cat or grep a html file to find specific text [duplicate] - bash

Question

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How to print lines between two patterns, inclusive or exclusive (in sed, AWK or Perl)?
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Extract lines between two patterns from a file [duplicate]
(3 answers)
Closed 4 years ago.
I am trying to use bash to parse and HTML file using grep.
The HTML won't change so I should be able to find the text easy enough.
The HTML will be like this, and I just want the number which will change each time the file changes:
<div class="total">
900 files inspected,
28301 offenses detected:
</div>
grep -E '^<div class="total">.</div>' my_file.html
Ideally I just want to pull the number of offenses so in the example above it would be 28301. I would like to assign it to a variable also.
Am I close?

Answer 1

you can do a simple
a=$(grep -oP '(\d+)(?=\soffenses\sdetected)' abc);echo $a
will give:
28301
-o only gives the matching part of the line
-P uses perl regular expression in regex
abc is the name of the file
(\d+)(?=\soffenses\sdetected) in this reges we are just using positive lookahead to capture the require digits that are followed by a particular word

Answer 2

If you have GNU grep and GNU sed, you can do:
$ cat file | xargs | grep -Po '<div class=total>\K(.*?)</div>' | sed -E 's/<\/div>//; s/, /\n/'
900 files inspected
28301 offenses detected:
If you have ruby available:
$ ruby -e 'puts readlines.join[/(?<=<div class="total">).+(?=<\/div>)/m].gsub(/^[ \t]+/m,"")' file
900 files inspected,
28301 offenses detected: