Schema building with foreign keys - laravel-4

I was wondering if someone could show me how to write the following SQL in Laravel 4Schema Builder`?
CREATE TABLE `conversation_reply` (
`cr_id` int(11) NOT NULL PRIMARY KEY AUTO_INCREMENT,
`reply` text,
`user_id_fk` int(11) NOT NULL,
`ip` varchar(30) NOT NULL,
`time` int(11) NOT NULL,
`c_id_fk` int(11) NOT NULL,
FOREIGN KEY (user_id_fk) REFERENCES users(user_id),
FOREIGN KEY (c_id_fk) REFERENCES conversation(c_id)
);

If I understand what you're asking, this should be close;
Schema::table('conversation_reply', function($table)
{
$table->increments('cr_id');
$table->text('reply')->nullable();
$table->foreign('user_id_fk')->references('user_id')->on('users');
$table->string('ip', 30);
$table->integer('time');
$table->foreign('c_id_fk')->references('c_id')->on('conversation');
});

Do Following:
Below Schema will go inside schema-migrations file under public function up()
//Create ** category table **
Schema:Create ('category',function ($table)){
//Relation: category table id used as FK -> to -> product table category_id
$table->increments('category_id');
//category name
$table->string('category_name',40)->unique();
//time staps: created,Updated
$table->timestamps();
}
Than,Inside product schema:
//Create ** product table **
Schema::create('products', function ($table){
//product id
$table->increments('product_id');
//product name
$table->string('p_name')->unique();
//product description
$table->text('p_description');
//created_at and updated_at column
$table->timestamps();
//Foregine Key
$table->integer('category_id_fk')->unsigned();
//Foreign Key link to category table
$table->foreign('category_id_fk')->references('category_id')->on('category');
}

