For-Loop strange issue - bash

Question

Please see below outputs, it looks like the first line isn't working for the first file only - but is for the others, any ideas?
#!/bin/sh
cpuser=$1
cd "/home/$cpuser/public_html"
wpconfigs=($(find . -name "wp-config.php"))
for i in "${wpconfigs[#]}";
do
cpuser=$cpuser
wpdb=$(grep -e "DB_NAME" $i | cut -d \' -f 4)
wpuser=$(grep -e "DB_USER" $i | cut -d \' -f 4)
wppass=$(grep -e "DB_PASS" $i | cut -d \' -f 4)
set -x uapi --output=jsonpretty --user="$cpuser" Mysql create_user name="${wpuser}" password="${wppass}";
sleep 2s;
set -x uapi --output=jsonpretty --user="$cpuser" Mysql set_privileges_on_database user="${wpuser}" database="${wpdb}" privileges="ALL PRIVILEGES";
sleep 2s;
set -x uapi --output=jsonpretty --user="$cpuser" Mysql set_password user="${wpuser}" password="${wppass}";
sleep 2s;
done
When I look at the output run set -x to debug I see the following;
[root#cpanel201 ~]# sh ./testing.sh qv5goe35p3783sz8
+ sleep 2s
+ set -x uapi --output=jsonpretty --user=qv5goe35p3783sz8 Mysql set_privileges_on_database 'user=qv5goe35p3783sz8_yscr_bbS$L5' database=qv5goe35p3783sz8_blog 'privileges=ALLPRIVILEGES'
+ sleep 2s
+ set -x uapi --output=jsonpretty --user=qv5goe35p3783sz8 Mysql set_password 'user=qv5goe35p3783sz8_yscr_bbS$L5' password=FhtH6UztIuoS0_
+ sleep 2s
+ for i in "${wpconfigs[#]}"
+ cpuser=qv5goe35p3783sz8
++ grep -e DB_NAME ./wordpress/wp-config.php
++ cut -d \' -f 4
+ wpdb=qv5goe35p3783sz8_wordpress
++ grep -e DB_USER ./wordpress/wp-config.php
++ cut -d \' -f 4
+ wpuser=qv5goe35p3783sz8_yscr_bb5X8h
++ grep -e DB_PASS ./wordpress/wp-config.php
++ cut -d \' -f 4
+ wppass=X7lyC17Td8tH3cm
+ set -x uapi --output=jsonpretty --user=qv5goe35p3783sz8 Mysql create_user name=qv5goe35p3783sz8_yscr_bb5X8h password=X7lyC17Td8tH3cm
+ sleep 2s
+ set -x uapi --output=jsonpretty --user=qv5goe35p3783sz8 Mysql set_privileges_on_database user=qv5goe35p3783sz8_yscr_bb5X8h database=qv5goe35p3783sz8_wordpress 'privileges=ALL PRIVILEGES'
+ sleep 2s
+ set -x uapi --output=jsonpretty --user=qv5goe35p3783sz8 Mysql set_password user=qv5goe35p3783sz8_yscr_bb5X8h password=X7lyC17Td8tH3cm
+ sleep 2s
+ for i in "${wpconfigs[#]}"
+ cpuser=qv5goe35p3783sz8
++ grep -e DB_NAME ./newsite/wp-config.php
++ cut -d \' -f 4
+ wpdb=qv5goe35p3783sz8_newsite
++ grep -e DB_USER ./newsite/wp-config.php
++ cut -d \' -f 4
+ wpuser=qv5goe35p3783sz8_yscr_bbxQiN
++ grep -e DB_PASS ./newsite/wp-config.php
++ cut -d \' -f 4
+ wppass=XpMa4v5z54tcM
+ set -x uapi --output=jsonpretty --user=qv5goe35p3783sz8 Mysql create_user name=qv5goe35p3783sz8_yscr_bbxQiN password=XpMa4v5z54tcM
+ sleep 2s
+ set -x uapi --output=jsonpretty --user=qv5goe35p3783sz8 Mysql set_privileges_on_database user=qv5goe35p3783sz8_yscr_bbxQiN database=qv5goe35p3783sz8_newsite 'privileges=ALL PRIVILEGES'
+ sleep 2s
+ set -x uapi --output=jsonpretty --user=qv5goe35p3783sz8 Mysql set_password user=qv5goe35p3783sz8_yscr_bbxQiN password=XpMa4v5z54tcM
+ sleep 2s
If you look at the outputs for the second + third set of files you'll see three uapi commands, however, for the first we only see two and no outputs in terms of the greps it is doing on the top file.
For your reference, cpuser is set on the command line (the value after sh ./testing.sh)
I've also noticed that in the top file, the user appears to get surrounded by 's however the other two don't.
For clarity what the script is doing here;
Scraping any wp configs for a sql db name, db user and db password
Passing the user name and password to a cpanel api to create the user in a cPanel instance
The action works on config files 2 and 3 in this instance, but, not with the initial one - you will see the first create_user is missing even on the set -x
**
UPDATE
Having reviewed the logs, I believe this may be due to the fact that the user on the first one has a $ within it - could this be why? I have noticed that only on this one also, the command gets quoted within ''s which is incorrect for uapi. If this may be why, how do I resolve that?
'user=qv5goe35p3783sz8_yscr_bbS$L5'
How do I escape the $, as I think that's what is causing the issue in this case - all others are okay, only where a $ is within the username does this issue occur

Answer 1

The follow code tells it all:
$ set -x ls
$ ls
+ ls
a.out
As far as I know in all shells the 'ls' behind 'set -x' is ignored. By the next '$ ls' and '+ ls' you can see that 'set -x' is executed.
The normal way to do this, and probably what you want, is:
$ set -x
$ ls
+ ls
a.out
$ set -
+ set -
Or as a one liner:
$ set -x ; ls ; set -
+ ls
a.out
+ set -
By the previous you can also see why the line is missing in your output 'set -x' just enables shell tracing for the next command, where 'set -' ends it also for the next command.