Separate Cents and dollars values Oracle - oracle

Question

I'm new with oracle queries and I would like to have some help as I'm totally stuck.
I have a Products table which contains the product id, price and product name:
And I would like to separate the price for the products into dollars and cents using select oracle query.
I don't know how to figure that but I tried the TRUNC function but I'm still can't get the cents values.
Can you help me please.
Here is the DB Table:
CREATE TABLE Products (
ProductID int,
Price varchar(255),
ProductName varchar(255)
);
INSERT INTO Products VALUES (1,5.17,'Apple');
INSERT INTO Products VALUES (2,6.527,'Orange');
INSERT INTO Products VALUES (3,7.12,'Watermelon');
INSERT INTO Products VALUES (4,3.25,'Pear');
INSERT INTO Products VALUES (5,4.123,'Grape');
Thanks for any help :)

Answer 1

Use TRUNC to get the dollar value and MOD (modulo) to get the cents value:
SELECT ProductID,
ProductName,
TRUNC( Price ) AS dollars,
MOD( Price, 1 ) * 100 AS cents
FROM Products
Which, for your sample data, outputs:
PRODUCTID | PRODUCTNAME | DOLLARS | CENTS
--------: | :---------- | ------: | ----:
1 | Apple | 5 | 17
2 | Orange | 6 | 52.7
3 | Watermelon | 7 | 12
4 | Pear | 3 | 25
5 | Grape | 4 | 12.3
db<>fiddle here

Answer 2

here is what you need.
select substr(price, 1, instr(price, '.')-1) dollars, substr(price, instr(price, '.')+1) cents, round(substr(price, instr(price, '.')),2)* 100 cents_rounded
from products

Answer 3

PRICE as VARHCAR2? Why? It should be a NUMBER as it is a numeric value. In that case:
SQL> desc products
Name Null? Type
----------------------------------------- -------- ----------------------------
PRODUCTID NUMBER(38)
PRICE NUMBER
PRODUCTNAME VARCHAR2(255)
SQL> SELECT productid,
2 productname,
3 price,
4 --
5 TRUNC (price) dollars,
6 (price - TRUNC (price)) * 100 cents
7 FROM products;
PRODUCTID PRODUCTNAM PRICE DOLLARS CENTS
---------- ---------- ---------- ---------- ----------
1 Apple 5,17 5 17
2 Orange 6,527 6 52,7
3 Watermelon 7,12 7 12
4 Pear 3,25 3 25
5 Grape 4,123 4 12,3
SQL>

Answer 4

Query:
Select productid,trunc(price) As Dollars, nvl(substr(price - trunc(price),2),0) as Cents, ProductName As Product From Products;
Output:
PRODUCTID
DOLLARS
CENTS
Product
1
5
17
Apple
2
6
527
Orange
3
7
12
Watermelon
4
3
25
Pear
5
4
123
Grape
Description:
Here I select the ProductId and then I use trunc function to remove any decimals (to have only the DOLLARS value) and after that I use nvl function to make like a replacement to null values (In case there are no cents in number) it will be replaced by 0 and the line: substr(price - trunc(price),2) that will subtract the full price from the DOLLARS value to get the cents.
Note:
You can solve this problem by different ways and other functions check this article for more informations: Link

Answer 5

create or replace FUNCTION METE(p_number VARCHAR, p_parent VARCHAR, p_child VARCHAR) RETURN VARCHAR
IS
v___left VARCHAR2(4000);
v___right VARCHAR2(4000);
v___number VARCHAR2(4000);
BEGIN
SELECT p_number INTO v___number FROM DUAL WHERE p_number LIKE '%.%';
IF v___number IS NOT NULL THEN
select rtrim((select rtrim(p_number,(select substr(p_number,(select instr(p_number,'.')from dual)+1) from dual)) from dual),'.')
into v___left
from dual;
select substr(p_number,(select instr(p_number,'.')from dual)+1)
INTO v___right
from dual;
RETURN NVL(v___left,'0')||' '||p_parent||' '||NVL(v___right,'0')||' '||p_child;
ELSIF v___number IS NULL THEN
select substr(p_number,(select instr(p_number,'.')from dual)+1)
INTO v___right
from dual;
RETURN NVL(v___right,'0')||' '||p_parent;
END IF;
EXCEPTION
WHEN NO_DATA_FOUND THEN
select substr(p_number,(select instr(p_number,'.')from dual)+1)
INTO v___right
from dual;
RETURN NVL(v___right,'0')||' '||p_parent;
END;
select ProductID, mete(price,'Dollar','Cent') price, productname from Products;