MVC 3 Error for Navigating between Models in View - asp.net-mvc-3

Question

I've been stuck in this issue for the whole afternoon, appreciate if anyone can tell me how, Thanks!
I am using MVC 3 and setup two models:
public class Employee
{
[Key]
public virtual int Id { get; set; }
public virtual string Emp_Id { get; set; }
public virtual string Emp_Name { get; set; }
public virtual int Emp_Type { get; set; }
public virtual ICollection<Job> Jobs { get; set; }
}
public class Job
{
[Key]
public virtual int Id { get; set; }
public virtual string SO { get; set; }
public virtual int? Manhour_Type { get; set; }
public virtual DateTime? StartJob { get; set; }
public virtual DateTime? EndJob { get; set; }
public virtual double? Duration { get; set; }
public virtual Employee employee { get; set; }
}
Two databases are generated by this code:
public class JMCDB : DbContext
{
public DbSet<Employee> Employees { get; set; }
public DbSet<Job> Jobs { get; set; }
protected override void OnModelCreating(DbModelBuilder modelBuilder)
{
modelBuilder.Entity<Job>().HasRequired(j => j.employee).WithMany(e => e.Jobs);
}
}
I Create the JobController as follows:
public class JobController : Controller
{
//
// GET: /Job/
JMCDB _db = new JMCDB();
public ActionResult Index()
{
var job = _db.Jobs;
return View(job);
}
}
In "View", I wanna see the employee name of this specific job:
#foreach (var item in Model) {
<tr>
<td>
#Html.DisplayFor(modelItem => item.SO)
</td>
<td>
#Html.DisplayFor(modelItem => item.Manhour_Type)
</td>
<td>
#Html.DisplayFor(modelItem => item.StartJob)
</td>
<td>
#Html.DisplayFor(modelItem => item.EndJob)
</td>
<td>
#Html.DisplayFor(modelItem => item.employee.Emp_Name)
</td>
<td>
</td>
</tr>
}
But when I run the program, there is an error for the last line of code
"#Html.DisplayFor(modelItem => item.employee.Emp_Name)"
I don't know how to solve, Thanks if anyone can tell me how.

Answer 1

You can use the Include method to eager load the navigational property employee
public ActionResult Index()
{
var job = _db.Jobs.Include(job => job.employee);
return View(job);
}