Related

Laravel Polymorphic Relationship - Many to Many issue

Have students, that can have documents.
Documents can either be 'just documents' that belong to students (normal one to many relationship)
However, Students can also have 'passports' and 'visas' (amongst others). Each passport and visa can have a document too. A single document can belong to many things (eg, one document can be associated with a passport and a visa). For the purpose of this troubleshooting, lets keep it simple and between Student / Passport (I've also left out other class stuff like fillable just to keep this brief).
Student Model:
class Student extends Model
{
public function documents() {
return $this->hasMany('App\StudentDocument');
}
public function visas() {
return $this->hasMany('App\StudentVisa');
}
public function passports() {
return $this->hasMany('App\StudentPassport');
}
}
Student Passport Class
class StudentPassport extends Model
{
public function student_documents()
{
return $this->morphToMany(StudentDocument::class, 'student_documentable');
}
}
Student Passport Store:
public function store(StudentPassportRequest $request, $student_id)
{
$student = Student::findOrFail($student_id);
$passport = $student->passports()->create($request->all());
if ($request->file('student_document_file')->isValid()) {
$uploaded_file = $request->file('student_document_file');
$filename = time().'-'.$uploaded_file->getClientOriginalName();
Storage::disk('local')->putFileAs(
'student_document_files/'. \Auth::user()->userable_id .'/'. $student_id .'/',
$uploaded_file,
$filename
);
$student_document = new StudentDocument;
$student_document->filename = $filename;
$student_document->student_document_type_id = StudentDocumentType::where('student_document_type','Passport')->first()->id;
$student_document->original_filename = $uploaded_file->getClientOriginalName();
$student_document->mime = $uploaded_file->getMimeType();
$student_document->student_id=$student_id;
$passport->student_documents()->save($student_document);
}
return redirect('/baadmin/students/'. $student_id .'#kt_tabs-passports')->with('flash_message', ['success','Created Successfully','Student Passport "'. $request->input('passport_number') .'" created successfully!']);
}
Error:
SQLSTATE[42S02]: Base table or view not found: 1146 Table 'student_documentables' doesn't exist
INSERT INTO `student_documentables` (
`student_document_id`,
`student_documentable_id`,
`student_documentable_type`
)
VALUES
(5, 503, App \ StudentPassport)
I took the example as found in the Laravel Documentation here and just renamed 'tag' to student_documents' essentially. The student_documentable table doesnt exist of course, as it should be plugging it into the student_documents table.
Schema:
CREATE TABLE `student_documents` (
`id` bigint(20) unsigned NOT NULL AUTO_INCREMENT,
`student_id` bigint(20) unsigned NOT NULL,
`student_document_type_id` bigint(20) unsigned NOT NULL,
`filename` varchar(191) COLLATE utf8mb4_unicode_ci NOT NULL,
`mime` varchar(191) COLLATE utf8mb4_unicode_ci NOT NULL,
`original_filename` varchar(191) COLLATE utf8mb4_unicode_ci NOT NULL,
`created_at` timestamp NULL DEFAULT NULL,
`updated_at` timestamp NULL DEFAULT NULL,
`deleted_at` timestamp NULL DEFAULT NULL,
`primary_date` datetime NOT NULL DEFAULT current_timestamp(),
`secondary_date` datetime DEFAULT NULL,
`student_documentable_id` bigint(20) DEFAULT NULL,
`student_documentable_type` varchar(191) COLLATE utf8mb4_unicode_ci DEFAULT NULL,
PRIMARY KEY (`id`),
KEY `student_id_index` (`student_id`),
KEY `student_document_type_id_index` (`student_document_type_id`),
KEY `student_documentable_id_index` (`student_documentable_id`)
) ENGINE=MyISAM AUTO_INCREMENT=6 DEFAULT CHARSET=utf8mb4 COLLATE=utf8mb4_unicode_ci;
What am I doing wrong or is Laravel just not understanding 'student_documents'?
I can of course change the Student Passport Class to not plug into 'student_documentable' and use 'student_document' then it would try put in the data to the correct table, but I dont know if this is right since all documentation refers to adding an 'able' at the end...
You should first create a pivot table for that MorphMany relation,
Schema::create('student_documentables', function (Blueprint $table)
{
// optional depends if you want an id or not
$table->id();
// here singular is used, to generate student_documentable_type and student_documentable_id fields
$table->morphs('student_documentable');
// the foreign key to student_document
$table->unsignedInteger('student_document_id');
$table->foreign('student_document_id')->on('student_documents')->references('id')->onUpdate('cascade')->onDelete('cascade');
});
In your StudentDocument :
// we define a relation to retrieve all documentables like passport that are linked to that document
public function student_documentables()
{
return $this->morphTo('student_documentables');
}
In your StudentPassport :
// we define a relation to retrieve all documents linked to that passport
public function student_documents()
{
return $this->morphMany(StudentDocument::class, 'student_documentables');
}

PHP function stripos() expects parameter 1 to be string, object given

I'm running through Laravel 6.0's addSelect() method as the official documentation described. However, I'm getting an error as my title suggested.
Two corresponding tables are:
CREATE TABLE `destinations` (
`id` int(11) NOT NULL AUTO_INCREMENT,
`name` varchar(90) NOT NULL,
PRIMARY KEY (`id`)
) ENGINE=InnoDB AUTO_INCREMENT=5 DEFAULT CHARSET=latin1
CREATE TABLE `flights` (
`id` int(11) NOT NULL AUTO_INCREMENT,
`name` varchar(90) NOT NULL,
`destination_id` int(11) NOT NULL,
`arrived_at` datetime NOT NULL,
PRIMARY KEY (`id`)
) ENGINE=InnoDB AUTO_INCREMENT=7 DEFAULT CHARSET=latin1
The corresponding controller:
use App\Flight;
use App\Destination;
class TestController extends Controller
{
public function Index()
{
return Destination::addSelect(['last_flight' =>
Flight::select('name')
->whereColumn('destination_id', 'destinations.id')
->orderBy('arrived_at', 'desc')
->limit(1)
])->get();
}
}
What is the object provided as a parameter, which is responsible for the error?

How to create laravel migration for tables with multiple foreign keys?

