Makefile logical AND - makefile

How to perform a logical AND in makefile. if I run make test It works as expected
it gives the output Both PARAMETERS are required. If one of the parameter is missing It should still give the same output but its not working that way for example if I run make test PARAM1=abc it should output Both PARAMETERS are required.How can I mandate both the parameters.
%/test:
ifeq ($(PARAM1)$(PARAM2),)
#echo "Both PARAMETERS are required"
#exit 1
endif
#echo "Do Something $(PARAM1) $(PARAM2)"
I have tried the below code and it gives the error *** missing separator. Stop. I am not familiar with makefile any help is appreciated.
%/test:
## $(or $(and $(PARAME1),$(PARAM2)),$(error Both PARAMETERS must be set))
#>&2 echo "Do Something $(PARAM1),$(PARAME2)"

Your test by its very nature checks that the concatenation of the two is the empty string. If that's not what you want to check, perform a different check. For example,
%/test:
## $(or $(and $(PARAM1),$(PARAM2)),$(error Both PARAMETERS must be set))
Various other variations; Makefile set if variable is empty

Related

Comparing the value of a computed variable, defined by target wildcard

I'd like to be able validate that required arguments have been passed to my make targets. Rather than defining similar logic for each target, I'd like to be able to reuse the same piece of code.
This is my current idea, which does not work:
e.g.
.PHONY: _validate-arg-%
_validate-arg-%:
ifeq ($($(*)),)
#echo "You must specify $(*), value was $($(*))"
#exit 1
endif
.PHONY: say-hello
say-hello: _validate-arg-moniker # this target requires the 'moniker' argument to be supplied
#echo "Hello $(moniker)"
Calling make say-hello moniker=John, results in the output You must specify moniker, value was John.
The expected output is Hello John.
Is what I'm trying to achieve possible? Is there an issue when using $(*) or computed variables with ifeq?
Update: ifeq and computed variables work fine. It seems the issue is only apparent when using the wildcard value $(*) with ifeq

How do you use (GNU) make's "simply expanded" variables in build rules and not get the last definition?

I have a complicated set of rules I need to write to generate a rather large number of "parameterised" output files and thought that, rather than expand them all out by hand, I could repeatedly "include" a template file with sets of rules and use (GNU)make's facility for allowing "simply expanded" variables to avoid the pain.
(In the past I've always been using the "recursively expanded" variable approach, so this is new to me)
As a trivial example of what I thought would work, I tried putting the following in a Makefile
Targ:=A
Param1:=Pa
Param2:=Qa
$(Targ):
#echo expect A, get $(Targ), Target is $#. Params are $(Param1) and $(Param2)
Targ:=B
Param1:=Pb
Param2:=Qb
$(Targ):
#echo expect B, get $(Targ), Target is $#. Params are $(Param1) and $(Param2)
Targ:=C
Param1:=Pc
Param2:=Qc
$(Targ):
#echo expect C, get $(Targ), Target is $#. Params are $(Param1) and $(Param2)
The eventual plan was to replace the rules with an include file containing dozens of different rules, each referencing the various "parameter" variables.
However, what I get is...
prompt> make A
expect A, get C, Target is A. Params are Pc and Qc
prompt> make B
expect B, get C, Target is B. Params are Pc and Qc
Essentially, unlike each rule's target, which is picking up the intended definition, the $(Targ), $(Param1), and $(Param2) in each rule's command is instead being run with the final definition.
Does anyone know how to prevent this, i.e. how do you force the command to use the definition at the time it is encountered in the Makefile?
Simple vs recursive expansion makes no difference here; regardless of which you use you'll see the same behavior. A GNU make variable is global and obviously can have only one value.
You have to understand when variables are expanded. The documentation provides a detailed description of this. Targets and prerequisites are expanded when the makefile is read in, so the value of Targ as the makefile is being parsed is used.
Recipes are expanded when the recipe is to be invoked, which is not until after all makefiles are parsed and make starts to build targets. At that time of course the variable Targ has its last set value.
Without knowing what your makefile really does it's hard to suggest an alternative. One option is to use target-specific variables:
Targ := A
$(Targ): LocalTarg := $(Targ)
$(Targ):
#echo expect A, get $(LocalTarg), Target is $#
Another option is to use constructed variable names:
Targ := A
Targ_$(Targ) := $(Targ)
$(Targ):
#echo expect A, get $(Targ_$#), Target is $#
Apologies for answering my own question, but I now realised it is possible to solve the issue I was having by running make recursively.
E.g. if the parameter variables for the rules are Targ, Param1 and Param2 then
#Set up "default" values for the parameters (As #madscientist points out,
#these will safely be overridden by the defs on the #(make) commands below
Targ=XXXXXXXXXX
Param=XXXXXXXXXX
Param2=XXXXXXXXXX
Recursing=
#
# define N (==3) templated rule(s)
#
$(Targ)%a:
#echo Run Combo_a $(Targ) $(Param1) $(Param2) $#
$(Targ)%b:
#echo Run Combo_b $(Targ) $(Param2) $(Param1) reversed $#
$(Targ)%c:
#echo Run Combo_c $(Param1) $(Targ) $(Param2) mixed again $#
#
#Enumerate "M" (==2) sets of parameters,
# (Except if we are already recursing because unrecognised targets may cause
# it to descend forever)
#
ifneq ($(Recursing), Yes)
Set1%:
#$(MAKE) Targ=Set1 Param1=foo Param2=bar Recursing=Yes $#
Set2%:
#$(MAKE) Targ=Set2 Param1=ray Param2=tracing Recursing=Yes $#
endif
This then allows N*M different combos for N+M typing cost.
eg. (removing messages from make re recursion)
>make Set1.a
Run Combo_a Set1 foo bar Set1.a
>make Set2.c
Run Combo_c ray Set2 tracing mixed again Set2.c

