How to set gin use release mode in the main function? [duplicate] - go

Question

This question already has answers here:
How to set gin mode to release mode?
(5 answers)
Closed 12 days ago.
I know to use gin.SetMode(gin.ReleaseMode), but as far as I've tried, it only seems to work in init()
How do I do?
Here is my code:
func (m *HttpSrv) Start() (err error) {
m.mtx.Lock()
defer m.mtx.Unlock()
if m.isStarted {
return errors.New("server is started")
}
if m.router == nil {
return errors.New("router unregister")
}
//gin setting
gin.ForceConsoleColor()
if !config.IsDebugModeOn() {
gin.SetMode(gin.ReleaseMode) //didn't work
}
m.srv = &http.Server{
Addr: ":" + m.port,
Handler: m.router,
ReadTimeout: 10 * time.Second,
WriteTimeout: 10 * time.Second,
}
m.isStarted = true
go func() {
if err = m.srv.ListenAndServe(); err != nil {
if err == http.ErrServerClosed {
m.isStarted = false
return
}
}
m.isStarted = false
}()
time.Sleep(10 * time.Millisecond)
return err
}

Answer 1

You've to set the gin.SetMode(gin.ReleaseMode) before invoking the gin.New() or gin.Default. Please check the below example:
package main
import "github.com/gin-gonic/gin"
func main() {
gin.SetMode(gin.ReleaseMode)
r := gin.Default()
r.GET("/ping", func(ctx *gin.Context) {
ctx.JSON(200, gin.H{
"message": "pong",
})
})
r.Run()
}
If you're gonna to invoke the gin.Default() function prior to the gin.SetMode(), this won't work.
Let me know if this helps, thanks!