Ruby Hash difference in 1.8.7 and 1.9.2 - ruby

Given the following script, I see a different output using Ruby 1.8.7 and Ruby 1.9.2. My question is, what has changed in Ruby hashes that enforces this particular behavior?
def to_params(_hash)
params = ''
stack = []
_hash.each do |k, v|
if v.is_a?(Hash)
stack << [k,v]
else
#v = v.first if v.is_a?(Array)
params << "#{k}=#{v}&"
end
end
stack.each do |parent, hash|
hash.each do |k, v|
if v.is_a?(Hash)
stack << ["#{parent}[#{k}]", v]
else
params << "#{parent}[#{k}]=#{v}&"
end
end
end
params.chop! # trailing &
params
end
q = {"some_key"=>["some_val"], "another_key"=>["another_val"]}
n = convert_params(q)
puts n
Ruby 1.8.7 output:
some_key=some_val&another_key=another_val
Ruby 1.9.2 output:
some_key=["some_val"]&another_key=["another_val"]
1.9.2 retains the "Array" type of the value whereas 1.8.7 changes the type to string implicitly.

Two things have changed (the latter being your observation):
Hashes are ordered now
array.to_s used to return array.join, now it returns array.inspect (see 1.8.7 and 1.9.2).

Related

mRuby 3.0.0 vs 3.1.0: different behavior

The code:
class XHash
attr_accessor :value
def method_missing(mid, *args)
puts [["XHash::method_missing called", mid, args]]
self.value.send mid, *args
end
end
class Hash
def method_missing(mid, *args)
puts [["Hash::method_missing called", mid, args]]
str = mid.to_s
if str[-1] == '='
str = str[0, str.length - 1];
self[str]=args[0]
else
self[str]
end
end
end
v = XHash.new
v.value = Hash.new
puts [["Before: ", v.value]]
v.SomeKey = "SomeValue"
puts [["After: ", v.value]]
mRuby 3.0.0 output (expected):
[["Before: ", {}]]
[["XHash::method_missing called", :"SomeKey=", ["SomeValue"]]]
[["Hash::method_missing called", :"SomeKey=", ["SomeValue"]]]
[["After: ", {"SomeKey"=>"SomeValue"}]]
mRuby 3.1.0 output:
[["Before: ", {}]]
[["XHash::method_missing called", :"SomeKey=", ["SomeValue"]]]
[["Hash::method_missing called", :"SomeKey=", [nil]]]
[["After: ", {"SomeKey"=>nil}]]
Am I doing something illegal, or is it a bug? If it is already fixed, then what stable revision should I pick for the release of my project, so I don't storm users with bugfixes afterwards? I'm upgrading from mRuby 3.0.0 to 3.1.0, but it breaks .rb code in my gems.
PS: custom puts is used in my gem, so it behaves the same in both versions.

