what about bind and reference in c++11 - c++11

why this code compiled in c++11 the it2 and it4 is correct.
but it1 and it3 is compiled error with non-static function?
is it bug with std compiler? or i understand the wrong about these?
#include <iostream>
#include <functional>
using namespace std;
namespace test {
class a {
public:
void funa() {}
};
class b : public a {
public:
void funb() { }
};
struct c {
void func() {}
};
}
int main()
{
test::b b1;
test::c c1;
auto it1 = std::bind(&(test::c::func),&c1);
auto it2 = std::bind(&test::c::func,&c1);
auto it3 = std::bind(&test::a::funa, &b1);
auto it4 = std::bind(&(test::a::funa),&b1);
}

Related

C++ Access member function using pointer

I am not able to access member function using pointer.Find the below code and Error message
The Error message is mentioned here
error: request for member ‘getstream’ in ‘* objA.A::getfunction()’, which is of non-class type ‘int’
ret = objA.getfunction()->getstream();
#include <iostream>
using namespace std;
class A {
public:
int *getfunction();
int getstream();
};
int* A::getfunction()
{
static int a;
a= getstream();
return &a;
}
int getstream()
{
return 1;
}
int main()
{
int *ret;
A objA;
ret = objA.getfunction()->getstream();
cout << ret;
return 0;
}
If you want to achieve a syntax like objA.getfunction()->getstream(); in your main function,
you can do it with class A implementation similar to this :
#include <iostream>
using namespace std;
// class A declaration
class A {
public:
// Nested class A::AFunction declaration
class AFunction {
public:
int getstream();
};
private:
AFunction *p_AFunction;
public:
A();
~A();
A::AFunction *getfunction();
}; // class A
// class A member function implementations
A::A() : p_AFunction(new AFunction()) {
}
A::~A() {
delete p_AFunction;
p_AFunction = nullptr;
}
A::AFunction *A::getfunction() {
return p_AFunction;
}
// Nested class A::AFunction member function implementations
int A::AFunction::getstream() {
return 1;
}
// main function
int main() {
A objA;
int ret = objA.getfunction()->getstream();
cout << ret;
return 0;
}
If you want A::getfunction() function to return a function pointer to a member function in class A, and then invoke it in main function, you can have a implementation similar to this :
#include <iostream>
using namespace std;
// class A declaration
class A {
public:
typedef int (A::*AMemberFuncPtr) ();
private:
AMemberFuncPtr fn_getstream;
public:
A();
A::AMemberFuncPtr getfunction();
private:
int getstream();
}; // class A
// class A member function implementations
A::A() : fn_getstream(&A::getstream) {
}
A::AMemberFuncPtr A::getfunction() {
return fn_getstream;
}
int A::getstream() {
return 1;
}
// main function
int main() {
A objA;
int ret = (objA.*objA.getfunction())();
cout << ret;
return 0;
}
Also see the answer to Function pointer to member function.

Template function taking generic pointer to member function with both const& and by-value implementations