Using ifeq to test the variables

I tried to write this dynamic target to check the variable before running the actual target:
.PHONY: check-env-%
check-env-%:
ifeq ($(${*}),)
$(error not found ${*})
endif
so that I can use it like:
build: check-env-VERSION
But looks like it cannot compare it and even when I supply the required variable, it errors: Makefile:16: *** not found VERSION. Stop.
I believe I'm using the ifeq correctly but not sure why it cannot compare it?
From the docs: "Conditionals control what make actually “sees” in the makefile, so they cannot be used to control recipes at the time of execution." So your access to $* always yields an empty string at the time of makefile analysis, leaving your $(error) as recipe instruction.
Vroomfondel is right. What you can do instead is this:
check-env-%:
test $($*) || (echo $* not found; exit 1;)
...
test shall stop when there is no variable defined.

How to print out a variable in makefile

In my makefile, I have a variable 'NDK_PROJECT_PATH', my question is how can I print it out when it compiles?
I read Make file echo displaying "$PATH" string and I tried:
#echo $(NDK_PROJECT_PATH)
#echo $(value NDK_PROJECT_PATH)
Both gives me
"build-local.mk:102: *** missing separator. Stop."
Any one knows why it is not working for me?
You can print out variables as the makefile is read (assuming GNU make as you have tagged this question appropriately) using this method (with a variable named "var"):
$(info $$var is [${var}])
You can add this construct to any recipe to see what make will pass to the shell:
.PHONY: all
all: ; $(info $$var is [${var}])echo Hello world
Now, what happens here is that make stores the entire recipe ($(info $$var is [${var}])echo Hello world) as a single recursively expanded variable. When make decides to run the recipe (for instance when you tell it to build all), it expands the variable, and then passes each resulting line separately to the shell.
So, in painful detail:
It expands $(info $$var is [${var}])echo Hello world
To do this it first expands $(info $$var is [${var}])
$$ becomes literal $
${var} becomes :-) (say)
The side effect is that $var is [:-)] appears on standard out
The expansion of the $(info...) though is empty
Make is left with echo Hello world
Make prints echo Hello world on stdout first to let you know what it's going to ask the shell to do
The shell prints Hello world on stdout.
As per the GNU Make manual and also pointed by 'bobbogo' in the below answer,
you can use info / warning / error to display text.
$(error text…)
$(warning text…)
$(info text…)
To print variables,
$(error VAR is $(VAR))
$(warning VAR is $(VAR))
$(info VAR is $(VAR))
'error' would stop the make execution, after showing the error string
from a "Mr. Make post"
https://www.cmcrossroads.com/article/printing-value-makefile-variable
Add the following rule to your Makefile:
print-% : ; #echo $* = $($*)
Then, if you want to find out the value of a makefile variable, just:
make print-VARIABLE
and it will return:
VARIABLE = the_value_of_the_variable
If you simply want some output, you want to use $(info) by itself. You can do that anywhere in a Makefile, and it will show when that line is evaluated:
$(info VAR="$(VAR)")
Will output VAR="<value of VAR>" whenever make processes that line. This behavior is very position dependent, so you must make sure that the $(info) expansion happens AFTER everything that could modify $(VAR) has already happened!
A more generic option is to create a special rule for printing the value of a variable. Generally speaking, rules are executed after variables are assigned, so this will show you the value that is actually being used. (Though, it is possible for a rule to change a variable.) Good formatting will help clarify what a variable is set to, and the $(flavor) function will tell you what kind of a variable something is. So in this rule:
print-% : ; $(info $* is a $(flavor $*) variable set to [$($*)]) #true
$* expands to the stem that the % pattern matched in the rule.
$($*) expands to the value of the variable whose name is given by by $*.
The [ and ] clearly delineate the variable expansion.
You could also use " and " or similar.
$(flavor $*) tells you what kind of variable it is. NOTE: $(flavor)
takes a variable name, and not its expansion.
So if you say make print-LDFLAGS, you get $(flavor LDFLAGS),
which is what you want.
$(info text) provides output.
Make prints text on its stdout as a side-effect of the expansion.
The expansion of $(info) though is empty.
You can think of it like #echo,
but importantly it doesn't use the shell,