How to recursively convert keys of Ruby Hashes that are symbols to String

Suppose I have following hash or nested hash:
h = { :a1 => { :b1 => "c1" },
:a2 => { :b2 => "c2"},
:a3 => { :b3 => "c3"} }
I want to create a method that takes hash as a parameter and recursively convert all the keys (keys that are symbol eg. :a1) to String (eg. "a1"). So far I have come up with the following method which doesn't work and returns {"a1"=>{:b1=>"c1"}, "a2"=>{:b2=>"c2"}, "a3"=>{:b3=>"c3"}}.:
def stringify_all_keys(hash)
stringified_hash = {}
hash.each do |k, v|
stringified_hash[k.to_s] = v
if v.class == Hash
stringify_all_keys(stringified_hash[k.to_s])
end
end
stringified_hash
end
What am I doing wrong and how do a get all the keys converted to string like this:
{"a1"=>{"b1"=>"c1"}, "a2"=>{"b2"=>"c2"}, "a3"=>{"b3"=>"c3"}}
If you are using ActiveSupport already or are open to using it, then deep_stringify_keys is what you're looking for.
hash = { person: { name: 'Rob', age: '28' } }
hash.deep_stringify_keys
# => {"person"=>{"name"=>"Rob", "age"=>"28"}}
Quick'n'dirty if your values are basic objects like strings, numbers, etc:
require 'json'
JSON.parse(JSON.dump(hash))
Didn't test this, but looks about right:
def stringify_all_keys(hash)
stringified_hash = {}
hash.each do |k, v|
stringified_hash[k.to_s] = v.is_a?(Hash) ? stringify_all_keys(v) : v
end
stringified_hash
end
using plain ruby code, the below code could help.
you can monkey patched it to the ruby Hash, to use it like this my_hash.deeply_stringfy_keys
however, I do not recommend monkey batching ruby.
you can adjust the method to provide the deeply_strigify_keys! (bang) version of it.
in case you want to make a different method witch does not stringify recursively, or to control the level of stringifying then consider re-writing the below method logic so you can have it written better with considering the other variation mentioned above.
def deeply_stringify_keys(hash)
stringified_hash = {}
hash.each do |k, v|
if v.is_a?(Hash)
stringified_hash[k.to_s] = deeply_stringify_keys(v)
elsif v.is_a?(Array)
stringified_hash[k.to_s] = v.map {|i| i.is_a?(Hash)? deeply_stringify_keys(i) : i}
else
stringified_hash[k.to_s] = v
end
end
stringified_hash
end

Ruby search for super nested key from json response

I have a terribly nested Json response.
[[{:test=>[{:id=>1, :b=>{id: '2'}}]}]]
There's more arrays than that but you get the idea.
Is there a way to recursively search through and find all the items that have a key I need?
I tried using this function extract_list() but it doesn't handle arrays well.
def nested_find(obj, needed_keys)
return {} unless obj.is_a?(Array) || obj.is_a?(Hash)
obj.inject({}) do |hash, val|
if val.is_a?(Hash) && (tmp = needed_keys & val.keys).length > 0
tmp.each { |key| hash[key] = val[key] }
elsif val.is_a?(Array)
hash.merge!(obj.map { |v| nested_find(v, needed_keys) }.reduce(:merge))
end
hash
end
end
Example
needed_keys = [:id, :another_key]
nested_find([ ['test', [{id:1}], [[another_key: 5]]]], needed_keys)
# {:id=>1, :another_key=>5}
The following is not what I'd suggest, but just to give a brief alternative to the other solutions provided:
2.1.1 :001 > obj = [[{:test=>[{:id=>1, :b=>{id: '2'}}]}]]
=> [[{:test=>[{:id=>1, :b=>{:id=>"2"}}]}]]
2.1.1 :002 > key = :id
=> :id
2.1.1 :003 > obj.inspect.scan(/#{key.inspect}=>([^,}]*)[,}]/).flatten.map {|s| eval s}
=> [1, "2"]
Note: use of eval here is just for an example. It would fail/produce incorrect results on anything whose inspect value was not eval-able back to the same instance, and it can execute malicious code:
You'll need to write your own recursive handler. Assuming that you've already converted your JSON to a Ruby data structure (via JSON.load or whatnot):
def deep_find_value_with_key(data, desired_key)
case data
when Array
data.each do |value|
if found = deep_find_value_with_key value, desired_key
return found
end
end
when Hash
if data.key?(desired_key)
data[desired_key]
else
data.each do |key, val|
if found = deep_find_value_with_key(val, desired_key)
return found
end
end
end
end
return nil
end
The general idea is that given a data structure, you check it for the key (if it's a hash) and return the matching value if found. Otherwise, you iterate it (if it's an Array or Hash) and perform the same check on each of it's children.
This will find the value for the first occurrence of the given key, or nil if the key doesn't exist in the tree. If you need to find all instances then it's slightly different - you basically need to pass an array that will accumulate the values:
def deep_find_value_with_key(data, desired_key, hits = [])
case data
when Array
data.each do |value|
deep_find_value_with_key value, desired_key, hits
end
when Hash
if data.key?(desired_key)
hits << data[desired_key]
else
data.each do |key, val|
deep_find_value_with_key(val, desired_key)
end
end
end
return hits
end