I want to create a table with multiple foreign keys. Here is the sql:
CREATE TABLE `customers` (
`id` int(10) unsigned NOT NULL AUTO_INCREMENT,
`name` varchar(50) DEFAULT NULL,
`address` varchar(100) DEFAULT NULL,
`email` varchar(50) DEFAULT NULL,
`type_id` tinyint(3) unsigned DEFAULT NULL,
`district_id` tinyint(3) unsigned DEFAULT NULL,
`city_id` tinyint(3) unsigned DEFAULT NULL,
`business_id` tinyint(3) unsigned DEFAULT NULL,
`group_id` tinyint(3) unsigned DEFAULT NULL,
PRIMARY KEY (`id`),
KEY `FK_customer_1` (`district_id`,`city_id`),
KEY `FK_customer_2` (`business_id`),
KEY `FK_customer_3` (`group_id`),
KEY `FK_customer_4` (`type_id`),
CONSTRAINT `FK_customer_1` FOREIGN KEY (`district_id`, `city_id`)
REFERENCES `cities` (`district_id`, `city_id`) ON DELETE CASCADE,
CONSTRAINT `FK_customer_2` FOREIGN KEY (`business_id`) REFERENCES `businesses` (`business_id`) ON DELETE CASCADE,
CONSTRAINT `FK_customer_3` FOREIGN KEY (`group_id`) REFERENCES `groups` (`group_id`) ON DELETE CASCADE,
CONSTRAINT `FK_customer_4` FOREIGN KEY (`type_id`) REFERENCES `types` (`type_id`) ON DELETE CASCADE
) ENGINE=InnoDB AUTO_INCREMENT=1 DEFAULT CHARSET=latin1;
I wrote a migration file with the following:
Schema::create('customers', function (Blueprint $table) {
$table->increments('id');
$table->string('name',50);
$table->string('address',100)->nullable();
$table->string('email',50)->nullable();
$table->integer('type_id')->unsigned()->index();
$table->integer('district_id')->unsigned()->index();
$table->integer('city_id')->unsigned()->index();
$table->integer('business_id')->unsigned()->index();
$table->integer('group_id')->unsigned()->index();
$table->timestamps();
$table->foreign(['district_id','city_id'])->references(['district_id','city_id'])->on('cities')->onDelete('cascade');
$table->foreign('business_id')->references('business_id')->on('businesses')->onDelete('cascade');
$table->foreign('type_id')->references('type_id')->on('types')->onDelete('cascade');
$table->foreign('group_id')->references('group_id')->on('groups')->onDelete('cascade');
});
But when I run the migration it gives me the following error.
SQLSTATE[HY000]: General error: 1005 Can't create table `wastewater`.`#sql-5a8_18a` (errno: 150 "Foreign key constraint is incorrectly formed") (SQL: alter table `customers` add constraint `customers_district_id_city_id_foreign` foreign key (`district_id`, `city_id`) references `cities` (`district_id`, `city_id`) on delete cascade)`
How can I this?
Can you please Try this way, Just removed array and define with comma-separated only.
Schema::create('customers', function (Blueprint $table) {
$table->increments('id');
$table->string('name',50);
$table->string('address',100)->nullable();
$table->string('email',50)->nullable();
$table->integer('type_id')->unsigned()->index();
$table->integer('district_id')->unsigned()->index();
$table->integer('city_id')->unsigned()->index();
$table->integer('business_id')->unsigned()->index();
$table->integer('group_id')->unsigned()->index();
$table->timestamps();
$table->foreign('district_id','city_id')->references('district_id','city_id')->on('cities','cities')->onDelete('cascade','cascade');
$table->foreign('business_id')->references('business_id')->on('businesses')->onDelete('cascade');
$table->foreign('type_id')->references('type_id')->on('types')->onDelete('cascade');
$table->foreign('group_id')->references('group_id')->on('groups')->onDelete('cascade');
});
Try the following way, it will work.
Schema::create('customers', function (Blueprint $table) {
$table->increments('id');
$table->integer('type_id', false, true);
$table->foreign('type_id')->references('type_id')->on('types')
->onDelete('cascade');
$table->integer('district_id', false, true);
$table->foreign('district_id')
->references('district_id')->on('cities')
->onDelete('cascade');
$table->integer('city_id', false, true);
$table->foreign('city_id')
->references('city_id')->on('cities')
->onDelete('cascade');
$table->integer('business_id', false, true);
$table->foreign('business_id')->references('business_id')
->on('businesses')->onDelete('cascade');
$table->integer('group_id', false, true);
$table->foreign('group_id')->references('group_id')->on('groups')
->onDelete('cascade');
$table->string('name',50);
$table->string('address',100)->nullable();
$table->string('email',50)->nullable();
$table->timestamps();
});

