Failed to create bean - spring

Question

I tried to run the following test code:
package guru.springframework.test.external.props;
import guru.springframework.test.jms.FakeJmsBroker;
import guru.test.config.external.props.ExternalPropsEnvironment;
import org.junit.Test;
import org.junit.runner.RunWith;
import org.springframework.beans.factory.annotation.Autowired;
import org.springframework.test.context.ContextConfiguration;
import org.springframework.test.context.junit4.SpringJUnit4ClassRunner;
import static org.junit.Assert.assertEquals;
/**
* Created by jt on 5/7/16.
*/
#RunWith(SpringJUnit4ClassRunner.class)
#ContextConfiguration(classes = ExternalPropsEnvironment.class)
public class PropertySourceEnvTest {
#Autowired
FakeJmsBroker fakeJmsBroker;
#Test
public void testPropsSet() throws Exception {
assertEquals("10.10.10.123", fakeJmsBroker.getUrl());
assertEquals(3330, fakeJmsBroker.getPort().intValue());
assertEquals("Ron", fakeJmsBroker.getUser());
assertEquals("Burgundy", fakeJmsBroker.getPassword());
}
}
Not sure why I am getting this error:
Caused by: org.springframework.beans.factory.BeanCreationException: Could not autowire field: guru.springframework.test.jms.FakeJmsBroker guru.springframework.test.external.props.PropertySourceEnvTest.fakeJmsBroker; nested exception is org.springframework.beans.factory.NoSuchBeanDefinitionException: No qualifying bean of type [guru.springframework.test.jms.FakeJmsBroker] found for dependency: expected at least 1 bean which qualifies as autowire candidate for this dependency. Dependency annotations: {#org.springframework.beans.factory.annotation.Autowired(required=true)}
FakeJmsBroker.java:
package guru.springframework.test.jms;
/**
* Created by jt on 5/7/16.
*/
public class FakeJmsBroker {
private String url;
private Integer port;
private String user;
private String password;
public String getUrl() {
return url;
}
public void setUrl(String url) {
this.url = url;
}
public Integer getPort() {
return port;
}
public void setPort(Integer port) {
this.port = port;
}
public String getUser() {
return user;
}
public void setUser(String user) {
this.user = user;
}
public String getPassword() {
return password;
}
public void setPassword(String password) {
this.password = password;
}
}

Answer 1

In this instance, FakeJmsBroker is just a POJO. Unless you either annotate it as #Component, #Service, etc, then Spring knows nothing about it.
You can also return a new instance of this as a #Bean in a #Configuration class. However, looking at this class, unless it's holding properties, it doesn't make sense as a component as it doesn't contain any behavior. Here's an example of making it a bean from a configuration.
#Configuration
public class MyConfig {
// This will create an instance of FakeJmsBroker that will be in the Spring context
#Bean
public FakeJmsBroker createFakeBroker() {
return new FakeJmsBroker();
}
}
Either that class/method, or using the annotation-driven approach will make this bean eligible for autowiring.