Ruby: how to iterate over an array of hash items?

irb> pp config
[{"file"=>"/var/tmp"},
{"size"=>"1024"},
{"modified"=>"03/28/2012"}]
=> nil
In the code,
config.each do |d|
# then how to break d into (k, v)???
end
config.each do |items|
items.each do |key, value|
# e.g. key="file", value="/var/tmp", etc.
end
end
Just do
config.each do |hash|
(k,v),_ = *hash
end
Inspired by #Arup's answer, here's a solution that doesn't require a extra, unused variable in the parallel assignment:
config.each do |hash|
key, value = hash.to_a[0]
end
to_a converts the hash into the same kind of array that you would get by using splat *hash, but you can actually index the first element of the array (i.e. the first key/value pair) with [0] this way, while trying to do so with splat (*hash) generates a syntax error (at least in Ruby version 2.1.1):
>> k,v = (*hash)[0]
SyntaxError: (irb):4: syntax error, unexpected ')', expecting '='
k,v = (*x)[0]
^
from c:/RailsInstaller/Ruby1.9.3/bin/irb:12:in `<main>'
>>
Of course, depending on what you're going to do with the key and value variables, it might make your code shorter and more readable to use one of these standard block constructs:
config.each do |hash|
hash.each { |key,value| puts "#{key}: #{value}" }
end
# or
config.each do |hash|
hash.each do |key,value|
puts "#{key}: #{value}"
end
end

Make an array in Ruby

I am very beginner in Ruby and probably the question is too easy but well, I've already spent some time on it and couldn't find a solution.
My Ruby script takes a number (ex 10) and a name (ex Vincent). What I want is to make an array looking like
Vincent0
Vincent1..
Vincent9
I can't figure a way to make it..
def arrayfy(string, number)
arr = []
0.upto(number-1) do |i|
arr << "#{string}#{i}"
end
return arr
end
Update: To add these as variables to the class
class Foo
def arrayfy(string, number)
0.upto(number-1) do |i|
var_string = "##{string}#{i}"
var_symbol = var_string.to_sym
self.instance_variable_set(var_symbol, "")
end
end
end
Array.new(10) {|i| "Vincent#{i}"}
gives you
["Vincent0", "Vincent1", "Vincent2", "Vincent3", "Vincent4", "Vincent5",
"Vincent6", "Vincent7", "Vincent8", "Vincent9"]
The documentation for Array is available at http://www.ruby-doc.org/core/classes/Array.html (googling for Array RDoc will give you the URL).
The bit in the braces ({|i| "Vincent#{i}"}) is called a block. You'll definitely want to learn about them.
Using Array.new with a block (docs):
def create_array(count, name)
Array.new(10) { |i| "#{name}#{i} }
end
Using Enumerable#reduce (docs):
def create_array(count, name)
(0...count).reduce([]) { |m,i| m << "#{name}#{i}" }
end
Or using Enumerable#each_with_object (docs):
def create_array(count, name)
(0...count).each_with_object([]) { |i,a| a << "#{name}#{i}" }
end
Using it:
# Using the array (assigning to variables)
array = create_array(10, 'Vincent') # => ['Vincent0', 'Vincent1', 'Vincent2' ...]
name = array[1] # => 'Vincent1'
Just for the record, a solution in a more functional style:
>> def arrayify(str, n)
.. ([str] * n).zip(0...n).map(&:join)
.. end
#=> nil
>> arrayify('Vincent', 10)
#=> ["Vincent0", "Vincent1", "Vincent2", "Vincent3", "Vincent4", "Vincent5", "Vincent6", "Vincent7", "Vincent8", "Vincent9"]
def array_maker(number, string)
result = []
for i in 0..number do
result << "#{string}#{i}"
end
result
end

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