Laravel 5.4 Model Relationship

I have created three tables users, courses and user_courses as shown below
CREATE TABLE `users` (
`id` bigint(20) unsigned NOT NULL AUTO_INCREMENT,
`name` varchar(255) COLLATE utf8mb4_unicode_ci NOT NULL,
`email` varchar(255) COLLATE utf8mb4_unicode_ci NOT NULL,
`password` varchar(255) COLLATE utf8mb4_unicode_ci NOT NULL,
`address` varchar(255) COLLATE utf8mb4_unicode_ci DEFAULT NULL,
`remember_token` varchar(100) COLLATE utf8mb4_unicode_ci DEFAULT NULL,
`status` enum('0','1') COLLATE utf8mb4_unicode_ci DEFAULT NULL,
`created_at` timestamp NULL DEFAULT NULL,
`updated_at` timestamp NULL DEFAULT NULL,
PRIMARY KEY (`id`)
) ENGINE=InnoDB AUTO_INCREMENT=1 DEFAULT CHARSET=utf8mb4 COLLATE=utf8mb4_unicode_ci
CREATE TABLE `courses` (
`id` bigint(20) NOT NULL AUTO_INCREMENT,
`title` text,
`description` text,
`price` varchar(255) DEFAULT NULL,
`schedule` varchar(255) DEFAULT NULL,
`duration` varchar(255) DEFAULT NULL,
`summary` text,
`skills` text,
`mode` enum('0','1') DEFAULT NULL COMMENT '0-Online 1 -Instructor',
`random_token` text,
PRIMARY KEY (`id`)
) ENGINE=InnoDB AUTO_INCREMENT=1 DEFAULT CHARSET=latin1
CREATE TABLE `user_courses` (
`id` bigint(20) NOT NULL AUTO_INCREMENT,
`user_id` bigint(20) DEFAULT NULL,
`course_id` bigint(20) DEFAULT NULL,
PRIMARY KEY (`id`)
) ENGINE=InnoDB AUTO_INCREMENT=1 DEFAULT CHARSET=latin1
Now with these tables, I want to bind relationship such as when I fetch Users I'm able to get courses for a user and when I get to courses I want users associated with the course.
Please help how I can achieve it.
I have got my answer so posting it here if it can help anyone.
The main thing here is to assign a many-to-many relationship. In my user model I have defined
public function courses()
{
return $this->belongsToMany('App\Course');
}
In course model
public function users()
{
return $this->belongsToMany('App\User');
}
Actually, it depends on how you want to use the relationship.In some parts of the code you will need $user->courses or more likely to query $course->users or both.
Now here user_course table will be assumed as a pivot table. So in model, you can write it as
public function courses()
{
return $this->belongsToMany('App\Course', 'user_courses');
}
Here you can also specify the actual names of the fields of that particular pivot table i.e user_courses table.Then, what all we have to do is just add two more parameters first is the current model field and then add the field of the model being joined like
public function courses()
{
return $this->belongsToMany('App\Course', 'user_courses','user_id', 'course_id');
}
So using the above model relationship you can easily fetch users with all the respective courses by
User::->with('courses')->get();
First Fix
First, fix the user_course table structure the users table has id as integer while it's being referenced in user_course in user_id as bigint.
Solution
The first thing to do is to create models in the application. Then create relationships within models and finally use those relationships.
Create models
By using command line
php artisan make:model Course
php artisan make:model UserCourse
You can create them manually if you like. By default, they will be created in app folder with namespace App. For example, the user model will be App/User and so on.
The user model will already exists as its shipped with laravel default installation.
Create relationships
In user model add the following function
public function courses()
{
$this->belongsToMany(Course::class, 'user_course');
}
You can leave the Course Model empty if you are not planning to make a reverese relation from course to user. The one above defines relation from user to courses
Usage
Say in a controller you can use this as
public function someFunctionInController()
{
$usersWithCourses = \App\User::with('courses')->get()->toArray();
//result of a single user record will look something like this
/**
[
'id' => 1,
'name' => 'some name'
... //other users table columns
//the courses will be an array of array content and will be automatically injected
'courses' => [[
'id' => 1 //the course id
... //course table columns,
'pivot' => [
'user_id' => 1,
'course_id' => 1
]
],[
'id' => 3 //the course id
... //course table columns,
'pivot' => [
'user_id' => 1,
'course_id' => 3
]
]]
]
**/
}

