How to get something in every 1 minute? - laravel-4

How I can get +50 resource in every 1 minute? My code is:
$r = DB::table('user_resources')->where('user_id', '=', 3)->first();
$time = time();
if ($time == 60) {
return $r->Iron + 50;
} else {
return 0;
}
I know that this is absolutely incorrect but i don't know how to do it.

First you got to fix your method into something like this:
public function addResource($n){
$r = UserResources::where('user_id', '=', 3)->first();
$r->Iron = $r->Iron+$n;
$r->save();
return $r->Iron;
}
Put the function at your route or controller if you use that. If this is a function that is suppose to be called by user, then create an AJAX call to the function from your view and iterate it every minute using the Javascript setInterval() method, else if this is suppose to be a backend service then you need to look into cron jobs.

Related

How to update only one property of model?

I'm working on user consents. In my request I have these properties:
$newsLetters (bool|nullable),
$sms (bool|nullable),
$billEmail (bool|nullable),
I need update only one. So I need to find one which is not null and update it, if in my request is more than one properties with bool values i need to throw exception.
How can I achieve this?
My request extends spatie/laravel-data.
I don't understand why would you handle something like this on the backend (you can use radio button for this and always send only one value), you can use validation for requests or something like this:
$newsLetters = null;
$sms = true;
$billEmail = null;
$values = [$newsLetters, $sms, $billEmail];
$filter = sizeof(array_filter($values, function($el) { return $el === null;})) < 2;
if($filter) {
//return exception or whatever
} else {
//update values
}

Refactoring multiple same queries with different value

Is there a better way to refactor this code? It's basically the same line with different values. I thought of doing a for loop but maybe there's another way.
$date = $request->date;
$underConsideration = Application::whereDate('created_at',$date)->where('status','Under consideration')->count();
$phoneScreened = Application::whereDate('created_at',$date)->where('status','Phone screened')->count();
$interviewed = Application::whereDate('created_at',$date)->where('status','Interviewed')->count();
$offerExtended = Application::whereDate('created_at',$date)->where('status','Offer extended')->count();
You should create a separate method for this.
public function myMethod()
{
$under_consideration = $this->fetchApplicationData($request, 'Under consideration');
$phone_screened = $this->fetchApplicationData($request, 'Phone screened');
$interviewed = $this->fetchApplicationData($request, 'Interviewed');
$offer_extended = $this->fetchApplicationData($request, 'Offer extended');
}
private function fetchApplicationData($request, $status)
{
return Application::
whereDate('created_at', $request->date)
->where('status', $status)
->count();
}
That is a much cleaner code.
However, I advise that you should put the items:
Under consideration, Phone screened, Interviewed, Offer extended
into a separate table on the database and just save the status_id on your main table.
One of the major advantage on this is the speed. For example, your client wants to know all record that has a status of Interviewed for a certain date span. Database searching against integer is a lot faster than string.
You could create a method to handle the select operations. Something like:
public function yourExisitingMethod() {
$date = $request->date;
$underConsideration = getData($date,'Under consideration');
$phoneScreened = getData($date,'Phone screened');
$interviewed = getData($date,'Interviewed');
$offerExtended = getData($date,'Offer extended');
}
public function getData($date, $status) {
$data = Application::whereDate('created_at',$date)->where('status',$status)->count();
return $data;
}
This would at the very least improve the maintainability of your code, and in my opinion improves reusability and readability.

How to call information from one model to another Codeigniter

I'm stuck on this from a while.Can't figured it out.I reed documantion, tried with several videos and tried like 10 different ways, nothing is working yet.So I have one view/model for one thing, in this example Destination and I have separate files for Offers.The controllers for both are in one file.I want tho the information that is in destination to go to Offers as well.Please help I can't figure out what I'm missing:
So here is the most important parts:
destination_model.php
<?php class Destination_model extends CI_Model
{
public function getDestinationDetails($slug) {
$this->db->select('
id,
title,
information
');
$this->db->where('slug', $slug);
$query = $this->db->get('destinations')->row();
if(count($query) > 0)
{
return $query;
}
else
{
// redirect(base_url());
}
}
public function getOffersByDestination($destination_id)
{
$this->db->select('
o.short_title,
o.price,
o.currency,
o.information,
o.long_title_slug,
oi.image,
c.slug as parent_category
');
$this->db->from('offers o');
$this->db->join('offers_images oi', 'oi.offer_id = o.id', 'left');
$this->db->join('categories c', 'c.id = o.category');
$this->db->group_by('o.id');
$this->db->where('o.destination', $destination_id);
$this->db->where('o.active', '1');
return $this->db->get();
} }
And then in the controller for offers I put this:
$this->load->model('frontend/destination_model');
$this->params['destination'] = $this->destination_model->getOffersByDestination($data->id);
All I need is the title and the information about the destination.
Here is the whole controller for the offers:
$data = $this->slugs_model->getOfferDetails(strtok($this->uri->segment(2), "."));
$this->load->model('frontend/offers_model');
$this->load->model('frontend/destination_model');
$this->params['main'] = 'frontend/pages/offer_details';
$this->params['title'] = $data->long_title;
$this->params['breadcumb'] = $this->slugs_model->getSlugName($this->uri->segment(1));
$this->params['data'] = $data;
$this->params['images'] = $this->slugs_model->getOfferImages($data->id);
$this->params['similar'] = $this->slugs_model->getSimilarOffers($data->category, $data->id);
$this->params['destination'] = $this->destination_model->getOffersByDestination($data->id);
$this->params['offers'] = $this->offers_model->getImportantOffers($data->offers, $data->category, $data->id);
You need to generate query results after you get it from model,
e.g: row_array(), this function returns a single result row.
here's the doc: Generating Query Results
try this:
$this->load->model('frontend/destination_model');
$data['destination'] = $this->destination_model->getOffersByDestination($data->id)->row_array();
$this->load->view('view_name', $data);
And in your view echo $destination['attribut_name'];,
or you can print the array, to see if it's work print_r($destination);

