I'm programming a bot to stop my friends from playing league, but I can't figure out a way to check that multiple words are in the message.
if 'league' in message.content.lower():
response = random.choice(Response)
await message.channel.send(response)
What I'm doing here, is copying pasting this and changing the league word to another term. How do I make it just one line of code instead of a whole 100 lines?
if you mean multiple seperate words you could use the built-in any() function. You could also use the "or" keyword.
You can take use of the any() function:
some_words = ['word1', 'word2', 'word3']
if any(word in message.content.lower() for word in some_words):
...
Related
First off I'm a total novice for Javascript, so please go gently. I'm aware of how people feel about having to now pay for IFTTT, but it's perfect for what I need.
I am using a more expansive version of this code below to capture certain keywords from Tweets to then generate emails if the search returns a positive result. This search works very nicely, except it is case sensitive which is a problem.
Yes, I know you can manipulate the twitter search to pick up specific words or phrases. I am very proficient in achieving searches this way. I am casting a wide net to pick up approx 120 search words or phrases which is too long to achieve through "OR" Twitter search parameters alone which is why I'm using this.
Q1 - I have tried adding item.toLowerCase() and just .toLowerCase() in various parts of the code so it wouldn't matter if the sentence case of the search term is different to that of the original tweet text case. I just can't get it to work though. I've seen various posts on here but I can't get any of them to work in IFTTT. I believe IFTTT doesn't accept REGEX either, which is annoying.
Any advice of how to get this code running so it's case-insensitive for text within IFTTT?
Q2 - I have approx 120 search terms for the tweet text to return positive results. There is a lot of junk that comes through with that. Does anyone know how to add a second layer of 'and exclude' search terms?
I have something like 300-400 words and specific phrases which would be used to stop the email from being triggered - so it'd be something like "IF tweet text contains a, b, c BUT text ALSO contains x, y, z... do not send the email"
let str=Twitter.newTweetFromSearch.Text;
let searchTerms=[
"Northbound",
"Westbound",
"Southbound",
"Eastbound"
]
let foundOne=0;
if(searchTerms.some(function(v){return str.indexOf(v)>=0;})){
foundOne=1;
}
if(foundOne==0){
Email.sendMeEmail.skip();
}
I have looked at the Twitter API, but that is a step too far for my coding ability which is why I'm using IFTTT.
Any help is very much appreciated
Thank you.
I'm playing with IFTTT Filter myself at the moment, so here are some thoughts about solving your solution.
If you want to do a case insensitive seatch on the original text, convert the original text to lowercase, then have all your search terms in lowercase.
Plus I think you want to iterate over the searchTerms array, and use the includes() method. Ok, just realised that .some() does the iteration for you, but I prefer includes() over indexof().
let str=Twitter.newTweetFromSearch.Text.toLowerCase();
let searchTerms=[
"northbound",
"westbound",
"southbound",
"eastbound"
]
let foundOne=0;
if(searchTerms.some(function(term){return str.includes(term);})){
foundOne=1;
}
if(foundOne==0){
Email.sendMeEmail.skip();
}
Or you could just skip having the foundOne variable, and do the search in the if() statement.
let str=Twitter.newTweetFromSearch.Text.toLowerCase();
let searchTerms=[
"northbound",
"westbound",
"southbound",
"eastbound"
]
if(!searchTerms.some(function(term){return str.includes(term);})){
Email.sendMeEmail.skip();
}
I have been struggling to return the count of courses from this XML file that contain "Cross-listed" as their description. The problem I encounter is because I am using for, it iterates and gives me "1 1" instead of "2". When I try using let instead I get 13 which means it counts all without condition even when I point return count($c["Cross-listed"]. What am I doing wrong and how can I fix it? Thanks in advance
for $c in doc("courses.xml")//Department/Course
where some $desc in $c/Description
satisfies contains($desc, "Cross-listed")
return count($c)
The problem I encounter is because I am using for
You are quite correct. You don't need to process items individually in order to count them.
You've made things much too difficult. You want
count(doc("courses.xml")//Department/Course[Description[contains(., "Cross-listed"]])
The key thing here is: you want a count, so call the count() function, and give it an argument which selects the set of things you want to include in the count.
I am creating a test that can be expressed as a disjunction of assertions; when the first assertion fails, then it should look at the next. Particularly, an item will be equal to one of two things. Which one, I do not know.
My code looks something like this. It does not work but it might give you an idea of what I am trying to do.
asset_one = Cache.asset_one
asset_two = Cache.asset_two
assert_equal(asset_one.name, Pages.name) or
assert_equal(asset_two.name, Pages.name)
The Pages.name should match one of the targets. I don't know which one. If it doesn't match the first, then I want it to skip it and try to match the second.
Any help is as always much appreciated.
If you want to match any one of the object having the given name, you can use assert_includes
asset_one = Cache.asset_one
asset_two = Cache.asset_two
assert_includes([asset_one, asset_two].map(&:name), Pages.name)
This should solve your purpose.
I want to find out how many of my students are being taught by a specific teacher. However some of the students have multiple teachers. The value of the teacher_name entry is represented as an array. The following query only shows those results where the match is exact, that is, it won't show me results where there are multiple teachers.
r.db('client').table('basic_info').filter({teacher_name: ["Andrew McSwain"]});
How can I iterate through the arrays to match if it contains the string I specified? Is there an API command for this or can I use good-ole javascript methods?
You probably want something like:
r.db('client').table('basic_info').filter(function(row) {
return row('teacher_name').contains('Andrew McSwain');
})
As part of a chat app I'm writing, I need to use regular expressions to match asterisks and underscores in chat messages and turn them into <strong> and <em> tags. Since I'm terrible with regex, I'm really stuck here. Ideally, we would have it set up such that:
One to three words, but not more, can be marked for strong/em.
Patterns such as "un*believ*able" would be matched.
Only one or the other (strong OR em) work within one line.
The above parameters are in order of importance, with only #1 being utterly necessary - the others are just prettiness. The closest I came to anything that worked was:
text = text.sub(/\*([(0-9a-zA-Z).*])\*/,'<b>\1<\/b>')
text = text.sub(/_([(0-9a-zA-Z).*])_/,'<i>\1<\/i>')
But it obviously doesn't work with any of our params.
It's odd that there's not an example of something similar already out there, given the popularity of using asterisks for bold and whatnot. If there is, I couldn't find it outside of plugins/gems (which won't work for this instance, as I really only need it in in one place in my model). Any help would be appreciated.
This should help you finish what you are doing:
sub(/\*(.*)\*/,'<b>\1</b>')
sub(/_(.*)_/,'<i>\1</i>')
Firstly, your criteria are a little strange, but, okay...
It seems that a possible algorithm for this would be to find the number of matches in a message, count them to see if there are less than 4, and then try to perform one set of substitutions.
strong_regexp = /\*([^\*]*)\*/
em_regexp = /_([^_]*)_/
def process(input)
if input ~= strong_regexp && input.match(strong_regexp).size < 4
input.sub strong_regexp, "<b>\1<\b>"
elsif input ~= em_regexp && intput.match(em_regexp).size < 4
input.sub em_regexp, "<i>\1<\i>"
end
end
Your specifications aren't entirely clear, but if you understand this, you can tweak it yourself.