I just looking for a query or function to round off my value as shown here:
Amount - 3162.145
Expected output - 3163
Kindly suggest to get the expected value with a query or any round off function.
Thanks
Abinnaya
Just use the CEIL function
select CEIL(3162.145) from dual; -- result 3163
select CEIL(3162) from dual; -- result 3162
Related
I need to convert string to decimals.
So the string value is: 89,333,22.2345
So i want to keep all decimal places and convert it to: 8933322.2345.
I tried the following query:
select to_number(replace(nvl(89,333,22.2345),0),',','') from dual;
This rounds it to 893322. But i want result with all decimals:
If i try running this query:
select to_number((replace(nvl(89,333,22.2345),0),',',''),'9999.99') from dual;
it throws error.
Try this:
select to_number('89,333,22.2345','99,999,99.9999') from dual;
I think you're passing the number as a parameter. Otherwise why would you use nvl. Then I see the query you need is going to be similar like that
select to_number(replace(nvl('89,333,22.2345','0'),',','')) from dual;
Things were wrong at your code:
since number is a varchar, it has to be placed between apostrophes
nvl takes parameters divided by a comma. And there was one closing bracket too much
nvl(89,333,22.2345),0) -> nvl('89,333,22.2345',0)
In the below code, I am trying to get the amount in words for the value in the AMOUNT column but can't seem to get it right. Anyone with an idea? Below the CREATE VIEW statement:
SELECT GLR3 AS RECEIPT_DOC_NO,
GLANI AS ACCOUNT_NUMBER,
GLSBL AS JDE_NO,
(SELECT YAALPH FROM PRODDTA.F060116 WHERE YAAN8 = T1.GLSBL) AS STAFF_NAME,
CASE GLDGJ WHEN 0 THEN TO_DATE (TO_CHAR (1 + 1900000), 'YYYYDDD')
ELSE TO_DATE (TO_CHAR (GLDGJ + 1900000), 'YYYYDDD') END AS GL_DATE,
GLEXA AS NARRATIVE,
GLLT AS LEDGER_TYPE,
GLSBLT AS SUBLEDGER_TYPE,
GLCRCD AS CURRENCY_CODE,
CASE GLAA WHEN 100 THEN ROUND (GLAA / 100, 2) ELSE ROUND (GLAA / 100, 2)
END AS AMOUNT,
(SELECT TO_CHAR(TO_DATE(T1.GLAA,'J'),'JSP')) FROM DUAL) AS AMOUNT_INWORDS
FROM PRODDTA.F0911 T1;
My code is failing with
ORA-00923: FROM keyword not found where expected.
ORA-00923: FROM keyword not found where expected.
Indicates a syntax error. In this case you have three ( and four ):
(SELECT TO_CHAR(TO_DATE(T1.GLAA,'J'),'JSP')) FROM DUAL) AS AMOUNT_INWORDS
The compiler is not expecting the second ) after 'JSP'.
The scalar cursor is unnecessary, so the simplified and corrected version would be:
TO_CHAR(TO_DATE(T1.GLAA,'J'),'JSP') AS AMOUNT_INWORDS
ORA-01854: julian date must be between 1 and 5373484
5373484 is the Julian date for 31-DEC-9999 which is the maximum date allowed in Oracle. This poses an absolute limit on the number which we can spell using JSP mask ... in one go. However, we can use PL/SQL to break larger numbers into chunks and spell those instead. The inestimable Tom Kyte wrote such a function and published it on the AskTom site. Find it here.
I think the value i'm trying to write in words has decimal values (400.00) hence the ORA-01854 error.
The Tom Kyte I linked to does address that issue further down the page. It's this comment here.
Data retrieved in amount column is preceded by a negative symbol when it shouldn't be,
If you simply want to ignore negative values then apply the ABS() function to give you the absolute value.
I am trying to understand a query in my application where it uses substr function.
I have gone through the documentation for substr, which looks simple and clear.
Now below is my query without using substr:
select last_day(to_date(to_char(add_months(TO_DATE('2004/10/25', 'yyyy/mm/dd'),1),'YYYY')||'0201','YYYYMMDD')) from dual;
This gives me result as 2/29/2004. The above query just returns last day of Feb in simple words.
Now I am using substr as below:
select substr(last_day(to_date(to_char(add_months(TO_DATE('2004/10/25', 'yyyy/mm/dd'),1),'YYYY')||'0201','YYYYMMDD')),5,1) from dual;
So here the start value is 5 & length is 1, so I am expecting output as 2 looking at 2/29/2004. but the actual output is E, I am not clear from where this E is coming as result.
You cannot use SUBSTR() on DATE values. SUBSTR() works only on strings!
When you run SUBSTR({DATE_VALUE}, ...) then Oracle actually does following:
SELECT
SUBSTR(
TO_CHAR(
{DATE_VALUE}, (SELECT VALUE FROM nls_session_parameters WHERE parameter = 'NLS_DATE_FORMAT')
), ...
)
FROM dual;
What is the purpose of this query? Do you like to find out whether input year is a leap-year?
Try this instead -
select substr(to_char(last_day(to_date(to_char(add_months(TO_DATE('2004/10/25', 'yyyy/mm/dd'),1),'YYYY')||'0201','YYYYMMDD')),'dd/mm/yyyy'),5,1)
from dual;
I need to count the number of rows returned by REGEXP_LIKE() in oracle. how do I do that?
I have tried the following query in a function:
RETURN COUNT(REGEXP_LIKE(SIN, '^(-|\\+){0,1}([0-9]+\\.[0-9]*|[0-9]*\\.[0-9]+|[0-9]+)$'));
Use regexp_count(https://docs.oracle.com/cd/B28359_01/server.111/b28286/functions135.htm) instead of REGEXP_LIKE
SELECT COUNT(*) INTO sin_count FROM your_tbl WHERE REGEXP_LIKE(
SIN, '^(-|\+){0,1}([0-9]+\.[0-9]|[0-9]\.[0-9]+|[0-9]+)$');
I have a requirement where i always need to display the number with the decimal point.
The datatype of the db column is that of number.
If the value is 1.25 it gets displayed as 1.25
But if the value is 1 it does gets displayed as 1 and I need to display the value as 1.00.
I need to perform rpad (right padding) operations once I get the result in the decimal format.
Without the decimal, the value of a whole number would be different from what is present in the database.
Example:
SELECT RPAD(ROUND(12,2), 5 ,0) AS test
FROM DUAL;
results in 12000 whereas I am expecting it to be 12.00.
Any pointers on this would help.
Thanks!
Use an appropriate to_char call. Something like
SELECT to_char( <<your number>>, '0.00' )
FROM dual;
That will return the string "1.00" when you pass in a value of 1. If you pass in a value of 0, it will return the string "0.00". If you pass in a a value of 1.25, it will return the string "1.25".
Try using a number format along with the TO_CHAR function, as:
SELECT TO_CHAR(12, 99.99) AS test
FROM DUAL;
Reference:
You can find documentatation related to other ways to format numbers here.
Try this:
select TRIM(to_char(100.5, '99999999.00')) FROM DUAL
The format specifications are here:
http://docs.oracle.com/cd/B19306_01/server.102/b14200/sql_elements004.htm#i34570