Difficulties with scope in Laravel

I'm trying to build an application where there's a device with an expire date:
the expire date must be created with values from 2 other tables: history (last date) & model (interval)
I've create following scope in my Device model:
public function scopeExpiryDate($query, $operator) {
if ($this->histories->last() != null) {
$cal_date = $this->histories->sortBy('date')->last()->date;
$interval = $this->product->interval;
return $query->where($cal_date->addDays($interval), $operator, Carbon::now());
}
return $query;
}
Then I could use the next line:
$devices->ExpiryDate('<=')->get();
Update
like #ceejayoz told in the comments I checked the scopes section on the Laravel-site.
I edited this question.
So how do I get this scope working?
Assuming that $cal_date is a Carbon\Carbon instance, you can use this query:
$query->whereDate($cal_date->addDays($interval), $operator, Carbon::now());
For more information, there's a great tutorial on date filtering here
Ok i've found the solution. It was not found in the scopes, but in adding a attribute.
I did the following in my Device model:
public function getExpirydateAttribute() {
if ($this->histories->last() != null) {
$cal_date = $this->histories->sortBy('date')->last()->date;
$interval = $this->product->interval;
return $cal_date->addDays($interval);
}
return Carbon::now();
}
and in my view I can call something like this:
$devices->filter(function($item){ return $item->Expirydate > now()->modify('last day of this month'); })->count()
Thanks to the people who answered to my question.

TYPO3 Extbase: How to render the pagetree from my model?

I want to create some kind of sitemap in extbase/fluid (based on the pagetree). I have loaded the pages table into a model:
config.tx_extbase.persistence.classes.Tx_MyExt_Domain_Model_Page.mapping.tableName = pages
I have created a controller and repository, but get stuck on the part wich can load the subpages as relation into my model.
For example:
$page = $this->pageRepository->findByPid($rootPid);
Returns my rootpage. But how can I extend my model that I can use $page->getSubpages() or $page->getNestedPages()?
Do I have to create some kind of query inside my model? Or do I have to resolve this with existing functions (like the object storage) and how?
I tried a lot of things but can simply figure out how this should work.
you have to overwrite your findByPid repository-method and add
public function findByPid($pid) {
$querySettings = $this->objectManager->create('Tx_Extbase_Persistence_Typo3QuerySettings');
$querySettings->setRespectStoragePage(FALSE);
$this->setDefaultQuerySettings($querySettings);
$query = $this->createQuery();
$query->matching($query->equals('pid', $pid));
$pages = $query->execute();
return $pages;
}
to get all pages. Than you can write your own getSubpages-method like
function getSubpages($currentPid) {
$subpages = $this->pagesRepository->findByPid($currentPid);
if (count($subpages) > 0) {
$i = 0;
foreach($subpages as $subpage) {
$subpageUid = $subpage->getUid();
$subpageArray[$i]['page'] = $subpage;
$subpageArray[$i]['subpages'] = $this->getSubpages($subpageUid);
$i++;
}
} else {
$subpageArray = Array();
}
return $subpageArray;
}
i didn't test this method, but it looks like this to get alle subpages.
i wonder that i couldĀ“t find a typo3 method that return the complete Page-Tree :( So i write a little function (you can use in an extbase extension), for sure not the best or fastes way, but easy to extend or customize ;)
first you need an instance of the PageRepository
$this->t3pageRepository = \TYPO3\CMS\Core\Utility\GeneralUtility::makeInstance('TYPO3\\CMS\\Frontend\\Page\\PageRepository');
this->t3pageRepository->init();
make the init, to set some basic confs, like "WHERE deletet = 0 AND hidden = 0..."
then with this function you get an array with the page data and subpages in. I implement yust up to three levels:
function getPageTree($pid,$deep=2){
$fields = '*';
$sortField = 'sorting';
$pages = $this->t3pageRepository->getMenu($pid,$fields,$sortField);
if($deep>=1){
foreach($pages as &$page) {
$subPages1 = $this->t3pageRepository->getMenu($page['uid'],$fields,$sortField);
if(count($subPages1)>0){
if($deep>=2){
foreach($subPages1 as &$subPage1){
$subPages2 = $this->t3pageRepository->getMenu($subPage1['uid'],$fields,$sortField);
if(count($subPages2>0)){
$subPage1['subpages'] = $subPages2;
}
}
}
$page['subpages'] = $subPages1;
}
}
}
return $pages;
}

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