so you don't have to worry about shell quoting rules.
#true is there just to provide a command for the rule.
Without that,
make will also output print-blah is up to date. I feel #true makes it more clear that it's meant to be a no-op.
Running it, you get
$ make print-LDFLAGS
LDFLAGS is a recursive variable set to [-L/Users/...]
All versions of make require that command lines be indented with a TAB (not space) as the first character in the line. If you showed us the entire rule instead of just the two lines in question we could give a clearer answer, but it should be something like:
myTarget: myDependencies
#echo hi
where the first character in the second line must be TAB.
#echo $(NDK_PROJECT_PATH) is the good way to do it.
I don't think the error comes from there.
Generally this error appears when you mistyped the intendation : I think you have spaces where you should have a tab.
No need to modify the Makefile.
$ cat printvars.mak
print-%:
#echo '$*=$($*)'
$ cd /to/Makefile/dir
$ make -f ~/printvars.mak -f Makefile print-VARIABLE
Run make -n; it shows you the value of the variable..
Makefile...
all:
#echo $(NDK_PROJECT_PATH)
Command:
export NDK_PROJECT_PATH=/opt/ndk/project
make -n
Output:
echo /opt/ndk/project
This makefile will generate the 'missing separator' error message:
all
#echo NDK_PROJECT_PATH=$(NDK_PROJECT_PATH)
done:
#echo "All done"
There's a tab before the #echo "All done" (though the done: rule and action are largely superfluous), but not before the #echo PATH=$(PATH).
The trouble is that the line starting all should either have a colon : or an equals = to indicate that it is a target line or a macro line, and it has neither, so the separator is missing.
The action that echoes the value of a variable must be associated with a target, possibly a dummy or PHONEY target. And that target line must have a colon on it. If you add a : after all in the example makefile and replace the leading blanks on the next line by a tab, it will work sanely.
You probably have an analogous problem near line 102 in the original makefile. If you showed 5 non-blank, non-comment lines before the echo operations that are failing, it would probably be possible to finish the diagnosis. However, since the question was asked in May 2013, it is unlikely that the broken makefile is still available now (August 2014), so this answer can't be validated formally. It can only be used to illustrate a plausible way in which the problem occurred.
The problem is that echo works only under an execution block. i.e. anything after "xx:"
So anything above the first execution block is just initialization so no execution command can used.
So create a execution blocl
If you don't want to modify the Makefile itself, you can use --eval to add a new target, and then execute the new target, e.g.
make --eval='print-tests:
#echo TESTS $(TESTS)
' print-tests
You can insert the required TAB character in the command line using CTRL-V, TAB
example Makefile from above:
all: do-something
TESTS=
TESTS+='a'
TESTS+='b'
TESTS+='c'
do-something:
#echo "doing something"
#echo "running tests $(TESTS)"
#exit 1
This can be done in a generic way and can be very useful when debugging a complex makefile. Following the same technique as described in another answer, you can insert the following into any makefile:
# if the first command line argument is "print"
ifeq ($(firstword $(MAKECMDGOALS)),print)
# take the rest of the arguments as variable names
VAR_NAMES := $(wordlist 2,$(words $(MAKECMDGOALS)),$(MAKECMDGOALS))
# turn them into do-nothing targets
$(eval $(VAR_NAMES):;#:))
# then print them
.PHONY: print
print:
#$(foreach var,$(VAR_NAMES),\
echo '$(var) = $($(var))';)
endif
Then you can just do "make print" to dump the value of any variable:
$ make print CXXFLAGS
CXXFLAGS = -g -Wall
You could create a vars rule in your make file, like this:
dispvar = echo $(1)=$($(1)) ; echo
.PHONY: vars
vars:
#$(call dispvar,SOMEVAR1)
#$(call dispvar,SOMEVAR2)
There are some more robust ways to dump all variables here: gnu make: list the values of all variables (or "macros") in a particular run.
if you use android make (mka) #echo $(NDK_PROJECT_PATH) will not work and gives you error *** missing separator. Stop."
use this answer if you are trying to print variables in android make
NDK_PROJECT_PATH := some_value
$(warning $(NDK_PROJECT_PATH))
that worked for me
I usually echo with an error if I wanted to see the variable value.(Only if you wanted to see the value. It will stop execution.)
#echo $(error NDK_PROJECT_PATH= $(NDK_PROJECT_PATH))
The following command does it for me on Windows:
Path | tr ; "\n"

