
echo \$a
EOF
echo $a
In the above example first echo print 10 inside ssh prints 10 but second echo $a prints nothing.
I would refine the last answer by defining some special syntax for passing the required settings back, e.g. "#SET var=value"
We could put the commands (that we want to run within the ssh session) in a cmdFile file like this:
a=`id`
b=`pwd`
echo "#SET a='$a'"
echo "#SET b='$b'"
And the main script would look like this:
#!/bin/bash
# SSH, run the remote commands, and filter anything they passed back to us
ssh user#host <cmdFile | grep "^#SET " | sed 's/#SET //' >vars.$$
# Source the variable settings that were passed back
. vars.$$
rm -f vars.$$
# Now we have the variables set
echo "a = $a"
echo "b = $b"
If you're doing this for lots of variables, you can add a function to cmdFile, to simplify/encapsulate your special syntax for passing data back:
passvar()
{
var=$1
val=$2
val=${val:-${!var}}
echo "#SET ${var}='${val}'"
}
a=`id`
passvar a
b=`pwd`
passvar b
You might need to play with quotes when the values include whitespace.
A script like this could be used to store all the output from SSH into a variable:
#!/bin/bash
VAR=$(ssh user#host << _EOF
id
_EOF)
echo "VAR=$VAR"
it produces the output:
VAR=uid=1000(user) gid=1000(user) groups=1000(user),4(adm),10(wheel)
I have a bash function i would like to bsub. It is recursively called when i try to source the script, but if i don't source the script it doesn't seem to recognize my function. How do I correctly call besub on a function within the same script file?
my_script(should print "12345"):
#! /bin/sh
function myFunct {
echo $1
}
bsub -q myQueue "source ./my_script; myFunct 12345"
a.bash may look like this
#! /bin/bash
export input=$1
function myFunct {
echo "$input"
}
# This is if you want to call bsub outside the bash
# Use bsub -q Queue `./a.bash 12345`
myFunct "$input"
# Put bsub inside and call the script
# ./a.bash 12345
bsub -q myQueue `myFunct "$input"`
I've gotten it to work with
bsub [...] bash -rcfile my_script.sh -i -c "myFunct 12345"