I want to have a template function which accepts unary member-function pointers of an instance of some generic type.
My problem is that I must support both void(T val) and void(const T& val) member functions.
I have written one template function for each case and it works fine, but this leads to code duplication since the function logic is completely the same. (I found something completely similar here: Function taking both pointer to member-function and pointer to const member-function but I fail to see a definitive solution).
An example of the generic type mentioned above:
using UserAddress = std::string;
class User
{
private:
int mHeight;
UserAddress mAddress;
public:
void SetHeight(int height){mHeight = height;}
void SetAddress(const UserAddress& address){mAddress = address;}
};
Where UserAddress is some heavy type I want to pass by reference.
My templated function:
template <typename TPersistentObject>
class Persistence
{
private:
std::map<std::string, std::function<void(User*)>> mSetterOfProperty;
template <typename TPersistentObject, typename TPropertyValue>
void DefinePropertySettingMethod(const std::string& propertyName,
void (TPersistentObject::*propertySetter)(TPropertyValue), std::function<TPropertyValue(void)> dataReader)
{
mSetterOfProperty[propertyName] =
[propertySetter, columnDataReader](TPersistentObject* persistentObject)
{
(persistentObject->*propertySetter)(dataReader());
};
}
};
/// Const& implementation leading to code duplication
template <typename TPersistentObject, typename TPropertyValue>
void DefinePropertySettingMethod(const std::string& propertyName,
void (TPersistentObject::*propertySetter)(const TPropertyValue&), std::function<TPropertyValue(void)> dataReader)
{
...
}
};
Is there some way to define this function to support the following:
int main()
{
auto intDataReader = []() {
return 1;
};
auto stringDataReader = []() {
return UserAddress("Next Door");
};
Persistence p;
p.DefinePropertySettingMethod<User,int>("Height", &User::SetHeight, intDataReader);
p.DefinePropertySettingMethod<User,UserAddress>("Address", &User::SetAddress, stringDataReader);
}
Thanks to Igor Tandetnik 's tip I managed to compile a solution. std::enable_if is not what I needed though since I did not need to deactivate an overload (or at least I couldn't come to a solution using it).
std::conditional did the trick.
Here is the code:
#include <string>
#include <functional>
#include <map>
#include <string>
#include <type_traits>
using UserAddress = std::string;
class User
{
private:
int mHeight;
UserAddress mAddress;
public:
void SetHeight(int height){mHeight = height;}
void SetAddress(const UserAddress& address){mAddress = address;}
};
template <typename TPersistentObject>
class Persistence
{
public:
std::map<std::string, std::function<void(TPersistentObject*)>> mSetterOfProperty;
template <typename TPropertyValue>
void DefinePropertySettingMethod(const std::string& propertyName,
void (TPersistentObject::*propertySetter)(TPropertyValue),
std::function<
typename std::conditional<!std::is_same<TPropertyValue, typename std::decay<TPropertyValue>::type>::value,
typename std::decay<TPropertyValue>::type, TPropertyValue>::type
(void)> dataReader)
{
mSetterOfProperty[propertyName] =
[propertySetter, dataReader](TPersistentObject* persistentObject)
{
(persistentObject->*propertySetter)(dataReader());
};
}
};
int main()
{
std::function<int()> intDataReader = []() {
return 1;
};
std::function<std::string()> stringDataReader = []() {
return UserAddress("Next Door");
};
Persistence<User> p;
p.DefinePropertySettingMethod("Height", &User::SetHeight, intDataReader);
p.DefinePropertySettingMethod("Address", &User::SetAddress, stringDataReader);
}

STD::FUNCTION C++

I'm still learning Modern C++ and I would like to clarify STD:FUNCTION,
Here is my sample code that works fine :
#include <iostream>
#include <functional>
using namespace std;
int func(function<bool()> foo) {
return 2;
}
struct fee {
bool operator()() {
return true;
}
};
int main() {
cout << func(fee());
}
It will display "2" on the console.
What I am wondering is why this does not work. I changed bool operator()() to bool operator()(int i).
#include <iostream>
#include <functional>
using namespace std;
int func(function<bool()> foo) {
return 2;
}
struct fee {
bool operator()(int i) {
return true;
}
};
int main() {
cout << func(fee());
}
The error says:
In function 'int main()':
18:20: error: could not convert 'fee()' from 'fee' to 'std::function<bool()>'
What should be the right thing to do ?
In the second example, the fee operator() function now takes an int as a parameter.
Therefore you need to change
int func(function<bool()> foo) {
return 2;
}
to
int func(function<bool(int)> foo) {
return 2;
}
to reflect that.