Conditional inclusion/execution of Makefile commands in a variable?

There is a Makefile that I am using, which I got from somewhere, and which is quite big. I have also found some things that I'd like changed occasionally in the makefile - and the easiest way to do that for me is to define (or not) a (switch) variable (say, OVWRCHOICE) at the start of the makefile; and then later on in the makefile code, do something like:
ifdef OVWRCHOICE
MYOPT = override
....
endif
... which is all dandy and fine.
The thing is, eventually I also need to change parts in the "override" part as well, so I'd like to have it at the start of the file. So, as this "override" part contains several make commands -- I tried to use define, to have a variable which will contain the commands (which would be executed at the ifdef OVWRCHOICE... part).
So I arrived at this simple example:
# uncomment as needed;
OVWRCHOICE = YES
define SET_OVWRCHOICE
MYOPT = override
endef
export SET_OVWRCHOICE
# ... many lines of code ...
MYOPT = default
# ... many lines of code...
# without indent: Makefile:18: *** missing separator. Stop.
# with tab indent: Makefile:18: *** commands commence before first target. Stop.
ifdef OVWRCHOICE
$(SET_OVWRCHOICE)
endif
all:
#echo $(MYOPT)
... which fails with the errors noted. Of course, if I use the first snippet in the post instead, all runs fine, and make prints out the expected result: "override".
How would I go about in achieving something like this? Not sure if "inclusion" or "execution" of "Makefile commands" are even the right terms in this context; so I have a hard time in finding a starting point for a search :)
Got it - it is described in Eval Function - GNU `make'; the right construct is:
ifdef OVWRCHOICE
$(eval $(call SET_OVWRCHOICE))
endif
Hope this helps someone,
Cheers!
Oh well, didn't really know where to archive this snippet, so back to this old question of mine :) this is off topic for OP; but here goes:
To test how environment variables are processed by a makefile, here is a simple example:
Foo=something
all :
ifdef DEBUG
#echo "Debug defined"
else
#echo "Debug NOT defined"
endif
... and here is the test for it:
$ make
Debug NOT defined
$ make DEBUG
make: *** No rule to make target `DEBUG'. Stop.
$ DEBUG make
DEBUG: command not found
$ DEBUG= make
Debug NOT defined
$ DEBUG=1 make
Debug defined
... so obviously, the right syntax to set that variable inside the makefile from the command line is: "DEBUG=1 make"

Resources