Laravel multiple function in a view - laravel

Question

i need help, i'm new in laravel, i want to make query to get year only from table like this
public function index() {
$items = Items::distinct()->orderBy('date','desc')->select(DB::raw('YEAR(`date`) as date'))->get();
$itemDet = Items::where('date', $items->date);
}
then i want to show other value from table based on year above with this function
public function itemDetail($year) {
$itemDet = Items::where('YEAR(`date`)', $year);
return $itemDet;
}
But i don't know how to call it in view, i only know how to call the first function in a view, and I don't know how to pass value year from first function as parameters to second function.
2018
- item2018
- item2018
- item2018
2017
- item2017
2016
-item2016
-item2016
sorry for my bad grammar, thank you!

Answer 1

public function itemDetail($year) {
$itemDet = Items::where('YEAR(`date`)', $year);
//return $itemDet; change it to
return view('yourViewPath',compact('itemDet'));
}
in view you can access like this way
{{ $itemDet }}

Answer 2

You can get that output right away in your index function without passing it to second function, one way to do it.
public function index() {
$arr_container = []; //create array container
$items = Items::distinct()->orderBy('date','desc')->select(DB::raw('YEAR(`date`) as date'))->get();
foreach($items as $val){
$itemDet = Items::select(DB::raw('item'))->where('YEAR(`date`)', $val->year)->get();
if($itemDet->count()>0){
$arr_container[$val->year][] = $itemDet[0]->item;
}
}
return view('view')->with('years',$arr_container);
}
You should get this output when you call {{$years}}.
2018
- item2018
- item2018
- item2018
2017
- item2017
2016
-item2016
-item2016