How to implement partition in laravel database migration

Using Laravel 5.3 how can I implement partition. Following is the mysql table structure I'm trying to add in migration.
CREATE TABLE `settings` (
`id` INT(10) unsigned NOT NULL AUTO_INCREMENT,
`client_id` INT(11) NOT NULL,
`key` VARCHAR(255) COLLATE utf8_unicode_ci NOT NULL,
`value` TEXT COLLATE utf8_unicode_ci NOT NULL,
`created_at` TIMESTAMP NULL DEFAULT NULL,
`updated_at` TIMESTAMP NULL DEFAULT NULL,
PRIMARY KEY `settings_id_primary` (`client_id`, `id`),
UNIQUE KEY `settings_key_unique` (`client_id`, `key`),
KEY `settings_id_key` (`id`)
) ENGINE=InnoDB DEFAULT CHARSET=utf8 COLLATE=utf8_unicode_ci PARTITION BY KEY (`client_id`) PARTITIONS 50;
Below is what I tried so far, but this is only adding columns & keys.
Schema::create('settings', function(Blueprint $table) {
$table->integer('id'); // I can't use increments, because throwing an error when I try to add primary key below
$table->integer('client_id');
$table->string('key');
$table->text('value');
$table->timestamps();
$table->primary(['client_id', 'id']);
$table->unique(['client_id', 'key']);
});
How can I do the partition? If there migration doesn't support partition. Is there way I can dump the whole SQL query in the migration and run.
I think it is help to you,
Schema::create('settings', function(Blueprint $table) {
$table-> increments('id');
$table->integer('client_id')->primary();
$table->string('key');
$table->text('value');
$table->timestamps();
$table->unique(['client_id', 'key']);
});
or
Schema::create('settings', function(Blueprint $table) {
$table-> increments('id');
$table->integer('client_id');
$table->string('key');
$table->text('value');
$table->timestamps();
$table->primary('client_id');
$table->unique(['client_id', 'key']);
});
I searched everywhere, i can't solution find for partition.
But,
My suggestion use, below unprepared into the migration file functions of up and down function
DB::unprepared()
in migration to run your SQL query with partition.
like,
DB::unprepared('create table....')
There's now a Composer package for this called brokenice/laravel-mysql-partition:
https://packagist.org/packages/brokenice
Here's a sample right from the docs:
// You use their extended Schema class:
use Brokenice\LaravelMysqlPartition\Schema\Schema;
// You might also need this (I didn't need it for partitioning by hash):
use Brokenice\LaravelMysqlPartition\Models\Partition;
// I omitted class and method definition boilerplate...
// Create a table as you would normally:
Schema::create('partitioned', static function (Blueprint $table) {
// ...
});
// Now partition it (it will run an ALTER TABLE query):
Schema::partitionByList(
'partitioned',
'id',
[
new Partition('server_east', Partition::LIST_TYPE, [1,43,65,12,56,73]),
new Partition('server_west', Partition::LIST_TYPE, [534,6422,196,956,22])
]
);

Resources