Inheritance of combinated templated types

I would like to make a class that inherits of a combination of two templated types like this for example:
#include <vector>
#include <set>
template<typename T, typename Base=std::vector<T>>
class A : public Base
{
};
int main()
{
A<int> a;
A<int, std::set<int>> b;
return 0;
}
But now, I would like to be able to write
A<int, std::set> b;
instead of
A<int, std::set<int>> b;
How can I do this please?
Thanks! :)
SOLUTION from #Piotr S.
Here I repost the complete solution given by Piotr S. so this very nice answer is easier to find for others (don't forget to vote for his answer :-P):
#include <vector>
#include <set>
#include <utility>
#include <iostream>
template <template <typename...> class> struct tag {};
template <typename T, template <typename...> class Base = std::vector>
class A : public Base<T>
{
public:
void add(const T& t)
{
return _add(tag<Base>{}, t);
}
private:
void _add(tag<std::set>, const T& t)
{
std::cout << "set\n";
Base<T>::insert(t);
}
void _add(tag<std::vector>, const T& t)
{
std::cout << "vector\n";
Base<T>::push_back(t);
}
};
int main()
{
A<int> a;
A<int, std::set> b;
a.add(1);
b.add(1);
}
#include <vector>
#include <set>
template <typename T, template <typename...> class Base = std::vector>
class A : public Base<T>
{
};
int main()
{
A<int> a;
A<int, std::set> b;
}
DEMO

How to write a C++ API class that will allow a user to register its own callback functions?

Let's say a user links his app against a library I wrote and I want to let him specify a callback function that I will call whenever an error occurs in my library. The implementation below works but I want to double check that I'm not missing something here:
Thread safety
DLL initialization issues
Public API considerations (I'm giving away a reference to an instance from the DLL is that OK?)
Anything that could be done better to hide implementation details from the public API?
errordispatcher.h:
#pragma once
#include <functional>
#include <memory>
#include <string>
namespace WE
{
class ErrorDispatcher
{
public:
ErrorDispatcher()
{}
explicit ErrorDispatcher(std::function<void(std::string)> user_func)
: error_callback_func{user_func}
{}
virtual ~ErrorDispatcher(){}
static ErrorDispatcher& getInstance()
{
return instance_;
}
void setErrorCallback(std::function<void(std::string)> user_func)
{
error_callback_func = nullptr;
if (user_func)
error_callback_func = user_func;
}
void dispatchError(std::string message)
{
if (error_callback_func)
error_callback_func(message);
}
private:
explicit ErrorDispatcher(const ErrorDispatcher&) = delete;
explicit ErrorDispatcher(ErrorDispatcher&&) = delete;
ErrorDispatcher& operator = (const ErrorDispatcher&) = delete;
ErrorDispatcher& operator = (ErrorDispatcher&&) = delete;
static ErrorDispatcher instance_;
std::function<void(std::string)> error_callback_func = nullptr;
};
}
NOTE: above I have inline implementation details in the public header to make this post shorter but they will be moved to a .cpp and won't be part of the public header
errordispatcher.cpp:
#include "errordispatcher.h"
namespace WE
{
ErrorDispatcher ErrorDispatcher::instance_;
}
apitest.h
namespace WE
{
void dllFunctionThatMightGiveError();
}
apitest.cpp
#include "errordispatcher.h"
#include "apitest.h"
namespace WE
{
void dllFunctionThatMightGiveError()
{
// Some error happens in dll so call user function and give a message to the user!
ErrorDispatcher::getInstance().dispatchError("Error in DLL!");
}
}
main.cpp (USER APP)
#include "errordispatcher.h"
#include "apitest.h"
#include <iostream>
#include <string>
void error_callback(std::string message)
{
std::cout << message << "\n";
}
int main(void)
{
WE::ErrorDispatcher::getInstance().setErrorCallback(error_callback);
WE::ErrorDispatcher::getInstance().dispatchError("Error in APP!");
WE::dllFunctionThatMightGiveError();
return 0;
}
Output is:
Error in APP!
Error in DLL!

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