I am working on a project where I need to check if the employee enter *done* in a text field, though employee enters '* done *' or '*done *' or '* done*' in similar fashion. As you see they are putting trailing and leading blank or both at a time.I have to check the column for all three/four possible entry in like statement, I tried trim,rtrim nothing seems like working.
case when
col like ('*done*')
or col like ('* done*')
or col like ('*done *')
or col like ('* done *')
end as work_status
doesn't seems a smart way to do it. What is the best way to to check this. Any help will be appreciated. Thank you.
Remove spaces:
case when replace(col, ' ') = '*done*' then 'done'
else 'not'
end as work_status
You can look for the done substring with anything preceding and following using the LIKE operator and % wildcards:
CASE WHEN col LIKE '%done%' THEN 'done' END AS work_status
Or you can trim the leading and trailing space characters:
CASE WHEN TRIM(col) = 'done' THEN 'done' END AS work_status
Or you can replace all the leading/trailing white spaces (in case the users have entered new lines, tabs, etc. rather than space characters) using a regular expression:
CASE
WHEN REGEXP_REPLACE(col, '^[[:space:]]+|[[:space:]]+$') = 'done'
THEN 'done'
END AS work_status
fiddle
Related
I need to allow only set of characters i.e.,
a to z A to Z 0 to 9 . !##$% *()_=+|[]{}"'';:?/.,-
but When I add dash(-) character to below query it is not working please help me at earliest.
SELECT :p_string FROM dual
WHERE NOT REGEXP_LIKE (translate(:p_string,chr(10)||chr(11)||chr(13), ' '),'[^]^A-Z^a-z^0-9^[^.^{^}^!^#^#^$^%^*^(^)^_^=^+^|^\^{^}^"^''^;^:^?^/^,^-^ ]' );
[.-.] will work fine on this query .
The extra ^ symbols inside the bracket expression in your pattern are not, as I think you expect, negations; only the first ^ inside the brackets does that.
The main issue that is causing, apart from allowing that actual circumflex symbol to be matched when you didn't seem to want it, is that you end up with ^-^ being treated as a range.
To include a literal - it has to be the first or last thing in the brackets; from the docs:
To specify a right bracket (]) in the bracket expression, place it first in the list (after the initial circumflex (^), if any).
To specify a hyphen in the bracket expression, place it first in the list (after the initial circumflex (^), if any), last in the list, or as an ending range point in a range expression.
So as you need to do both, make the hyphen last; you can change your pattern to:
'[^]A-Za-z0-9[.{}!##$%*()_=+|\{}"'';:?/, -]'
You could also skip the tralsnate step by including those special characters in the pattern too:
'[^]A-Za-z0-9[.{}!##$%*()_=+|\{}"'';:?/, '||chr(10)||chr(11)||chr(13)||'-]'
Looks like you need to permit only (7-bit) ASCII characters with exception of ~ and ^
In this case I would try it like this:
WHERE CONVERT(p_string, 'US7ASCII') = p_string
AND NOT REGEXP_LIKE(p_string, '~|\^')
Instead of CONVERT(p_string, 'US7ASCII') = p_string you can also use ASCIISTR(REPLACE(p_string, '\', '/')) = REPLACE(p_string, '\', '/')
I have query in my project and that is having REGEXP_REPLACE
i tried to find how it works by searching but i found it like
w+ Matches a word character (that is, an alphanumeric or underscore
(_) character).
but not able to find '"\w+\":' why these "" are used and what is mean by '{|}|"',''
UPDATE (SELECT data,data_value FROM TEMP) t
SET t.DATA_VALUE=REGEXP_REPLACE(REGEXP_REPLACE(t.data, '"\w+\":',''),'{|}|"','');
can you please tell me how it works?
This appear to be a regular expression for stripping keys and enclosing brackets from a JSON string - unfortunately, if this is the case then it does not work in all situations.
The regular expression
'"\w+\":'
will match:
A " double quotation mark;
\w+ one-or-more word (a-z or A-Z or 0-9 or _) characters;
\" another double quotation mark - note: the \ character is not necessary; then
A : colon.
So:
REGEXP_REPLACE(
'{"key":"value","key2":"value with \"quote"}',
'"\w+":', -- Pattern matched
'' -- Replacement string
)
Will output:
{"value","value with \"quote"}
The second pattern {|}|" will match either a {, or a } or a " character (and could have been equivalently written as [{}"]) so:
REGEXP_REPLACE(
'{"value","value with \"quote"}',
'{|}|"', -- Pattern matched
'' -- Replacement string
)
Will output:
value,value with \quote
Which is fine, until (like my example) you have an escaped double quote (or curly braces) in the value string; in which case those will also get stripped leaving the escape character.
(Note: you would not typically find this but it is possible to include escaped quotes in the key. So {"keywith\":quote":"value"} would get replaced to {quote":"value"} and then quote:value which is not the intended output.)
