Suppose I have 100 .ps files in a directory, called doc1.ps, doc2.ps, ... , doc100.ps. I would like to write a Makefile to do the following: (1) when I run "make", all the files matching the pattern doc*.ps should be converted to the pdf format (without deleting the original copy) using the command line program ps2pdf. (2) Any .ps files not matching the name pattern doc*.ps should be left untouched. (3) Whenever a file doc*.ps is updated, running "make" again should only update the PDF copy of this specific file, without converting all of them again. How can this be done?
P.S. I don't want to type the names of the .ps files explicitly into the Makefile, because this is tedious when there are many files. I'd like to have Makefile handle the matching of wildcard filenames.
Related
I have very little experience with the command line and I'm trying to do something very complicated (to me).
I have a directory with A LOT of subfolders and files in them. All file names contain the parent folder name, e.g.:
Folder1
data_Folder1.csv
other_file_Folder1.csv
Folder2
data_Folder2.csv
other_file_Folder2.csv
In another folder (all in one directory), I have a new version of all the data_FolderX.csv files and I need to replace them in the original folders. I cannot give them another name because of later analyses. Is there a way to replace the files in the original folders with the new version, in the command line?
I tried this Replacing a file into multiple folders/subdirectories but didn't work for me. Given that I have many .csv files in the derectories, I don't want to replace them all, so I don't think I should do it based on the file extension. I would also like to note that the name "FolderX" contains several other _, so in principal, I want to replace the .csv file starting with data in the FolderX.
Can anyone help?
Thanks in advance!
I have two folders with many files of the same naming format but differing extensions. I would like to loop through the files of the first folder and extract their filenames to check if a file of the same name exists in the other folder, then create one (with the other extension) if it doesn't. I can't get a grapple on bash for whatever reason, so I was wondering if there's a simple way to do this.
I have a bunch of files I'm trying to organize quickly, and I had two questions about how to do that. I really appreciate any help! I tried searching but couldn't find anything on these specific commands for OSX.
First, I have about 100 folders in a directory - I'd like to place an folder in each one of those folders.
For example, I have
Cars/Mercedes/<br>
Cars/BMW/<br>
Cars/Audi/<br>
Cars/Jeep/<br>
Cars/Tesla/
Is there a way I can create a folder inside each of those named "Pricing" in one command, i.e. ->
Cars/Mercedes/Pricing <br>
Cars/BMW/Pricing<br>
Cars/Audi/Pricing<br>
Cars/Jeep/Pricing<br>
Cars/Tesla/Pricing
My second question is a little tougher to explain. In each of these folders, I'd like move certain files into these newly created folders (above) in the subdirectory.
Each file has a slightly different filename but contains the same string of letters - for example, in each of the above folders, I might have
Cars/Mercedes/payment123.html
Cars/BMW/payment432.html
Cars/Audi/payment999.html
Cars/Jeep/payment283.html
Is there a way to search each subdirectory for a file containing the string "payment" and move that file into a subfolder in that subdirecotry - i.e. into the hypothetical "Pricing" folders we just created above with one command for all the subdirectories in Cars?
Thanks so much~! help with either of these would be invaluable.
I will assume you are using bash, since it is the default shell in OS X. One way to do this uses a for loop over each directory to create the subdirectory and move the file. Wildcards are used to find all of the directories and the file.
for DIR in Cars/*/ ; do
mkdir "${DIR}Pricing"
mv "${DIR}payment*.html" "${DIR}Pricing/"
done
The first line finds every directory in Cars, and then runs the loop once for each, replacing ${DIR} with the current directory. The second line creates the subdirectory using the substitution. Note the double quotes, which are necessary only if the path could contain spaces. The third line moves any file in the directory whose name starts with "payment" and ends with ".html" to the subdirectory. If you have multiple files which match this, they will all be moved. The fourth line simply marks the end of the loop.
If you are typing this directly into the command line, you can combine it into a single line:
for DIR in Cars/*/ ; do mkdir "${DIR}Pricing"; mv "${DIR}payment*.html" "${DIR}Pricing/"; done
Using Ruby (1.9.3) I need to replace a single file in a zip archive.
The situation is as follows. I have ~1000 zip archives that need to be updated, specifically one file in each of them needs to be replaced. The archives are all of the same structure. Is there a quick and dirty way for Ruby, or a library/gem for Ruby, to simply say "replace the file in this zip archive with this file on the filesystem"?
I'll work on a solution of my own in the meantime.
You can use the zip command, called from the ruby, which probably will be the best solution. From the zip manpage zip manpage
-d
--delete
Remove (delete) entries from a zip archive. For example:
zip -d foo foo/tom/junk foo/harry/\* \*.o
will remove the entry foo/tom/junk, all of the files that start with foo/harry/, and all of the files that end with .o (in any path). Note that shell path‐
name expansion has been inhibited with backslashes, so that zip can see the asterisks, enabling zip to match on the contents of the zip archive instead of the
contents of the current directory. (The backslashes are not used on MSDOS-based platforms.) Can also use quotes to escape the asterisks as in
zip -d foo foo/tom/junk "foo/harry/*" "*.o"
Not escaping the asterisks on a system where the shell expands wildcards could result in the asterisks being converted to a list of files in the current
directory and that list used to delete entries from the archive.
Under MSDOS, -d is case sensitive when it matches names in the zip archive. This requires that file names be entered in upper case if they were zipped by
PKZIP on an MSDOS system. (We considered making this case insensitive on systems where paths were case insensitive, but it is possible the archive came from
a system where case does matter and the archive could include both Bar and bar as separate files in the archive.) But see the new option -ic to ignore case
in the archive.
If you want a pure ruby solution take a look at ZipFileSystem
Zip::ZipFile looks promising. It appears to have a way to delete and add files to a zip archive.
On a Windows box, I need to extract a RAR archive so that individual files in it go into specific directories. I can provide, say, a text file that lists each file and the target directory for it? Then I need help creating a batch file that will actually extract these files into their target locations.
E.g.
RAR archive x.rar contains
a.a
b.b
c.c
Text file x.txt says
a.a C:\foo
b.b C:\bar
c.c C:\foo
Result of running batch file on x.rar and x.txt should be:
in C:\foo we have a.a and c.c
in C:\bar we have b.b
You can pass rar a list of file names to extract with -n#<listfile>. So if you create a single file for each directory you want to extract to this should be a viable option. However, the file you describe to have doesn't quite match the format; you'd need to group it by target directory (much more fun in PowerShell by the way).
However, if the archive you're extracting is a solid archive this will take far longer since you essentially have to decompress the whole archive over and over again.
The best and probably easiest method would then probably to extract the archive once and then sort all files in their respective directories.