If parsing JSON is what you are trying to do (pre-Oracle 12) then you can use:
REGEXP_REPLACE(
'{"key":"value","key2":"value with \"quote","keywith\":quote":"value with \"{}"}',
'^{|"(\\"|[^"])+":(")?((\\"|[^"])+?)\2((,)|})',
'\3\6'
)
Which outputs:
value,value with \"quote,value with \"{}
Or in Oracle 12 you can do:
SELECT *
FROM JSON_TABLE(
'{"key":"value","key2":"value with \"quote","keywith\":quote":"value with \"{}"}',
'$.*' NULL ON ERROR
COLUMNS (
value VARCHAR2(4000) PATH '$'
)
)
Which outputs:
VALUE
-----------------
value
value with "quote
value with "{}
example:::REGEXP_REPLACE( string, pattern [, replacement_string [, start_position [, nth_appearance [, match_parameter ] ] ] ] )
| is or(CAN MEAN MORE THAN ONE ALTERNATIVE ) , is for at least as in {n,} at least n times
https://www.techonthenet.com/oracle/functions/regexp_replace.php
"where I got my info"
'"\w+\":' why these "" are used and what is mean by '{|}|"',''
Matches a word character(\w)One or more times(+) this has to be messed up it's missing the right quantity of close parentheses by putting \" w+ \"
they allow the " to be shown. This expression takes one expression changes it then uses that as the basis for the next change. Good luck figuring the rest out. Regular expressions aren't too bad, pretty intuitive once you get the basics down.
I have a query like this:
INSERT INTO TAB_AUTOCRCMTREQUESTS
(RequestOrigin, RequestKey, CommentText) VALUES ('Tracker', 'OPM03865_0', '[Orange.Security.OrangePrincipal]
em[u02650791]okok
it's friday!')
As expected it is throwing an error of missing comma, due to this it's friday! which has a single quote.
I want to remove this single quote while inserting using Replace function.
How can this be done?
Reason for error is because of the single Quote. In order to correct it, you shall not remove the single quote instead you need to add one more i.e. you need to make it's friday to it''s friday while inserting.
If you need to replace it for sure, then try the below code :
insert into Blagh values(REPLACE('it''s friday', '''', ''),12);
I would suggest using Oracle q quote.
Example:
INSERT INTO TAB_AUTOCRCMTREQUESTS (RequestOrigin, RequestKey, CommentText)
VALUES ('Tracker', 'OPM03865_0',
q'{[Orange.Security.OrangePrincipal] em[u02650791]okok it's friday!}')
You can read about q quote here.
To shorten this article you will follow this format: q'{your string here}' where "{" represents the starting delimiter, and "}" represents the ending delimiter. Oracle automatically recognizes "paired" delimiters, such as [], {}, (), and <>. If you want to use some other character as your start delimiter and it doesn't have a "natural" partner for termination, you must use the same character for start and end delimiters.
Obviously you can't user [] delimiters because you have this in your queries. I sugest using {} delimiters.
Of course you can use double qoute in it it''s with replace. You can omit last parameter in replace because it isn't mandatory and without it it automatically will remove ' character.
INSERT INTO TAB_AUTOCRCMTREQUESTS (CommentText) VALUES (REPLACE('...it''s friday!', ''''))
Single quotes are escaped by doubling them up
INSERT INTO Blagh VALUES(REPLACE('it''s friday', '''', ''),12);
You can try this, (sorry but I don't know why q'[ ] works)
INSERT INTO TAB_AUTOCRCMTREQUESTS
(RequestOrigin, RequestKey, CommentText) VALUES ('Tracker', 'OPM03865_0', q'[[Orange.Security.OrangePrincipal] em[u02650791]okok it's friday!]')
I just got the q'[] from this link Oracle pl-sql escape character (for a " ' ") - this question could be a possible duplicate
In Oracle I want to check whether the string has "=' sign at the end. could you please let me know how to check it. If it has '=' sign at the end of string, I need to trailing that '=' sign.
for eg,
varStr VARCHAR2(20);
varStr = 'abcdef='; --needs to trailing '=' sign
I don't think you need "pattern matching" here. Just check if the last character is the =
where substr(varstr, -1, 1) = '='
substr when called with a negative position will work from the end of the string, so substr(varstr,-1,1) extracts the last character of the given string.
Use the REGEX_EXP function. I'm putting a sql command since you didn't specify on your question.:
select *
from someTable
where regexp_like( someField, '=$' );
The pattern $ means that the precedent character should be at the end of the string.
see it here on sql fiddle: http://sqlfiddle.com/#!4/d8afd/3
It seems that substr is the way to go, at lease with my sample data of about 400K address lines this returns 1043 entries that end in 'r' in an average of 0.2 seconds.
select count(*) from addrline where substr(text, -1, 1) = 'r';
On the other hand, the following returns the same results but takes 1.1 seconds.
select count(*) from addrline where regexp_like(text, 'r$' );
My regex captures quoted phrases:
"([^"]*)"
I want to improve it, by ignoring quotes, which are followed by ', -' (a comma, a space and a dash in this particular order).
How do I do this?
The test: http://rubular.com/r/xls6vN1w92
This should do it, using a Negative Lookahead:
"(?!, -)([^"]*)"(?!, -)
A little icky, but it works. You want to make sure either quote isn't followed by your string, or else the match will start at the closing quotes.
http://rubular.com/r/yFMyUKJOHL
Regex
"(.*?)"(?!, -)
Working Example
http://rubular.com/r/9kOmZLxLfy
This is unparsable in your context, its open ended. The only way to parse it is to consume the not's as well as the want's, but its still an invalid premise.
/"([^"]*?)"(?!, -)|"[^"]*?"(?=, -)/
Then check for capture group 1 on each match, something like this:
$rx = qr/"([^"]*?)"(?!, -)|"[^"]*?"(?=, -)/;
while (' "ingnore me", - "but not me" ' =~ /$rx/g) {
print "'$1'\n" if defined $1
}
Add (?!...) at the end of the regex:
"([^"\n]*)"(?!, -)